final View activityRootView = findViewById(R.id.rootlayout);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {

            Rect r = new Rect();
            activityRootView.getWindowVisibleDisplayFrame(r);

            int screenHeight = activityRootView.getRootView().getHeight();
            Log.e("screenHeight", String.valueOf(screenHeight));
            int heightDiff = screenHeight - (r.bottom - r.top);
            Log.e("heightDiff", String.valueOf(heightDiff));
            boolean visible = heightDiff > screenHeight / 3;
            Log.e("visible", String.valueOf(visible));
            if (visible) {
                Toast.makeText(LabRegister.this, "I am here 1", Toast.LENGTH_SHORT).show();
            } else {
                Toast.makeText(LabRegister.this, "I am here 2", Toast.LENGTH_SHORT).show();
            }
        }
});

There is a direct method to find this out. And, it does not require the layout changes. So it works in immersive fullscreen mode, too. But, unfortunately, it does not work on all devices. So you have to test it with your device(s). The trick is that you try to hide or show the soft keyboard and capture the result of that try. If it works correct then the keyboard is not really shown or hidden. We just ask for the state. To stay up-to-date, you simply repeat this operation, e.g. every 200 milliseconds, using a Handler. The implementation below does just a single check. If you do multiple checks, then you should enable all the (_keyboardVisible) tests.

public interface OnKeyboardShowHide
{
    void    onShowKeyboard( Object param );
    void    onHideKeyboard( Object param );
}

private static Handler      _keyboardHandler    = new Handler();
private boolean             _keyboardVisible    = false;
private OnKeyboardShowHide  _keyboardCallback;
private Object              _keyboardCallbackParam;

public void start( OnKeyboardShowHide callback, Object callbackParam )
{
    _keyboardCallback      = callback;
    _keyboardCallbackParam = callbackParam;
    //
    View view = getCurrentFocus();
    if (view != null)
    {
        InputMethodManager imm = (InputMethodManager) getSystemService( Activity.INPUT_METHOD_SERVICE );
        imm.hideSoftInputFromWindow( view.getWindowToken(), InputMethodManager.HIDE_IMPLICIT_ONLY, _keyboardResultReceiver );
        imm.showSoftInput( view, InputMethodManager.SHOW_IMPLICIT, _keyboardResultReceiver );
    }
    else // if (_keyboardVisible)
    {
        _keyboardVisible = false;
        _keyboardCallback.onHideKeyboard( _keyboardCallbackParam );
    }
}

private ResultReceiver      _keyboardResultReceiver = new ResultReceiver( _keyboardHandler )
{
    @Override
    protected void onReceiveResult( int resultCode, Bundle resultData )
    {
        switch (resultCode)
        {
            case InputMethodManager.RESULT_SHOWN :
            case InputMethodManager.RESULT_UNCHANGED_SHOWN :
                // if (!_keyboardVisible)
                {
                    _keyboardVisible = true;
                    _keyboardCallback.onShowKeyboard( _keyboardCallbackParam );
                }
                break;
            case InputMethodManager.RESULT_HIDDEN :
            case InputMethodManager.RESULT_UNCHANGED_HIDDEN :
                // if (_keyboardVisible)
                {
                    _keyboardVisible = false;
                    _keyboardCallback.onHideKeyboard( _keyboardCallbackParam );
                }
                break;
        }
    }
};

我也遇到过类似的问题。我需要对屏幕上的Enter按钮做出反应(这隐藏了键盘)。在这种情况下，你可以订阅键盘打开的文本视图的OnEditorAction -如果你有多个可编辑框，那么就订阅所有的文本视图。

在你的活动中，你可以完全控制键盘，所以如果你监听所有打开和关闭事件，你就不会面临键盘是否打开的问题。

非常容易

1. 把id放在根视图上

rootView只是一个视图指向我的根视图在这种情况下，一个相对布局:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:id="@+id/addresses_confirm_root_view"
                android:background="@color/WHITE_CLR">

2. 在Activity中初始化根视图:

RelativeLayout rootView = (RelativeLayout) findViewById(R.id.addresses_confirm_root_view);

3.使用getViewTreeObserver()检测键盘是否打开或关闭

    rootView.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
            @Override
            public void onGlobalLayout() {
                int heightDiff = rootView.getRootView().getHeight() - rootView.getHeight();
                
                if (heightDiff > 100) { // Value should be less than keyboard's height 
                    Log.e("MyActivity", "keyboard opened");
                } else { 
                    Log.e("MyActivity", "keyboard closed");
                }
            }
        });

@iWantScala的回答很棒，但不适合我 rootView.getRootView().getHeight()总是有相同的值

一种方法是定义两个变量

private int maxRootViewHeight = 0;
private int currentRootViewHeight = 0;

添加全局监听器

rootView.getViewTreeObserver()
    .addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            currentRootViewHeight = rootView.getHeight();
            if (currentRootViewHeight > maxRootViewHeight) {
                maxRootViewHeight = currentRootViewHeight;
            }
        }
    });

然后检查

if (currentRootViewHeight >= maxRootViewHeight) {
    // Keyboard is hidden
} else {
    // Keyboard is shown
}

工作正常

这里有一个工作区，以了解软键盘是否可见。

使用ActivityManager.getRunningServices(max_count_of_services)检查系统上正在运行的服务; 从返回的ActivityManager。运行ningserviceinfo实例，检查软键盘服务的clientCount值。 前面提到的clientCount将在每次显示软键盘时递增。例如，如果clientCount最初是1，那么在显示键盘时它将是2。 在键盘撤销时，clientCount递减。在本例中，它重置为1。

一些流行的键盘在它们的classname中有特定的关键字:

谷歌AOSP = IME Swype =输入法 Swiftkey = KeyboardService Fleksy =键盘 Adaptxt = IME (KPTAdaptxtIME) 智能=键盘(SmartKeyboard)

从ActivityManager。RunningServiceInfo，在ClassNames中检查上述模式。 同时,ActivityManager。RunningServiceInfo的clientPackage=android，表示键盘绑定到系统。

可以将上述信息进行严格的组合，以判断软键盘是否可见。