为什么Python中没有++和——运算符?
当前回答
我相信这源于Python的信条“显式优于隐式”。
其他回答
我相信这源于Python的信条“显式优于隐式”。
其他答案描述了为什么迭代器不需要它,但有时它在赋值以inline增加变量时很有用,你可以使用元组和多次赋值达到相同的效果:
B = ++a变成:
a,b = (a+1,)*2
b = a++变成:
a,b = a+1, a
Python 3.8引入了赋值:=操作符,允许我们用
foo(a:=a+1)
Foo (a++)仍然是难以捉摸的。
这并不是因为它没有意义;将“x++”定义为“x+ = 1,求值到x的前一个绑定”非常有意义。
如果你想知道最初的原因,你必须在旧的Python邮件列表中寻找,或者询问当时在那里的人(例如。Guido),但事后很容易就能证明:
简单的递增和递减不需要像其他语言那样多。你不会写这样的for(int i = 0;I < 10;i)在Python中经常使用;相反,你可以把I放在(0,10)范围内。
由于不经常需要它,所以没有理由给它自己的特殊语法;当您确实需要增加时,+=通常就可以了。
It's not a decision of whether it makes sense, or whether it can be done--it does, and it can. It's a question of whether the benefit is worth adding to the core syntax of the language. Remember, this is four operators--postinc, postdec, preinc, predec, and each of these would need to have its own class overloads; they all need to be specified, and tested; it would add opcodes to the language (implying a larger, and therefore slower, VM engine); every class that supports a logical increment would need to implement them (on top of += and -=).
这些都是+=和-=的冗余,所以会变成净损失。
Maybe a better question would be to ask why do these operators exist in C. K&R calls increment and decrement operators 'unusual' (Section 2.8page 46). The Introduction calls them 'more concise and often more efficient'. I suspect that the fact that these operations always come up in pointer manipulation also has played a part in their introduction. In Python it has been probably decided that it made no sense to try to optimise increments (in fact I just did a test in C, and it seems that the gcc-generated assembly uses addl instead of incl in both cases) and there is no pointer arithmetic; so it would have been just One More Way to Do It and we know Python loathes that.
因为,在Python中,整数是不可变的(int's +=实际上返回一个不同的对象)。
同样,使用++/——,您需要考虑前后的递增/递减,并且只需要多击一次键就可以写出x+=1。换句话说,它以很少的收益为代价避免了潜在的混乱。
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