我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
当前回答
Somearray = ["some"， "thing"]
Anotherarray = ["another"， "thing"]
Somearray + anotherarray
其他回答
我发现更容易推入或追加数组，然后将它们压平，如下所示:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push anotherarray # => ["some", "thing", ["another", "thing"]]
#or
somearray << anotherarray # => ["some", "thing", ["another", "thing"]]
somearray.flatten! # => ["some", "thing", "another", "thing"]
somearray # => ["some", "thing", "another", "thing"]
这里有两种方法，注意在这个例子中，第一种方法分配一个新数组(转换为somearray = somearray + anotherarray)
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray += anotherarray # => ["some", "thing", "another", "thing"]
somearray = ["some", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
a = ["some", "thing"]
b = ["another", "thing"]
将b追加到a并将结果存储在a中:
a.push(*b)
or
a += b
在这两种情况下，a都变成:
["some", "thing", "another", "thing"]
但在前一种情况下，b的元素被追加到现有的a数组中，在后一种情况下，两个数组连接在一起，结果存储在a中。
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray + anotherarray # => ["some", "thing", "another", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
somearray.push(anotherarray).flatten # => ["some", "thing", "another", "thing"]
somearray.push *anotherarray # => ["another", "thing", "another", "thing"]
(array1 + array2).uniq
这样你就可以先得到array1元素。你不会得到副本。
