iOS

解决方案从接口生成器，设置templateImage参数在keyPath和选择您的色调颜色从IB

extension UIImageView {

// make template image with tint color
var templateImage: Bool {
    set {
        if newValue, let image = self.image {
            let newImage = image.withRenderingMode(.alwaysTemplate)
            self.image = newImage
        }
    } get {
        return false
    }
}

}

如果您有SVG图像的任何id，您可以根据id填充颜色。

    let image = SVGKImage(named: "iconName")
    let svgIMGV = SVGKFastImageView(frame: self.imgView.frame)
         svgIMGV.image = image
          svgIMGV.fillTintColor(colorImage: UIColor.red, iconID: "Bank")

// Add in extension SVGKImageView
extension SVGKImageView {
 func fillTintColor(colorImage: UIColor, iconID: String) {
        if self.image != nil && self.image.caLayerTree != nil {
            print(self.image.caLayerTree.sublayers)
            guard let sublayers = self.image.caLayerTree.sublayers else { return }
            fillRecursively(sublayers: sublayers, color: colorImage, iconID: iconID)
        }
    }

     private func fillRecursively(sublayers: [CALayer], color: UIColor, iconID: String, hasFoundLayer: Bool) {
        var isLayerFound = false
        for layer in sublayers {
            if let l = layer as? CAShapeLayer {

                print(l.name)                
                //IF you want to color the specific shapelayer by id else remove the l.name  == "myID"  validation
                if let name =  l.name,  hasFoundLayer == true && name == "myID" {
                    self.colorThatImageWIthColor(color: color, layer: l)
                    print("Colouring FInished")
                }
            } else {
                if layer.name == iconID {
                    if let innerSublayer = layer.sublayers as? [CAShapeLayer] {
                        fillRecursively(sublayers: innerSublayer, color: color, iconID: iconID, hasFoundLayer: true )
                        print("FOund")
                    }
                } else {
                    if let l = layer as? CALayer, let sub = l.sublayers {
                        fillRecursively(sublayers: sub, color: color, iconID: iconID, hasFoundLayer: false)
                    }
                }
            }

        }
    }

    func colorThatImageWIthColor(color: UIColor, layer: CAShapeLayer) {
        if layer.strokeColor != nil {
            layer.strokeColor = color.cgColor
        }
        if layer.fillColor != nil {
            layer.fillColor = color.cgColor
        }
    }

}

或者签出这个例子。

https://github.com/ravisfortune/SVGDEMO

用于着色UIButton的图像

let image1 = "ic_shopping_cart_empty"
btn_Basket.setImage(UIImage(named: image1)?.withRenderingMode(.alwaysTemplate), for: .normal)
btn_Basket.setImage(UIImage(named: image1)?.withRenderingMode(.alwaysTemplate), for: .selected)
btn_Basket.imageView?.tintColor = UIColor(UIColor.Red)

profileImageView。image = theImageView.image!.withRenderingMode(.alwaysTemplate) profileImageView。tintColor = uiccolor .green

OR

首先在图像资产中选择特定图像，然后选择红色作为模板而不是默认，然后写行。 profileImageView。tintColor = uiccolor .green

这里有一个类别应该可以做到这一点

@interface UIImage(Overlay)
@end

@implementation UIImage(Overlay)

- (UIImage *)imageWithColor:(UIColor *)color1
{
        UIGraphicsBeginImageContextWithOptions(self.size, NO, self.scale);
        CGContextRef context = UIGraphicsGetCurrentContext();
        CGContextTranslateCTM(context, 0, self.size.height);
        CGContextScaleCTM(context, 1.0, -1.0);
        CGContextSetBlendMode(context, kCGBlendModeNormal);
        CGRect rect = CGRectMake(0, 0, self.size.width, self.size.height);
        CGContextClipToMask(context, rect, self.CGImage);
        [color1 setFill];
        CGContextFillRect(context, rect);
        UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
        UIGraphicsEndImageContext();
        return newImage;
}
@end

所以你会这样做:

theImageView.image = [theImageView.image imageWithColor:[UIColor redColor]];

iOS 对于iOS应用程序，在Swift 3,4或5中:

theImageView.image = theImageView.image?.withRenderingMode(.alwaysTemplate)
theImageView.tintColor = UIColor.red

对于Swift 2:

theImageView.image = theImageView.image?.imageWithRenderingMode(UIImageRenderingMode.AlwaysTemplate)
theImageView.tintColor = UIColor.redColor()

同时，现代的Objective-C解决方案是:

theImageView.image = [theImageView.image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];
[theImageView setTintColor:[UIColor redColor]];

Watchkit 在Apple Watch应用程序的WatchKit中，您可以为模板图像设置色调颜色。

您必须将图像添加到WatchKit应用程序中的资产目录，并将图像集设置为在属性检查器中呈现为模板图像。与iPhone应用程序不同，您目前不能在WatchKit扩展的代码中设置模板渲染。 设置该图像用于你的WKInterfaceImage在界面生成器为你的应用程序 创建一个IBOutlet在你的WKInterfaceController为WKInterfaceImage称为“theImage”…

然后在Swift 3或4中设置色调颜色:

theImage.setTintColor(UIColor.red)

斯威夫特2:

theImage.setTintColor(UIColor.redColor())

然后在Objective-C中设置色调颜色:

[self.theImage setTintColor:[UIColor redColor]];

如果您使用模板图像并且没有应用着色颜色，则将应用WatchKit应用程序的全局着色。如果你没有设置全局色调，当作为模板图像使用时，图像将默认为浅蓝色。