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2023-10-28 10:00:05

如何从使用经纬度坐标的位置获得时区?

给定一个位置的经度和纬度，如何知道该位置的有效时区?

在大多数情况下，我们正在寻找IANA/Olson时区id，尽管有些服务可能只返回UTC偏移量或其他一些时区标识符。详细信息请阅读时区标签信息。

当前回答

https://en.wikipedia.org/wiki/Great-circle_distance

下面是一个使用JSON数据的很好的实现: https://github.com/agap/llttz

public TimeZone nearestTimeZone(Location node) {
    double bestDistance = Double.MAX_VALUE;
    Location bestGuess = timeZones.get(0);

    for (Location current : timeZones.subList(1, timeZones.size())) {
        double newDistance = distanceInKilometers(node, current);

        if (newDistance < bestDistance) {
            bestDistance = newDistance;
            bestGuess = current;
        }
    }

    return java.util.TimeZone.getTimeZone(bestGuess.getZone());
}

  protected double distanceInKilometers(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double meridianLength = 111.1;
        return meridianLength * centralAngle(latFrom, lonFrom, latTo, lonTo);
    }

    protected double centralAngle(final Location from, final Location to) {
        return centralAngle(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }

    protected double centralAngle(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double latFromRad = toRadians(latFrom),
                lonFromRad = toRadians(lonFrom),
                latToRad   = toRadians(latTo),
                lonToRad   = toRadians(lonTo);

        final double centralAngle = toDegrees(acos(sin(latFromRad) * sin(latToRad) + cos(latFromRad) * cos(latToRad) * cos(lonToRad - lonFromRad)));

        return centralAngle <= 180.0 ? centralAngle : (360.0 - centralAngle);
    }

    protected double distanceInKilometers(final Location from, final Location to) {
        return distanceInKilometers(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }
}
2015-08-19 10:44:07

其他回答

下面是如何使用谷歌的脚本编辑器来获取gsheet中的timezoneName和timeZoneId。

步骤1。获取谷歌的时区API的API键

步骤2。创建一个新的gsheet。在“工具”菜单下单击“脚本编辑器”。添加如下代码:

function getTimezone(lat, long) {  
  var apiKey = 'INSERTAPIKEYHERE'
  var url = 'https://maps.googleapis.com/maps/api/timezone/json?location=' + lat + ',' + long + '&timestamp=1331161200&key=' + apiKey 
  var response = UrlFetchApp.fetch(url);
  var data = JSON.parse(response.getContentText());
  return data["timeZoneName"];
}

步骤3。保存并发布getTimezone()函数，并如上图所示使用它。

2017-12-08 16:34:35

你可以使用geolocator.js轻松获得时区和更多…

它使用需要密钥的谷歌api。首先你配置geolocator

geolocator.config({
    language: "en",
    google: {
        version: "3",
        key: "YOUR-GOOGLE-API-KEY"
    }
});

获取TimeZone，如果你有坐标:

geolocator.getTimeZone(options, function (err, timezone) {
    console.log(err || timezone);
});

示例输出:

{
    id: "Europe/Paris",
    name: "Central European Standard Time",
    abbr: "CEST",
    dstOffset: 0,
    rawOffset: 3600,
    timestamp: 1455733120
}

定位，然后获得时区和更多

如果没有坐标，可以先定位用户位置。

下面的例子将首先尝试HTML5 Geolocation API来获取坐标。如果失败或被拒绝，它将通过Geo-IP查找获得坐标。最后，它将获得时区和更多…

var options = {
    enableHighAccuracy: true,
    timeout: 6000,
    maximumAge: 0,
    desiredAccuracy: 30,
    fallbackToIP: true, // if HTML5 fails or rejected
    addressLookup: true, // this will get full address information
    timezone: true,
    map: "my-map" // this will even create a map for you
};
geolocator.locate(options, function (err, location) {
    console.log(err || location);
});

示例输出:

