我在Android上构建了一个简单的音乐播放器。每首歌的视图都包含一个SeekBar,实现如下:

public class Song extends Activity implements OnClickListener,Runnable {
    private SeekBar progress;
    private MediaPlayer mp;

    // ...

    private ServiceConnection onService = new ServiceConnection() {
          public void onServiceConnected(ComponentName className,
            IBinder rawBinder) {
              appService = ((MPService.LocalBinder)rawBinder).getService(); // service that handles the MediaPlayer
              progress.setVisibility(SeekBar.VISIBLE);
              progress.setProgress(0);
              mp = appService.getMP();
              appService.playSong(title);
              progress.setMax(mp.getDuration());
              new Thread(Song.this).start();
          }
          public void onServiceDisconnected(ComponentName classname) {
              appService = null;
          }
    };

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.song);

        // ...

        progress = (SeekBar) findViewById(R.id.progress);

        // ...
    }

    public void run() {
    int pos = 0;
    int total = mp.getDuration();
    while (mp != null && pos<total) {
        try {
            Thread.sleep(1000);
            pos = appService.getSongPosition();
        } catch (InterruptedException e) {
            return;
        } catch (Exception e) {
            return;
        }
        progress.setProgress(pos);
    }
}

这很好。现在我想要一个计时器计算秒/分钟的歌曲的进展。所以我把一个TextView在布局,得到它与findViewById()在onCreate(),并把这个在run()后的progress.setProgress(pos):

String time = String.format("%d:%d",
            TimeUnit.MILLISECONDS.toMinutes(pos),
            TimeUnit.MILLISECONDS.toSeconds(pos),
            TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(
                    pos))
            );
currentTime.setText(time);  // currentTime = (TextView) findViewById(R.id.current_time);

但最后一句给了我一个例外:

android.view。只有创建视图层次结构的原始线程才能触及它的视图。

然而,我在这里所做的事情基本上与我在SeekBar中所做的事情相同——在onCreate中创建视图,然后在run()中触摸它——它没有给我这个抱怨。


当前回答

我看到你已经接受了@providence的答案。以防万一,您也可以使用处理程序!首先,处理int字段。

    private static final int SHOW_LOG = 1;
    private static final int HIDE_LOG = 0;

接下来,将处理程序实例作为字段。

    //TODO __________[ Handler ]__________
    @SuppressLint("HandlerLeak")
    protected Handler handler = new Handler()
    {
        @Override
        public void handleMessage(Message msg)
        {
            // Put code here...

            // Set a switch statement to toggle it on or off.
            switch(msg.what)
            {
            case SHOW_LOG:
            {
                ads.setVisibility(View.VISIBLE);
                break;
            }
            case HIDE_LOG:
            {
                ads.setVisibility(View.GONE);
                break;
            }
            }
        }
    };

创建一个方法。

//TODO __________[ Callbacks ]__________
@Override
public void showHandler(boolean show)
{
    handler.sendEmptyMessage(show ? SHOW_LOG : HIDE_LOG);
}

最后,把这个放在onCreate()方法。

showHandler(true);

其他回答

如果你找不到UIThread,你可以用这种方法。

yourcurrentcontext意味着,你需要解析当前上下文

 new Thread(new Runnable() {
        public void run() {
            while (true) {
                (Activity) yourcurrentcontext).runOnUiThread(new Runnable() {
                    public void run() { 
                        Log.d("Thread Log","I am from UI Thread");
                    }
                });
                try {
                    Thread.sleep(1000);
                } catch (Exception ex) {

                }
            }
        }
    }).start();

对于在Kotlin中挣扎的人来说,它是这样工作的:

lateinit var runnable: Runnable //global variable

 runOnUiThread { //Lambda
            runnable = Runnable {

                //do something here

                runDelayedHandler(5000)
            }
        }

        runnable.run()

 //you need to keep the handler outside the runnable body to work in kotlin
 fun runDelayedHandler(timeToWait: Long) {

        //Keep it running
        val handler = Handler()
        handler.postDelayed(runnable, timeToWait)
    }

我通过将runOnUiThread(new Runnable(){..在run ():

thread = new Thread(){
        @Override
        public void run() {
            try {
                synchronized (this) {
                    wait(5000);

                    runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            dbloadingInfo.setVisibility(View.VISIBLE);
                            bar.setVisibility(View.INVISIBLE);
                            loadingText.setVisibility(View.INVISIBLE);
                        }
                    });

                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            Intent mainActivity = new Intent(getApplicationContext(),MainActivity.class);
            startActivity(mainActivity);
        };
    };  
    thread.start();

我也遇到过类似的问题,我的解决方案很难看,但很有效:

void showCode() {
    hideRegisterMessage(); // Hides view 
    final Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            showRegisterMessage(); // Shows view
        }
    }, 3000); // After 3 seconds
}

我也遇到过类似的问题,上面提到的方法对我都不起作用。最后,这对我来说很管用:

Device.BeginInvokeOnMainThread(() =>
    {
        myMethod();
    });

我在这里找到了这块宝石。