是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

既然你想优化时间从一个页面移动到另一个UIWebView,这是不是意味着你真的在寻找优化Javascript加载这些页面?

为此,我想看看WebKit分析器,就像这里所说的:

http://www.alertdebugging.com/2009/04/29/building-a-better-javascript-profiler-with-webkit/

另一种方法是从高层次开始,思考如何设计有问题的网页,使用AJAX样式的页面加载来最小化加载时间,而不是每次都刷新整个web视图。

其他回答

NSDate *methodStart = [NSDate date];

/* ... Do whatever you need to do ... */

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

迅速:

let methodStart = NSDate()

/* ... Do whatever you need to do ... */

let methodFinish = NSDate()
let executionTime = methodFinish.timeIntervalSinceDate(methodStart)
print("Execution time: \(executionTime)")

Swift3:

let methodStart = Date()

/* ... Do whatever you need to do ... */

let methodFinish = Date()
let executionTime = methodFinish.timeIntervalSince(methodStart)
print("Execution time: \(executionTime)")

易于使用,具有亚毫秒精度。

你可以得到很好的时间(秒。部分秒)使用这个StopWatch类。它使用了iPhone的高精度计时器。使用NSDate只能获得秒级精度。这个版本是专门为自动发布和objective-c设计的。如果需要的话,我也有一个c++版本。你可以在这里找到c++版本。

StopWatch.h

#import <Foundation/Foundation.h>


@interface StopWatch : NSObject 
{
    uint64_t _start;
    uint64_t _stop;
    uint64_t _elapsed;
}

-(void) Start;
-(void) Stop;
-(void) StopWithContext:(NSString*) context;
-(double) seconds;
-(NSString*) description;
+(StopWatch*) stopWatch;
-(StopWatch*) init;
@end

StopWatch.m

#import "StopWatch.h"
#include <mach/mach_time.h>

@implementation StopWatch

-(void) Start
{
    _stop = 0;
    _elapsed = 0;
    _start = mach_absolute_time();
}
-(void) Stop
{
    _stop = mach_absolute_time();   
    if(_stop > _start)
    {
        _elapsed = _stop - _start;
    }
    else 
    {
        _elapsed = 0;
    }
    _start = mach_absolute_time();
}

-(void) StopWithContext:(NSString*) context
{
    _stop = mach_absolute_time();   
    if(_stop > _start)
    {
        _elapsed = _stop - _start;
    }
    else 
    {
        _elapsed = 0;
    }
    NSLog([NSString stringWithFormat:@"[%@] Stopped at %f",context,[self seconds]]);

    _start = mach_absolute_time();
}


-(double) seconds
{
    if(_elapsed > 0)
    {
        uint64_t elapsedTimeNano = 0;

        mach_timebase_info_data_t timeBaseInfo;
        mach_timebase_info(&timeBaseInfo);
        elapsedTimeNano = _elapsed * timeBaseInfo.numer / timeBaseInfo.denom;
        double elapsedSeconds = elapsedTimeNano * 1.0E-9;
        return elapsedSeconds;
    }
    return 0.0;
}
-(NSString*) description
{
    return [NSString stringWithFormat:@"%f secs.",[self seconds]];
}
+(StopWatch*) stopWatch
{
    StopWatch* obj = [[[StopWatch alloc] init] autorelease];
    return obj;
}
-(StopWatch*) init
{
    [super   init];
    return self;
}

@end

该类有一个返回自动释放对象的静态stopWatch方法。

调用start后,使用seconds方法获取运行时间。再次调用start来重新启动它。或者停下来停下来。在调用stop后,您仍然可以随时读取时间(调用秒数)。

函数中的示例(执行的定时调用)

-(void)SomeFunc
{
   StopWatch* stopWatch = [StopWatch stopWatch];
   [stopWatch Start];

   ... do stuff

   [stopWatch StopWithContext:[NSString stringWithFormat:@"Created %d Records",[records count]]];
}

这里有一个Swift 3的解决方案,可以在任何地方对代码进行等分,以找到长时间运行的进程。

var increment: Int = 0

var incrementTime = NSDate()

struct Instrumentation {
    var title: String
    var point: Int
    var elapsedTime: Double

    init(_ title: String, _ point: Int, _ elapsedTime: Double) {
        self.title = title
        self.point = point
        self.elapsedTime = elapsedTime
    }
}

var elapsedTimes = [Instrumentation]()

func instrument(_ title: String) {
    increment += 1
    let incrementedTime = -incrementTime.timeIntervalSinceNow
    let newPoint = Instrumentation(title, increment, incrementedTime)
    elapsedTimes.append(newPoint)
    incrementTime = NSDate()
}

用法:-

instrument("View Did Appear")

print("ELAPSED TIMES \(elapsedTimes)")

样例输出:

[MyApp.SomeViewController.]仪器仪表(标题:“开始视图 Did Load", point: 1, elapsedTime: 0.040504038333892822), MyApp.SomeViewController。检测(标题:“完成添加 SubViews", point: 2, elapsedTime: 0.010585010051727295), MyApp.SomeViewController。仪器仪表(标题:“视图已出现”, 点:3,elapsedTime: 0.56564098596572876)]

对于OS X上的细粒度计时,您应该使用在<mach/mach_time.h>中声明的mach_absolute_time():

#include <mach/mach_time.h>
#include <stdint.h>

// Do some stuff to setup for timing
const uint64_t startTime = mach_absolute_time();
// Do some stuff that you want to time
const uint64_t endTime = mach_absolute_time();

// Time elapsed in Mach time units.
const uint64_t elapsedMTU = endTime - startTime;

// Get information for converting from MTU to nanoseconds
mach_timebase_info_data_t info;
if (mach_timebase_info(&info))
   handleErrorConditionIfYoureBeingCareful();

// Get elapsed time in nanoseconds:
const double elapsedNS = (double)elapsedMTU * (double)info.numer / (double)info.denom;

当然,关于细粒度度量的通常警告也适用;您可能最好多次调用测试中的例程,并求平均值/取最小值/一些其他形式的处理。

此外,请注意,您可能会发现使用Shark等工具对应用程序运行进行概要分析更有用。这不会为您提供确切的时间信息,但它会告诉您应用程序的时间在哪里花费了多少百分比,这通常更有用(但并不总是如此)。

我使用这个代码:

#import <mach/mach_time.h>

float TIME_BLOCK(NSString *key, void (^block)(void)) {
    mach_timebase_info_data_t info;
    if (mach_timebase_info(&info) != KERN_SUCCESS)
    {
        return -1.0;
    }

    uint64_t start = mach_absolute_time();
    block();
    uint64_t end = mach_absolute_time();
    uint64_t elapsed = end - start;

    uint64_t nanos = elapsed * info.numer / info.denom;
    float cost = (float)nanos / NSEC_PER_SEC;

    NSLog(@"key: %@ (%f ms)\n", key, cost * 1000);
    return cost;
}