我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
当前回答
使用当前版本的TypeScript,你可以使用这些函数将Enum映射到你选择的记录。注意,不能用这些函数定义字符串值,因为它们查找值为数字的键。
enum STATES {
LOGIN,
LOGOUT,
}
export const enumToRecordWithKeys = <E extends any>(enumeration: E): E => (
Object.keys(enumeration)
.filter(key => typeof enumeration[key] === 'number')
.reduce((record, key) => ({...record, [key]: key }), {}) as E
);
export const enumToRecordWithValues = <E extends any>(enumeration: E): E => (
Object.keys(enumeration)
.filter(key => typeof enumeration[key] === 'number')
.reduce((record, key) => ({...record, [key]: enumeration[key] }), {}) as E
);
const states = enumToRecordWithKeys(STATES)
const statesWithIndex = enumToRecordWithValues(STATES)
console.log(JSON.stringify({
STATES,
states,
statesWithIndex,
}, null ,2));
// Console output:
{
"STATES": {
"0": "LOGIN",
"1": "LOGOUT",
"LOGIN": 0,
"LOGOUT": 1
},
"states": {
"LOGIN": "LOGIN",
"LOGOUT": "LOGOUT"
},
"statesWithIndex": {
"LOGIN": 0,
"LOGOUT": 1
}
}
其他回答
如果你有enum
enum Diet {
KETO = "Ketogenic",
ATKINS = "Atkins",
PALEO = "Paleo",
DGAF = "Whatever"
}
然后你可以得到如下的键和值:
Object.keys(Diet).forEach((d: Diet) => {
console.log(d); // KETO
console.log(Diet[d]) // Ketogenic
});
在当前的TypeScript版本1.8.9中,我使用类型化enum:
export enum Option {
OPTION1 = <any>'this is option 1',
OPTION2 = <any>'this is option 2'
}
与结果在这个Javascript对象:
Option = {
"OPTION1": "this is option 1",
"OPTION2": "this is option 2",
"this is option 1": "OPTION1",
"this is option 2": "OPTION2"
}
所以我必须通过键和值查询,只返回值:
let optionNames: Array<any> = [];
for (let enumValue in Option) {
let optionNameLength = optionNames.length;
if (optionNameLength === 0) {
this.optionNames.push([enumValue, Option[enumValue]]);
} else {
if (this.optionNames[optionNameLength - 1][1] !== enumValue) {
this.optionNames.push([enumValue, Option[enumValue]]);
}
}
}
我在数组中收到选项键:
optionNames = [ "OPTION1", "OPTION2" ];
这里发现的另一个有趣的解决方案是使用ES6 Map:
export enum Type {
low,
mid,
high
}
export const TypeLabel = new Map<number, string>([
[Type.low, 'Low Season'],
[Type.mid, 'Mid Season'],
[Type.high, 'High Season']
]);
USE
console.log(TypeLabel.get(Type.low)); // Low Season
TypeLabel.forEach((label, value) => {
console.log(label, value);
});
// Low Season 0
// Mid Season 1
// High Season 2
虽然答案已经提供了,但几乎没有人指向文档
下面是一个片段
enum Enum {
A
}
let nameOfA = Enum[Enum.A]; // "A"
请记住,string enum成员根本不会生成反向映射。
我的Enum是这样的:
export enum UserSorting {
SortByFullName = "Sort by FullName",
SortByLastname = "Sort by Lastame",
SortByEmail = "Sort by Email",
SortByRoleName = "Sort by Role",
SortByCreatedAt = "Sort by Creation date",
SortByCreatedBy = "Sort by Author",
SortByUpdatedAt = "Sort by Edit date",
SortByUpdatedBy = "Sort by Editor",
}
这样做会返回undefined:
UserSorting[UserSorting.SortByUpdatedAt]
为了解决这个问题,我选择了另一种使用管道的方法:
import { Pipe, PipeTransform } from '@angular/core';
@Pipe({
name: 'enumKey'
})
export class EnumKeyPipe implements PipeTransform {
transform(value, args: string[] = null): any {
let enumValue = args[0];
var keys = Object.keys(value);
var values = Object.values(value);
for (var i = 0; i < keys.length; i++) {
if (values[i] == enumValue) {
return keys[i];
}
}
return null;
}
}
要使用它:
return this.enumKeyPipe.transform(UserSorting, [UserSorting.SortByUpdatedAt]);