我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
当前回答
这里有两种方法，注意在这个例子中，第一种方法分配一个新数组(转换为somearray = somearray + anotherarray)
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray += anotherarray # => ["some", "thing", "another", "thing"]
somearray = ["some", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
其他回答
只是另一种方法。
[somearray, anotherarray].flatten
=> ["some", "thing", "another", "thing"]
这里有两种方法，注意在这个例子中，第一种方法分配一个新数组(转换为somearray = somearray + anotherarray)
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray += anotherarray # => ["some", "thing", "another", "thing"]
somearray = ["some", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
试试这个，它将结合你的数组删除重复
array1 = ["foo", "bar"]
array2 = ["foo1", "bar1"]
array3 = array1|array2
http://www.ruby-doc.org/core/classes/Array.html
进一步的文档请参阅“Set Union”
["some", "thing"] + ["another", "thing"]
如果新数据可以是数组或标量，并且如果它是数组，则希望防止新数据嵌套，splat操作符非常棒!它为标量返回一个标量，为数组返回一个已解压的参数列表。
1.9.3-p551 :020 > a = [1, 2]
=> [1, 2]
1.9.3-p551 :021 > b = [3, 4]
=> [3, 4]
1.9.3-p551 :022 > c = 5
=> 5
1.9.3-p551 :023 > a.object_id
=> 6617020
1.9.3-p551 :024 > a.push *b
=> [1, 2, 3, 4]
1.9.3-p551 :025 > a.object_id
=> 6617020
1.9.3-p551 :026 > a.push *c
=> [1, 2, 3, 4, 5]
1.9.3-p551 :027 > a.object_id
=> 6617020
