对于我所需要的需求来说，这要简单得多。希望这能有所帮助:

关于MainActivity:

public void dismissKeyboard(){
    InputMethodManager imm =(InputMethodManager)this.getSystemService(Context.INPUT_METHOD_SERVICE);
    imm.hideSoftInputFromWindow(mSearchBox.getWindowToken(), 0);
    mKeyboardStatus = false;
}

public void showKeyboard(){
    InputMethodManager imm =(InputMethodManager)this.getSystemService(Context.INPUT_METHOD_SERVICE);
    imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, InputMethodManager.HIDE_IMPLICIT_ONLY);
    mKeyboardStatus = true;
}

private boolean isKeyboardActive(){
    return mKeyboardStatus;
}

mKeyboardStatus的默认基元布尔值将初始化为false。

然后检查如下值，并执行相应的操作:

 mSearchBox.requestFocus();
    if(!isKeyboardActive()){
        showKeyboard();
    }else{
        dismissKeyboard();
    }

在Android中，你可以通过ADB shell进行检测。我写下并使用了这个方法:

{
        JSch jsch = new JSch();
        try {
            Session session = jsch.getSession("<userName>", "<IP>", 22);
            session.setPassword("<Password>");
            Properties config = new Properties();
            config.put("StrictHostKeyChecking", "no");
            session.setConfig(config);
            session.connect();

            ChannelExec channel = (ChannelExec)session.openChannel("exec");
            BufferedReader in = new BufferedReader(new    
            InputStreamReader(channel.getInputStream()));
            channel.setCommand("C:/Android/android-sdk/platform-tools/adb shell dumpsys window 
            InputMethod | findstr \"mHasSurface\"");
            channel.connect();

            String msg = null;
            String msg2 = " mHasSurface=true";

            while ((msg = in.readLine()) != null) {
                Boolean isContain = msg.contains(msg2);
                log.info(isContain);
                if (isContain){
                    log.info("Hiding keyboard...");
                    driver.hideKeyboard();
                }
                else {
                    log.info("No need to hide keyboard.");
                }
            }

            channel.disconnect();
            session.disconnect();

        } catch (JSchException | IOException | InterruptedException e) {
            e.printStackTrace();
        }
    }
}

A可能会使用:

@Override
public void onConfigurationChanged(Configuration newConfig) {
    super.onConfigurationChanged(newConfig);

    Log.d(
    getClass().getSimpleName(), 
    String.format("conf: %s", newConfig));

    if (newConfig.hardKeyboardHidden != hardKeyboardHidden) {
        onHardwareKeyboardChange(newConfig.hardKeyboardHidden);

        hardKeyboardHidden = newConfig.hardKeyboardHidden;
    }

    if (newConfig.keyboardHidden != keyboardHidden) {
        onKeyboardChange(newConfig.keyboardHidden);

        keyboardHidden = newConfig.hardKeyboardHidden;
    }

}

public static final int KEYBOARDHIDDEN_UNDEFINED = 0;
public static final int KEYBOARDHIDDEN_NO = 1;
public static final int KEYBOARDHIDDEN_YES = 2;
public static final int KEYBOARDHIDDEN_SOFT = 3;

//todo
private void onKeyboardChange(int keyboardHidden) {

}

//todo
private void onHardwareKeyboardChange(int hardKeyboardHidden) {

}

试试这段代码，它真的工作，如果keyboardshow是显示的，那么这个函数返回真值....

private final String TAG = "TextEditor";
private TextView mTextEditor;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_editor);
    mTextEditor = (TextView) findViewById(R.id.text_editor);
    mTextEditor.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            isKeyboardShown(mTextEditor.getRootView());
        }
    });
}

private boolean isKeyboardShown(View rootView) {
    /* 128dp = 32dp * 4, minimum button height 32dp and generic 4 rows soft keyboard */
    final int SOFT_KEYBOARD_HEIGHT_DP_THRESHOLD = 128;

    Rect r = new Rect();
    rootView.getWindowVisibleDisplayFrame(r);
    DisplayMetrics dm = rootView.getResources().getDisplayMetrics();
    /* heightDiff = rootView height - status bar height (r.top) - visible frame height (r.bottom - r.top) */
    int heightDiff = rootView.getBottom() - r.bottom;
    /* Threshold size: dp to pixels, multiply with display density */
    boolean isKeyboardShown = heightDiff > SOFT_KEYBOARD_HEIGHT_DP_THRESHOLD * dm.density;

    Log.d(TAG, "isKeyboardShown ? " + isKeyboardShown + ", heightDiff:" + heightDiff + ", density:" + dm.density
            + "root view height:" + rootView.getHeight() + ", rect:" + r);

    return isKeyboardShown;
}

我是这样做的，但只有当你的目标是关闭/打开键盘时，它才有意义。

关闭示例:(检查键盘是否已经关闭，如果没有关闭)

imm.showSoftInput(etSearch, InputMethodManager.HIDE_IMPLICIT_ONLY, new ResultReceiver(null) {
                    @Override
                    protected void onReceiveResult(int resultCode, Bundle resultData) {
                        super.onReceiveResult(resultCode, resultData);
                        if (resultCode != InputMethodManager.RESULT_UNCHANGED_HIDDEN)
                            imm.toggleSoftInput(InputMethodManager.SHOW_FORCED, 0);
                    }
                });

这里有一个工作区，以了解软键盘是否可见。

使用ActivityManager.getRunningServices(max_count_of_services)检查系统上正在运行的服务; 从返回的ActivityManager。运行ningserviceinfo实例，检查软键盘服务的clientCount值。 前面提到的clientCount将在每次显示软键盘时递增。例如，如果clientCount最初是1，那么在显示键盘时它将是2。 在键盘撤销时，clientCount递减。在本例中，它重置为1。

一些流行的键盘在它们的classname中有特定的关键字:

谷歌AOSP = IME Swype =输入法 Swiftkey = KeyboardService Fleksy =键盘 Adaptxt = IME (KPTAdaptxtIME) 智能=键盘(SmartKeyboard)

从ActivityManager。RunningServiceInfo，在ClassNames中检查上述模式。 同时,ActivityManager。RunningServiceInfo的clientPackage=android，表示键盘绑定到系统。

可以将上述信息进行严格的组合，以判断软键盘是否可见。