我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
当前回答
适用于Ruby版本>= 2.0但不适用于旧版本的简单方法:
irb(main):001:0> a=[1,2]
=> [1, 2]
irb(main):003:0> b=[3,4]
=> [3, 4]
irb(main):002:0> c=[5,6]
=> [5, 6]
irb(main):004:0> [*a,*b,*c]
=> [1, 2, 3, 4, 5, 6]
其他回答
a = ['a', 'b']
b = ['c', 'd']
arr = [a, b].flatten
这不会去除dups，但是
a|b
删除重复。
适用于Ruby版本>= 2.0但不适用于旧版本的简单方法:
irb(main):001:0> a=[1,2]
=> [1, 2]
irb(main):003:0> b=[3,4]
=> [3, 4]
irb(main):002:0> c=[5,6]
=> [5, 6]
irb(main):004:0> [*a,*b,*c]
=> [1, 2, 3, 4, 5, 6]
你有一个可行的想法，但#flatten!在错误的地方——它会使接收器变平，所以你可以用它把[1,2，['foo'， 'bar']]变成[1,2，'foo'，'bar']。
毫无疑问，我忘记了一些方法，但你可以串联起来:
a1.concat a2
a1 + a2 # creates a new array, as does a1 += a2
或预先考虑/追加:
a1.push(*a2) # note the asterisk
a2.unshift(*a1) # note the asterisk, and that a2 is the receiver
或接头:
a1[a1.length, 0] = a2
a1[a1.length..0] = a2
a1.insert(a1.length, *a2)
或append和flatten:
(a1 << a2).flatten! # a call to #flatten instead would return a new array
我很惊讶没有人提到reduce，当你有一个数组的数组时，它工作得很好:
lists = [["a", "b"], ["c", "d"]]
flatlist = lists.reduce(:+) # ["a", "b", "c", "d"]
["some", "thing"] + ["another", "thing"]
