我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
当前回答
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray + anotherarray # => ["some", "thing", "another", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
somearray.push(anotherarray).flatten # => ["some", "thing", "another", "thing"]
somearray.push *anotherarray # => ["another", "thing", "another", "thing"]
其他回答
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray + anotherarray # => ["some", "thing", "another", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
somearray.push(anotherarray).flatten # => ["some", "thing", "another", "thing"]
somearray.push *anotherarray # => ["another", "thing", "another", "thing"]
我很惊讶没有人提到reduce,当你有一个数组的数组时,它工作得很好:
lists = [["a", "b"], ["c", "d"]]
flatlist = lists.reduce(:+) # ["a", "b", "c", "d"]
详细阐述@Pilcrow的答案,对于大型数组唯一合适的答案是concat(+),因为它速度快,并且在循环中操作时不会分配一个新对象来进行垃圾回收。
下面是基准:
require 'benchmark'
huge_ary_1 = Array.new(1_000_000) { rand(5_000_000..30_000_00) }
huge_ary_2 = Array.new(1_000_000) { rand(35_000_000..55_000_00) }
Benchmark.bm do |bm|
p '-------------------CONCAT ----------------'
bm.report { huge_ary_1.concat(huge_ary_2) }
p '------------------- PUSH ----------------'
bm.report { huge_ary_1.push(*huge_ary_2) }
end
结果:
user system total real
"-------------------CONCAT ----------------"
0.000000 0.000000 0.000000 ( 0.009388)
"------------------- PUSH ----------------"
example/array_concat_vs_push.rb:13:in `block (2 levels) in <main>': stack level too deep (SystemStackError)
正如你所看到的,当数组足够大时,使用push会抛出ERROR:堆栈级别太深(SystemStackError)。
a = ["some", "thing"]
b = ["another", "thing"]
将b追加到a并将结果存储在a中:
a.push(*b)
or
a += b
在这两种情况下,a都变成:
["some", "thing", "another", "thing"]
但在前一种情况下,b的元素被追加到现有的a数组中,在后一种情况下,两个数组连接在一起,结果存储在a中。
a = ['a', 'b']
b = ['c', 'd']
arr = [a, b].flatten
这不会去除dups,但是
a|b
删除重复。