我的解决方案是基于@AdrianoSpadoni给出的，并解决了克隆对象的需要

function generateData(object: any, path: string, value: any): object {
  const clone = JSON.parse(JSON.stringify(object));
  path
    .split(".")
    .reduce(
    (o, p, i) => (o[p] = path.split(".").length === ++i ? value : o[p] || {}),
  clone
);
  return clone;
}

我只是基于一些类似的代码，我已经有了，它似乎工作:

Object.byString = function(o, s) {
    s = s.replace(/\[(\w+)\]/g, '.$1'); // convert indexes to properties
    s = s.replace(/^\./, '');           // strip a leading dot
    var a = s.split('.');
    for (var i = 0, n = a.length; i < n; ++i) {
        var k = a[i];
        if (k in o) {
            o = o[k];
        } else {
            return;
        }
    }
    return o;
}

用法::

Object.byString(someObj, 'part3[0].name');

在http://jsfiddle.net/alnitak/hEsys/上可以看到一个工作演示

有些人注意到，如果传递的字符串中最左边的索引与对象中正确嵌套的条目不对应，这段代码将抛出错误。这是一个有效的问题，但我认为最好在调用时使用try / catch块来解决，而不是让这个函数对于无效的索引无声地返回undefined。

这可以通过将逻辑分解为三个独立的函数来简化:

const isVal = a => a != null; // everything except undefined + null

const prop = prop => obj => {
    if (isVal(obj)) {
        const value = obj[prop];
        if (isVal(value)) return value;
        else return undefined;
    } else return undefined;
};

const path = paths => obj => {
    const pathList = typeof paths === 'string' ? paths.split('.') : paths;
    return pathList.reduce((value, key) => prop(key)(value), obj);
};

//usage:
const myObject = { foo: { bar: { baz: 'taco' } } };
const result = path('foo.bar')(myObject);
//results => { baz: 'taco' }

这个变体支持:

传递一个数组或字符串参数 在调用和执行期间处理未定义的值 独立测试每个功能 单独使用每个函数

在这里我提供了更多的方法，这些方法在很多方面看起来都更快:

选项1:Split string on。Or [Or] Or ' Or "，颠倒过来，跳过空项。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var parts = path.split(/\[|\]|\.|'|"/g).reverse(), name; // (why reverse? because it's usually faster to pop off the end of an array)
    while (parts.length) { name=parts.pop(); if (name) origin=origin[name]; }
    return origin;
}

选项2(最快的，除了eval):低级字符扫描(没有regex/split/等等，只是一个快速字符扫描)。 注意:该命令不支持索引引用。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c = '', pc, i = 0, n = path.length, name = '';
    if (n) while (i<=n) ((c = path[i++]) == '.' || c == '[' || c == ']' || c == void 0) ? (name?(origin = origin[name], name = ''):(pc=='.'||pc=='['||pc==']'&&c==']'?i=n+2:void 0),pc=c) : name += c;
    if (i==n+2) throw "Invalid path: "+path;
    return origin;
} // (around 1,000,000+/- ops/sec)

选项3:(新:选项2扩展到支持引号-有点慢，但仍然很快)

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c, pc, i = 0, n = path.length, name = '', q;
    while (i<=n)
        ((c = path[i++]) == '.' || c == '[' || c == ']' || c == "'" || c == '"' || c == void 0) ? (c==q&&path[i]==']'?q='':q?name+=c:name?(origin?origin=origin[name]:i=n+2,name='') : (pc=='['&&(c=='"'||c=="'")?q=c:pc=='.'||pc=='['||pc==']'&&c==']'||pc=='"'||pc=="'"?i=n+2:void 0), pc=c) : name += c;
    if (i==n+2 || name) throw "Invalid path: "+path;
    return origin;
}

JSPerf： http://jsperf.com/ways-to-dereference-a-delimited-property-string/3

"eval(...)" is still king though (performance wise that is). If you have property paths directly under your control, there shouldn't be any issues with using 'eval' (especially if speed is desired). If pulling property paths "over the wire" (on the line!? lol :P), then yes, use something else to be safe. Only an idiot would say to never use "eval" at all, as there ARE good reasons when to use it. Also, "It is used in Doug Crockford's JSON parser." If the input is safe, then no problems at all. Use the right tool for the right job, that's it.

ES6:只有一行在Vanila JS(它返回null如果没有找到，而不是给出错误):

'path.string'.split('.').reduce((p,c)=>p&&p[c]||null, MyOBJ)

或例子:

'a.b.c'.split('.').reduce((p,c)=>p&&p[c]||null, {a:{b:{c:1}}})

可选链接操作符:

'a.b.c'.split('.').reduce((p,c)=>p?.[c], {a:{b:{c:1}}})

对于一个也识别false, 0和负数并接受默认值作为参数的ready to use函数:

const resolvePath = (object, path, defaultValue) => path
   .split('.')
   .reduce((o, p) => o ? o[p] : defaultValue, object)

示例:

resolvePath(window,'document.body') => <body>
resolvePath(window,'document.body.xyz') => undefined
resolvePath(window,'document.body.xyz', null) => null
resolvePath(window,'document.body.xyz', 1) => 1

奖金:

要设置路径(由@rob-gordon请求)，您可以使用:

const setPath = (object, path, value) => path
   .split('.')
   .reduce((o,p,i) => o[p] = path.split('.').length === ++i ? value : o[p] || {}, object)

例子:

let myVar = {}
setPath(myVar, 'a.b.c', 42) => 42
console.log(myVar) => {a: {b: {c: 42}}}

使用[]访问数组:

const resolvePath = (object, path, defaultValue) => path
   .split(/[\.\[\]\'\"]/)
   .filter(p => p)
   .reduce((o, p) => o ? o[p] : defaultValue, object)

例子:

const myVar = {a:{b:[{c:1}]}}
resolvePath(myVar,'a.b[0].c') => 1
resolvePath(myVar,'a["b"][\'0\'].c') => 1

请注意，以下选项并不适用于所有有效的unicode属性名(但据我所知，其他选项也不适用)。

const PATTERN = /[\^|\[|\.]([$|\w]+)/gu function propValue(o, s) { const names = [] for(let [, name] of [...s.matchAll(PATTERN)]) names.push(name) return names.reduce((p, propName) => { if(!p.hasOwnProperty(propName)) throw 'invalid property name' return p[propName] }, o) } let path = 'myObject.1._property2[0][0].$property3' let o = { 1: { _property2: [ [{ $property3: 'Hello World' }] ] } } console.log(propValue(o, path)) // 'Hello World'