通过字符串路径访问嵌套的JavaScript对象和数组

我有一个这样的数据结构:

var someObject = {
    'part1' : {
        'name': 'Part 1',
        'size': '20',
        'qty' : '50'
    },
    'part2' : {
        'name': 'Part 2',
        'size': '15',
        'qty' : '60'
    },
    'part3' : [
        {
            'name': 'Part 3A',
            'size': '10',
            'qty' : '20'
        }, {
            'name': 'Part 3B',
            'size': '5',
            'qty' : '20'
        }, {
            'name': 'Part 3C',
            'size': '7.5',
            'qty' : '20'
        }
    ]
};

我想使用这些变量访问数据:

var part1name = "part1.name";
var part2quantity = "part2.qty";
var part3name1 = "part3[0].name";

part1name应该用someObject.part1.name的值填充，即“Part 1”。part2quantity也是一样，它的容量是60。

有没有办法实现这与纯javascript或JQuery?

当前回答

而不是尝试模拟JS语法，你将不得不花费大量的计算解析，或者只是错误/忘记一些事情，比如一堆这些答案(带.s的键，有人吗?)，只是使用一个键数组。

var part1name     = Object.get(someObject, ['part1', 'name']);
var part2quantity = Object.get(someObject, ['part2', 'qty']);
var part3name1    = Object.get(someObject, ['part3', 0, 'name']);

如果您需要使用单个字符串，只需JSONify它。此方法的另一个改进是您可以删除/设置根级对象。

function resolve(obj, path) {
    let root = obj = [obj];
    path = [0, ...path];
    while (path.length > 1)
        obj = obj[path.shift()];
    return [obj, path[0], root];
}
Object.get = (obj, path) => {
    let [parent, key] = resolve(obj, path);
    return parent[key];
};
Object.del = (obj, path) => {
    let [parent, key, root] = resolve(obj, path);
    delete parent[key];
    return root[0];
};
Object.set = (obj, path, value) => {
    let [parent, key, root] = resolve(obj, path);
    parent[key] = value;
    return root[0];
};

其他功能演示:

对于.set(/.del()的bob =是不必要的，除非你的路径可能是空的(操作根对象)。我证明我不克隆的对象使用史蒂夫保持原始的引用和检查bob == steve //true后，第一个.set(

2021-05-19 13:10:31

其他回答

我认为你的要求是:

var part1name = someObject.part1.name;
var part2quantity = someObject.part2.qty;
var part3name1 =  someObject.part3[0].name;

你可以这样问:

var part1name = someObject["part1"]["name"];
var part2quantity = someObject["part2"]["qty"];
var part3name1 =  someObject["part3"][0]["name"];

这两种方法都可行

也许这是你自找的

var partName = "part1";
var nameStr = "name";

var part1name = someObject[partName][nameStr];

终于轮到你自找麻烦了

var partName = "part1.name";

var partBits = partName.split(".");

var part1name = someObject[partBits[0]][partBits[1]];

2011-06-27 10:28:27

从@Alnitak answer开始，我构建了这个源代码，它下载了一个实际的.JSON文件并对其进行处理，为每一步打印到控制台解释字符串，以及在传递错误键的情况下的更多细节:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
  <script>
function retrieveURL(url) {
        var client = new XMLHttpRequest();
        prefix = "https://cors-anywhere.herokuapp.com/"
        client.open('GET', prefix + url);
        client.responseType = 'text';
        client.onload = function() {
            response = client.response; // Load remote response.
            console.log("Response received.");
            parsedJSON  = JSON.parse(response);
            console.log(parsedJSON);
            console.log(JSONitemByPath(parsedJSON,"geometry[6].obs[3].latituade"));
            return response;
        };
        try {
            client.send();
        } catch(e) {
            console.log("NETWORK ERROR!");
            console.log(e);
        }
}



function JSONitemByPath(o, s) {
    structure = "";
    originalString = s;
    console.log("Received string: ", s);
    s = s.replace(/\[(\w+)\]/g, '.$1'); // convert indexes to properties
    console.log("Converted to   : ", s);
    s = s.replace(/^\./, '');           // strip a leading dot
    var a = s.split('.');

