我使用了以下ggplot命令:

ggplot(survey, aes(x = age)) + stat_bin(aes(n = nrow(h3), y = ..count.. / n), binwidth = 10)
  + scale_y_continuous(formatter = "percent", breaks = c(0, 0.1, 0.2))
  + facet_grid(hospital ~ .)
  + theme(panel.background = theme_blank())

生产

然而,我想将facet标签更改为更短的内容(如Hosp 1, Hosp 2…),因为它们现在太长了,看起来很局促(增加图形的高度不是一个选项,它将占用文档中的太多空间)。我查看了facet_grid帮助页面,但不知道如何操作。


当前回答

我觉得我应该加上我的答案,因为我花了很长时间才做到这一点:

这个答案是为你准备的:

您不想编辑原始数据 如果你需要表达式(bquote)在标签和 如果您想要单独的标签名称-向量的灵活性

我基本上把标签放在一个命名向量中,这样标签就不会混淆或切换。标签器表达式可能更简单,但这至少是可行的(非常欢迎改进)。注意'(后引号)以保护facet-factor。

n <- 10
x <- seq(0, 300, length.out = n)

# I have my data in a "long" format
my_data <- data.frame(
  Type = as.factor(c(rep('dl/l', n), rep('alpha', n))),
  T = c(x, x),
  Value = c(x*0.1, sqrt(x))
)

# the label names as a named vector
type_names <- c(
  `nonsense` = "this is just here because it looks good",
  `dl/l` = Linear~Expansion~~Delta*L/L[Ref]~"="~"[%]", # bquote expression
  `alpha` = Linear~Expansion~Coefficient~~alpha~"="~"[1/K]"
  )


ggplot() + 
  geom_point(data = my_data, mapping = aes(T, Value)) + 
  facet_wrap(. ~ Type, scales="free_y", 
             labeller = label_bquote(.(as.expression(
               eval(parse(text = paste0('type_names', '$`', Type, '`')))
               )))) +
  labs(x="Temperature [K]", y="", colour = "") +
  theme(legend.position = 'none')

其他回答

如果你有两个面医院和房间,但只想重命名其中一个,你可以使用:

facet_grid( hospital ~ room, labeller = labeller(hospital = as_labeller(hospital_names)))

使用基于矢量的方法重命名两个面(如naught101的答案),你可以这样做:

facet_grid( hospital ~ room, labeller = labeller(hospital = as_labeller(hospital_names),
                                                 room = as_labeller(room_names)))

更改底层因子级别的名称,如下所示:

# Using the Iris data
> i <- iris
> levels(i$Species)
[1] "setosa"     "versicolor" "virginica" 
> levels(i$Species) <- c("S", "Ve", "Vi")
> ggplot(i, aes(Petal.Length)) + stat_bin() + facet_grid(Species ~ .)

你试过改变医院载体的具体水平吗?

levels(survey$hospital)[levels(survey$hospital) == "Hospital #1"] <- "Hosp 1"
levels(survey$hospital)[levels(survey$hospital) == "Hospital #2"] <- "Hosp 2"
levels(survey$hospital)[levels(survey$hospital) == "Hospital #3"] <- "Hosp 3"

我现在解决这个问题的方法是使用dplyr::case_when在facet_grid或facet_wrap函数中生成一个标签器。这是@lillemets提出的解决方案的扩展

ggplot(survey, aes(x = age)) + stat_bin(aes(n = nrow(h3), y = ..count.. / n), binwidth = 10)
  + scale_y_continuous(formatter = "percent", breaks = c(0, 0.1, 0.2))
  + facet_grid(case_when(hospital == "Hospital #1" ~ "Hosp1",
                         hospital == "Hospital #2" ~ "Hosp2") ~ .)
  + theme(panel.background = theme_blank())

如果您有第二个facet标签要更改,那么只需在facet_grid中的~的另一侧使用相同的方法即可

添加另一个类似于@domi的解决方案,解析数学符号、上标、下标、圆括号/方括号等。

library(tidyverse)
theme_set(theme_bw(base_size = 18))

### create separate name vectors
# run `demo(plotmath)` for more examples of mathematical annotation in R
am_names <- c(
  `0` = "delta^{15}*N-NO[3]^-{}",
  `1` = "sqrt(x,y)"
)

# use `scriptstyle` to reduce the size of the parentheses &
# `bgroup` to make adding `)` possible 
cyl_names <- c(
  `4` = 'scriptstyle(bgroup("", a, ")"))~T~-~5*"%"',
  `6` = 'scriptstyle(bgroup("", b, ")"))~T~+~10~degree*C',
  `8` = 'scriptstyle(bgroup("", c, ")"))~T~+~30*"%"'
)

ggplot(mtcars, aes(wt, mpg)) + 
  geom_jitter() +
  facet_grid(am ~ cyl,
             labeller = labeller(am  = as_labeller(am_names,  label_parsed),
                                 cyl = as_labeller(cyl_names, label_parsed))
             ) +
  geom_text(x = 4, y = 25, size = 4, nudge_y = 1,
            parse = TRUE, check_overlap = TRUE,
            label = as.character(expression(paste("Log"["10"], bgroup("(", frac("x", "y"), ")")))))

### OR create new variables then assign labels directly
# reverse facet orders just for fun
mtcars <- mtcars %>% 
  mutate(am2  = factor(am,  labels = am_names),
         cyl2 = factor(cyl, labels = rev(cyl_names), levels = rev(attr(cyl_names, "names")))
  )

ggplot(mtcars, aes(wt, mpg)) + 
  geom_jitter() +
  facet_grid(am2 ~ cyl2,
             labeller = label_parsed) +
  annotate("text", x = 4, y = 30, size = 5,
           parse = TRUE, 
           label = as.character(expression(paste("speed [", m * s^{-1}, "]"))))

由reprex包于2019-03-30创建(v0.2.1.9000)