我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
当前回答
这对于基于键值的enum更有效:
enum yourEnum {
["First Key"] = "firstWordValue",
["Second Key"] = "secondWordValue"
}
Object.keys(yourEnum)[Object.values(yourEnum).findIndex(x => x === yourValue)]
// Result for passing values as yourValue
// FirstKey
// SecondKey
其他回答
如果你只搜索名称,然后迭代使用:
Object.keys(myEnum).map(key => myEnum[key]).filter(value => typeof value === 'string') as string[];
Typescript游乐场示例
enum TransactionStatus {
SUBMITTED = 'submitted',
APPROVED = 'approved',
PAID = 'paid',
CANCELLED = 'cancelled',
DECLINED = 'declined',
PROCESSING = 'processing',
}
let set1 = Object.entries(TransactionStatus).filter(([,value]) => value === TransactionStatus.SUBMITTED || value === TransactionStatus.CANCELLED).map(([key,]) => {
return key
})
let set2 = Object.entries(TransactionStatus).filter(([,value]) => value === TransactionStatus.PAID || value === TransactionStatus.APPROVED).map(([key,]) => {
return key
})
let allKeys = Object.keys(TransactionStatus)
console.log({set1,set2,allKeys})
我的Enum是这样的:
export enum UserSorting {
SortByFullName = "Sort by FullName",
SortByLastname = "Sort by Lastame",
SortByEmail = "Sort by Email",
SortByRoleName = "Sort by Role",
SortByCreatedAt = "Sort by Creation date",
SortByCreatedBy = "Sort by Author",
SortByUpdatedAt = "Sort by Edit date",
SortByUpdatedBy = "Sort by Editor",
}
这样做会返回undefined:
UserSorting[UserSorting.SortByUpdatedAt]
为了解决这个问题,我选择了另一种使用管道的方法:
import { Pipe, PipeTransform } from '@angular/core';
@Pipe({
name: 'enumKey'
})
export class EnumKeyPipe implements PipeTransform {
transform(value, args: string[] = null): any {
let enumValue = args[0];
var keys = Object.keys(value);
var values = Object.values(value);
for (var i = 0; i < keys.length; i++) {
if (values[i] == enumValue) {
return keys[i];
}
}
return null;
}
}
要使用它:
return this.enumKeyPipe.transform(UserSorting, [UserSorting.SortByUpdatedAt]);
这里发现的另一个有趣的解决方案是使用ES6 Map:
export enum Type {
low,
mid,
high
}
export const TypeLabel = new Map<number, string>([
[Type.low, 'Low Season'],
[Type.mid, 'Mid Season'],
[Type.high, 'High Season']
]);
USE
console.log(TypeLabel.get(Type.low)); // Low Season
TypeLabel.forEach((label, value) => {
console.log(label, value);
});
// Low Season 0
// Mid Season 1
// High Season 2
在当前的TypeScript版本1.8.9中,我使用类型化enum:
export enum Option {
OPTION1 = <any>'this is option 1',
OPTION2 = <any>'this is option 2'
}
与结果在这个Javascript对象:
Option = {
"OPTION1": "this is option 1",
"OPTION2": "this is option 2",
"this is option 1": "OPTION1",
"this is option 2": "OPTION2"
}
所以我必须通过键和值查询,只返回值:
let optionNames: Array<any> = [];
for (let enumValue in Option) {
let optionNameLength = optionNames.length;
if (optionNameLength === 0) {
this.optionNames.push([enumValue, Option[enumValue]]);
} else {
if (this.optionNames[optionNameLength - 1][1] !== enumValue) {
this.optionNames.push([enumValue, Option[enumValue]]);
}
}
}
我在数组中收到选项键:
optionNames = [ "OPTION1", "OPTION2" ];