I like and double Jay's comment (https://stackoverflow.com/a/2223803/1517187). I agree that this is the bad design of Java. Many other languages support overriding static methods, as we see in previous comments. I feel Jay has also come to Java from Delphi like me. Delphi (Object Pascal) was one of the languages implementing OOP before Java and one of the first languages used for commercial application development. It is obvious that many people had experience with that language since it was in the past the only language to write commercial GUI products. And - yes, we could in Delphi override static methods. Actually, static methods in Delphi are called "class methods", while Delphi had the different concept of "Delphi static methods" which were methods with early binding. To override methods you had to use late binding, declare "virtual" directive. So it was very convenient and intuitive and I would expect this in Java.

简单的解决方案:使用单例实例。它将允许重写和继承。

在我的系统中，我有SingletonsRegistry类，它为传递的class返回实例。如果没有找到instance，则创建它。

Haxe语言类:

package rflib.common.utils;
import haxe.ds.ObjectMap;



class SingletonsRegistry
{
  public static var instances:Map<Class<Dynamic>, Dynamic>;

  static function __init__()
  {
    StaticsInitializer.addCallback(SingletonsRegistry, function()
    {
      instances = null;
    });

  } 

  public static function getInstance(cls:Class<Dynamic>, ?args:Array<Dynamic>)
  {
    if (instances == null) {
      instances = untyped new ObjectMap<Dynamic, Dynamic>();      
    }

    if (!instances.exists(cls)) 
    {
      if (args == null) args = [];
      instances.set(cls, Type.createInstance(cls, args));
    }

    return instances.get(cls);
  }


  public static function validate(inst:Dynamic, cls:Class<Dynamic>)
  {
    if (instances == null) return;

    var inst2 = instances[cls];
    if (inst2 != null && inst != inst2) throw "Can\'t create multiple instances of " + Type.getClassName(cls) + " - it's singleton!";
  }

}

一般来说，允许“重写”静态方法是没有意义的，因为没有好的方法来确定在运行时调用哪个方法。以Employee为例，如果我们调用regularemploee . getbonusmultiplier()——应该执行哪个方法?

以Java为例，人们可以想象这样一种语言定义:只要静态方法是通过对象实例调用的，就可以“覆盖”它们。然而，这样做只是重新实现常规的类方法，在没有真正带来任何好处的情况下为语言增加冗余。

现在看到上面的答案，每个人都知道我们不能重写静态方法，但不应该误解从子类访问静态方法的概念。

我们可以通过子类引用访问超类的静态方法，如果这个静态方法没有被子类中定义的新静态方法所隐藏。

例如，请参见下面的代码:-

public class StaticMethodsHiding {
    public static void main(String[] args) {
        SubClass.hello();
    }
}


class SuperClass {
    static void hello(){
        System.out.println("SuperClass saying Hello");
    }
}


class SubClass extends SuperClass {
    // static void hello() {
    // System.out.println("SubClass Hello");
    // }
}

输出:

SuperClass saying Hello

关于在子类中隐藏静态方法的细节，请参阅Java oracle文档并搜索你可以在子类中做什么。

谢谢

通过重写，可以实现动态多态。 当您说覆盖静态方法时，您试图使用的词语是矛盾的。

静态表示-编译时，重写用于动态多态性。 两者在性质上是相反的，因此不能同时使用。

动态多态行为发生在程序员使用对象并访问实例方法时。JRE将根据您使用的对象类型映射不同类的不同实例方法。

当你说覆盖静态方法时，我们将使用类名访问静态方法，它将在编译时被链接，因此没有在运行时将方法与静态方法链接的概念。因此，术语“重写”静态方法本身没有任何意义。

注意:即使你用一个对象访问一个类方法，java编译器仍然有足够的智能来发现它，并会做静态链接。

Yes. Practically Java allows overriding static method, and No theoretically if you Override a static method in Java then it will compile and run smoothly but it will lose Polymorphism which is the basic property of Java. You will Read Everywhere that it is not possible to try yourself compiling and running. you will get your answer. e.g. If you Have Class Animal and a static method eat() and you Override that static method in its Subclass lets called it Dog. Then when wherever you Assign a Dog object to an Animal Reference and call eat() according to Java Dog's eat() should have been called but in static Overriding Animals' eat() will Be Called.

class Animal {
    public static void eat() {
        System.out.println("Animal Eating");
    }
}

class Dog extends Animal{
    public static void eat() {
        System.out.println("Dog Eating");
    }
}

class Test {
    public static void main(String args[]) {
       Animal obj= new Dog();//Dog object in animal
       obj.eat(); //should call dog's eat but it didn't
    }
}


Output Animal Eating

According to Polymorphism Principle of Java, the Output Should be Dog Eating. But the result was different because to support Polymorphism Java uses Late Binding that means methods are called only at the run-time but not in the case of static methods. In static methods compiler calls methods at the compile time rather than the run-time, so we get methods according to the reference and not according to the object a reference a containing that's why You can say Practically it supports static overring but theoretically, it doesn't.