    console.log("Single keys to parse: ",a);

    for (var i = 0, n = a.length; i < n; ++i) {
        var k = a[i];
        if (k in o) {
            o = o[k];
            console.log("object." + structure +  a[i], o);
            structure +=  a[i] + ".";
        } else {
            console.log("ERROR: wrong path passed: ", originalString);
            console.log("       Last working level: ", structure.substr(0,structure.length-1));
            console.log("       Contents: ", o);
            console.log("       Available/passed key: ");
            Object.keys(o).forEach((prop)=> console.log("       "+prop +"/" + k));
            return;
        }
    }
    return o;
}


function main() {
    rawJSON = retrieveURL("http://haya2now.jp/data/data.json");
}

</script>
  </head>
  <body onload="main()">
  </body>
</html>

输出的例子:

Response received.
json-querier.html:17 {geometry: Array(7), error: Array(0), status: {…}}
json-querier.html:34 Received string:  geometry[6].obs[3].latituade
json-querier.html:36 Converted to   :  geometry.6.obs.3.latituade
json-querier.html:40 Single keys to parse:  (5) ["geometry", "6", "obs", "3", "latituade"]
json-querier.html:46 object.geometry (7) [{…}, {…}, {…}, {…}, {…}, {…}, {…}]
json-querier.html:46 object.geometry.6 {hayabusa2: {…}, earth: {…}, obs: Array(6), TT: 2458816.04973593, ryugu: {…}, …}
json-querier.html:46 object.geometry.6.obs (6) [{…}, {…}, {…}, {…}, {…}, {…}]
json-querier.html:46 object.geometry.6.obs.3 {longitude: 148.98, hayabusa2: {…}, sun: {…}, name: "DSS-43", latitude: -35.4, …}
json-querier.html:49 ERROR: wrong path passed:  geometry[6].obs[3].latituade
json-querier.html:50        Last working level:  geometry.6.obs.3
json-querier.html:51        Contents:  {longitude: 148.98, hayabusa2: {…}, sun: {…}, name: "DSS-43", latitude: -35.4, …}
json-querier.html:52        Available/passed key: 
json-querier.html:53        longitude/latituade
json-querier.html:53        hayabusa2/latituade
json-querier.html:53        sun/latituade
json-querier.html:53        name/latituade
json-querier.html:53        latitude/latituade
json-querier.html:53        altitude/latituade
json-querier.html:18 undefined

2019-11-28 13:38:11

我还没有找到一个包来使用字符串路径执行所有操作，所以我最终编写了自己的快速小包，它支持insert()， get()(默认返回)，set()和remove()操作。

您可以使用点表示法、括号、数字索引、字符串数字属性以及非单词字符的键。简单用法如下:

> var jsocrud = require('jsocrud');

...

// Get (Read) ---
> var obj = {
>     foo: [
>         {
>             'key w/ non-word chars': 'bar'
>         }
>     ]
> };
undefined

> jsocrud.get(obj, '.foo[0]["key w/ non-word chars"]');
'bar'

https://www.npmjs.com/package/jsocrud

https://github.com/vertical-knowledge/jsocrud

2015-04-25 01:08:31

简单的函数，允许字符串或数组路径。

function get(obj, path) {
  if(typeof path === 'string') path = path.split('.');

  if(path.length === 0) return obj;
  return get(obj[path[0]], path.slice(1));
}

const obj = {a: {b: {c: 'foo'}}};

console.log(get(obj, 'a.b.c')); //foo

console.log(get(obj, ['a', 'b', 'c'])); //foo

2016-12-26 04:51:19

这是一个有lodash的单班轮。

const deep = { l1: { l2: { l3: "Hello" } } };
const prop = "l1.l2.l3";
const val = _.reduce(prop.split('.'), function(result, value) { return result ? result[value] : undefined; }, deep);
// val === "Hello"

或者更好……

const val = _.get(deep, prop);

或ES6版本w/ reduce…

const val = prop.split('.').reduce((r, val) => { return r ? r[val] : undefined; }, deep);

普伦克尔

2016-12-08 16:19:48

通过字符串路径访问嵌套的JavaScript对象和数组

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