我试着:

somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)

我预期的

["some", "thing", "another", "thing"]

但有

["some", "thing", nil]

当前回答

你有一个可行的想法,但#flatten!在错误的地方——它会使接收器变平,所以你可以用它把[1,2,['foo', 'bar']]变成[1,2,'foo','bar']。

毫无疑问,我忘记了一些方法,但你可以串联起来:

a1.concat a2
a1 + a2              # creates a new array, as does a1 += a2

或预先考虑/追加:

a1.push(*a2)         # note the asterisk
a2.unshift(*a1)      # note the asterisk, and that a2 is the receiver

或接头:

a1[a1.length, 0] = a2
a1[a1.length..0] = a2
a1.insert(a1.length, *a2)

或append和flatten:

(a1 << a2).flatten!  # a call to #flatten instead would return a new array

其他回答

如果新数据可以是数组或标量,并且如果它是数组,则希望防止新数据嵌套,splat操作符非常棒!它为标量返回一个标量,为数组返回一个已解压的参数列表。

1.9.3-p551 :020 > a = [1, 2]
 => [1, 2] 
1.9.3-p551 :021 > b = [3, 4]
 => [3, 4] 
1.9.3-p551 :022 > c = 5
 => 5 
1.9.3-p551 :023 > a.object_id
 => 6617020 
1.9.3-p551 :024 > a.push *b
 => [1, 2, 3, 4] 
1.9.3-p551 :025 > a.object_id
 => 6617020 
1.9.3-p551 :026 > a.push *c
 => [1, 2, 3, 4, 5] 
1.9.3-p551 :027 > a.object_id
 => 6617020 

最简洁的方法是使用array# concat方法;它不会创建一个新数组(不像array# +会做同样的事情,但创建一个新数组)。

直接从文档(http://www.ruby-doc.org/core-1.9.3/Array.html#method-i-concat):

concat (other_ary) 将other_ary的元素追加到self。

So

[1,2].concat([3,4])  #=> [1,2,3,4]  

如果作为参数传入多维数组,array# concat将不会平展多维数组。你需要单独处理:

arr= [3,[4,5]]
arr= arr.flatten   #=> [3,4,5]
[1,2].concat(arr)  #=> [1,2,3,4,5]

最后,您可以使用我们的corelib gem (https://github.com/corlewsolutions/corelib),它为Ruby核心类添加了有用的帮助程序。特别地,我们有一个array# add_all方法,它将在执行concat之前自动将多维数组平展。

我发现更容易推入或追加数组,然后将它们压平,如下所示:

somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push anotherarray # => ["some", "thing", ["another", "thing"]]
#or
somearray << anotherarray # => ["some", "thing", ["another", "thing"]]
somearray.flatten!  # => ["some", "thing", "another", "thing"]
somearray # => ["some", "thing", "another", "thing"]
a = ['a', 'b']
b = ['c', 'd']
arr = [a, b].flatten

这不会去除dups,但是

a|b

删除重复。

我很惊讶没有人提到reduce,当你有一个数组的数组时,它工作得很好:

lists = [["a", "b"], ["c", "d"]]
flatlist = lists.reduce(:+)  # ["a", "b", "c", "d"]