Android系统中是否有一种方法可以检测软件(也就是Android。“软”)键盘在屏幕上可见吗?


当前回答

A可能会使用:

@Override
public void onConfigurationChanged(Configuration newConfig) {
    super.onConfigurationChanged(newConfig);

    Log.d(
    getClass().getSimpleName(), 
    String.format("conf: %s", newConfig));

    if (newConfig.hardKeyboardHidden != hardKeyboardHidden) {
        onHardwareKeyboardChange(newConfig.hardKeyboardHidden);

        hardKeyboardHidden = newConfig.hardKeyboardHidden;
    }

    if (newConfig.keyboardHidden != keyboardHidden) {
        onKeyboardChange(newConfig.keyboardHidden);

        keyboardHidden = newConfig.hardKeyboardHidden;
    }

}

public static final int KEYBOARDHIDDEN_UNDEFINED = 0;
public static final int KEYBOARDHIDDEN_NO = 1;
public static final int KEYBOARDHIDDEN_YES = 2;
public static final int KEYBOARDHIDDEN_SOFT = 3;

//todo
private void onKeyboardChange(int keyboardHidden) {

}

//todo
private void onHardwareKeyboardChange(int hardKeyboardHidden) {

}

其他回答

@iWantScala的回答很棒,但不适合我 rootView.getRootView().getHeight()总是有相同的值

一种方法是定义两个变量

private int maxRootViewHeight = 0;
private int currentRootViewHeight = 0;

添加全局监听器

rootView.getViewTreeObserver()
    .addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            currentRootViewHeight = rootView.getHeight();
            if (currentRootViewHeight > maxRootViewHeight) {
                maxRootViewHeight = currentRootViewHeight;
            }
        }
    });

然后检查

if (currentRootViewHeight >= maxRootViewHeight) {
    // Keyboard is hidden
} else {
    // Keyboard is shown
}

工作正常

这是如何在一个片段中使用软键盘状态监听器(适用于API 21及以上)

    private var currentWindowInsets: WindowInsetsCompat = WindowInsetsCompat.Builder().build()

    override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
        super.onViewCreated(view, savedInstanceState)
        setWindowInsetsAnimationCallback(requireView().rootView, object : Callback(DISPATCH_MODE_CONTINUE_ON_SUBTREE) {
            override fun onProgress(insets: WindowInsetsCompat, runningAnimations: MutableList<WindowInsetsAnimationCompat>): WindowInsetsCompat {
                currentWindowInsets = insets
                return insets
            }
    
            override fun onEnd(animation: WindowInsetsAnimationCompat) {
                super.onEnd(animation)
                val keyboardIsVisible = currentWindowInsets.isVisible(WindowInsetsCompat.Type.ime())
                if (keyboardIsVisible) { //do your stuff }
            }
        })
    }

我也遇到过类似的问题。我需要对屏幕上的Enter按钮做出反应(这隐藏了键盘)。在这种情况下,你可以订阅键盘打开的文本视图的OnEditorAction -如果你有多个可编辑框,那么就订阅所有的文本视图。

在你的活动中,你可以完全控制键盘,所以如果你监听所有打开和关闭事件,你就不会面临键盘是否打开的问题。

如你所知,android软件的键盘只有在有可能的输入事件时才可见。换句话说,只有当EditText被聚焦时,键盘才可见。这意味着你可以通过使用OnFocusChangeListener获得键盘是否可见。

//Declare this Globally

public boolean isKeyBoardVisible = false;

//In OnCreate *[For Activity]*, OnCreateView *[For Fragment]*

text_send.setOnFocusChangeListener(new View.OnFocusChangeListener() {

    @Override
    public void onFocusChange(View v, boolean hasFocus) {
        if(hasFocus)
            isKeyBoardVisible = true;
        else
            isKeyBoardVisible = false;
    }
});

现在你可以在类的任何地方使用isKeyBoardVisible变量来获取键盘是否打开。这对我来说很有效。

注意:当使用InputMethodManager以编程方式打开键盘时,这个过程不起作用,因为它不调用OnFocusChangeListener。

final View activityRootView = findViewById(R.id.rootlayout);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {

            Rect r = new Rect();
            activityRootView.getWindowVisibleDisplayFrame(r);

            int screenHeight = activityRootView.getRootView().getHeight();
            Log.e("screenHeight", String.valueOf(screenHeight));
            int heightDiff = screenHeight - (r.bottom - r.top);
            Log.e("heightDiff", String.valueOf(heightDiff));
            boolean visible = heightDiff > screenHeight / 3;
            Log.e("visible", String.valueOf(visible));
            if (visible) {
                Toast.makeText(LabRegister.this, "I am here 1", Toast.LENGTH_SHORT).show();
            } else {
                Toast.makeText(LabRegister.this, "I am here 2", Toast.LENGTH_SHORT).show();
            }
        }
});