如你所知，android软件的键盘只有在有可能的输入事件时才可见。换句话说，只有当EditText被聚焦时，键盘才可见。这意味着你可以通过使用OnFocusChangeListener获得键盘是否可见。

//Declare this Globally

public boolean isKeyBoardVisible = false;

//In OnCreate *[For Activity]*, OnCreateView *[For Fragment]*

text_send.setOnFocusChangeListener(new View.OnFocusChangeListener() {

    @Override
    public void onFocusChange(View v, boolean hasFocus) {
        if(hasFocus)
            isKeyBoardVisible = true;
        else
            isKeyBoardVisible = false;
    }
});

现在你可以在类的任何地方使用isKeyBoardVisible变量来获取键盘是否打开。这对我来说很有效。

注意:当使用InputMethodManager以编程方式打开键盘时，这个过程不起作用，因为它不调用OnFocusChangeListener。

我把答案转换为kotlin，希望这对kotlin用户有帮助。

private fun checkKeyboardVisibility() {
    var isKeyboardShowing = false

    binding.coordinator.viewTreeObserver.addOnGlobalLayoutListener {
        val r = Rect()
        binding.coordinator.getWindowVisibleDisplayFrame(r)
        val screenHeight = binding.coordinator.rootView.height

        // r.bottom is the position above soft keypad or device button.
        // if keypad is shown, the r.bottom is smaller than that before.
        val keypadHeight = screenHeight - r.bottom


        if (keypadHeight > screenHeight * 0.15) { // 0.15 ratio is perhaps enough to determine keypad height.
            // keyboard is opened
            if (!isKeyboardShowing) {
                isKeyboardShowing = true

            }
        } else {
            // keyboard is closed
            if (isKeyboardShowing) {
                isKeyboardShowing = false

            }
        }
    }
}

可以使用showSoftInput()和hideSoftInput()的回调结果来检查键盘的状态。完整的细节和示例代码在

https://rogerkeays.com/how-to-check-if-the-software-keyboard-is-shown-in-android

我用这个作为基础:https://rogerkeays.com/how-to-check-if-the-software-keyboard-is-shown-in-android

/**
* To capture the result of IMM hide/show soft keyboard
*/
public class IMMResult extends ResultReceiver {
     public int result = -1;
     public IMMResult() {
         super(null);
}

@Override 
public void onReceiveResult(int r, Bundle data) {
    result = r;
}

// poll result value for up to 500 milliseconds
public int getResult() {
    try {
        int sleep = 0;
        while (result == -1 && sleep < 500) {
            Thread.sleep(100);
            sleep += 100;
        }
    } catch (InterruptedException e) {
        Log.e("IMMResult", e.getMessage());
    }
    return result;
}
}

然后写了这个方法:

public boolean isSoftKeyboardShown(InputMethodManager imm, View v) {
    
    IMMResult result = new IMMResult();
    int res;
    
    imm.showSoftInput(v, 0, result);

    // if keyboard doesn't change, handle the keypress
    res = result.getResult();
    if (res == InputMethodManager.RESULT_UNCHANGED_SHOWN ||
            res == InputMethodManager.RESULT_UNCHANGED_HIDDEN) {

        return true;
    }
    else
        return false;

}

然后你可以用它来测试所有可能打开软键盘的字段(EditText, AutoCompleteTextView等):

    InputMethodManager imm = (InputMethodManager) getActivity().getSystemService(Context.INPUT_METHOD_SERVICE);
    if(isSoftKeyboardShown(imm, editText1) | isSoftKeyboardShown(imm, autocompletetextview1))
        //close the softkeyboard
        imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);

当然不是一个理想的解决方案，但它可以完成工作。

@iWantScala的回答很棒，但不适合我 rootView.getRootView().getHeight()总是有相同的值

一种方法是定义两个变量

private int maxRootViewHeight = 0;
private int currentRootViewHeight = 0;

添加全局监听器

rootView.getViewTreeObserver()
    .addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            currentRootViewHeight = rootView.getHeight();
            if (currentRootViewHeight > maxRootViewHeight) {
                maxRootViewHeight = currentRootViewHeight;
            }
        }
    });

然后检查

if (currentRootViewHeight >= maxRootViewHeight) {
    // Keyboard is hidden
} else {
    // Keyboard is shown
}

工作正常

没有直接的方法-请参阅http://groups.google.com/group/android-platform/browse_thread/thread/1728f26f2334c060/5e4910f0d9eb898a，来自Android团队的Dianne Hackborn已经回复。但是，您可以通过检查#onMeasure中窗口大小是否改变来间接检测它。参见如何检查软件键盘的可见性在Android?。