{
    coords: {
        latitude: 37.4224764,
        longitude: -122.0842499,
        accuracy: 30,
        altitude: null,
        altitudeAccuracy: null,
        heading: null,
        speed: null
    },
    address: {
        commonName: "",
        street: "Amphitheatre Pkwy",
        route: "Amphitheatre Pkwy",
        streetNumber: "1600",
        neighborhood: "",
        town: "",
        city: "Mountain View",
        region: "Santa Clara County",
        state: "California",
        stateCode: "CA",
        postalCode: "94043",
        country: "United States",
        countryCode: "US"
    },
    formattedAddress: "1600 Amphitheatre Parkway, Mountain View, CA 94043, USA",
    type: "ROOFTOP",
    placeId: "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
    timezone: {
        id: "America/Los_Angeles",
        name: "Pacific Standard Time",
        abbr: "PST",
        dstOffset: 0,
        rawOffset: -28800
    },
    flag: "//cdnjs.cloudflare.com/ajax/libs/flag-icon-css/2.3.1/flags/4x3/us.svg",
    map: {
        element: HTMLElement,
        instance: Object, // google.maps.Map
        marker: Object, // google.maps.Marker
        infoWindow: Object, // google.maps.InfoWindow
        options: Object // map options
    },
    timestamp: 1456795956380
}
2016-07-01 23:51:10

从古比鱼:

import geocoders
g = geocoders.GoogleV3()
place, (lat, lng) = g.geocode('Fairbanks')
print place, (lat, lng)
Fairbanks, AK, USA (64.8377778, -147.7163889)
timezone = g.timezone((lat, lng))
print timezone.dst

美国/安克雷奇。DstTzInfo的dst

美国/主播LMT-1天，STD 1400:00

2016-02-10 23:57:42

我写了一个包https://github.com/ringsaturn/tzf支持获取时区在Go&Python和非常快:

package main

import (
    "fmt"

    "github.com/ringsaturn/tzf"
)

func main() {
    finder, err := tzf.NewDefaultFinder()
    if err != nil {
        panic(err)
    }
    fmt.Println(finder.GetTimezoneName(116.6386, 40.0786))
}

Python https://github.com/ringsaturn/tzfpy sample:

from tzfpy import get_tz

print(get_tz(121.4737, 31.2305))

Rust https://github.com/ringsaturn/tzf-rs样品:

use tzf_rs::DefaultFinder;

fn main() {
    let finder = DefaultFinder::new();

    print!("{:?}\n", DefaultFinder.get_tz_name(116.3883, 39.9289));
}
2022-11-12 14:50:19

https://en.wikipedia.org/wiki/Great-circle_distance

下面是一个使用JSON数据的很好的实现: https://github.com/agap/llttz

public TimeZone nearestTimeZone(Location node) {
    double bestDistance = Double.MAX_VALUE;
    Location bestGuess = timeZones.get(0);

    for (Location current : timeZones.subList(1, timeZones.size())) {
        double newDistance = distanceInKilometers(node, current);

        if (newDistance < bestDistance) {
            bestDistance = newDistance;
            bestGuess = current;
        }
    }

    return java.util.TimeZone.getTimeZone(bestGuess.getZone());
}

  protected double distanceInKilometers(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double meridianLength = 111.1;
        return meridianLength * centralAngle(latFrom, lonFrom, latTo, lonTo);
    }

    protected double centralAngle(final Location from, final Location to) {
        return centralAngle(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }

    protected double centralAngle(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double latFromRad = toRadians(latFrom),
                lonFromRad = toRadians(lonFrom),
                latToRad   = toRadians(latTo),
                lonToRad   = toRadians(lonTo);

        final double centralAngle = toDegrees(acos(sin(latFromRad) * sin(latToRad) + cos(latFromRad) * cos(latToRad) * cos(lonToRad - lonFromRad)));

        return centralAngle <= 180.0 ? centralAngle : (360.0 - centralAngle);
    }

    protected double distanceInKilometers(final Location from, final Location to) {
        return distanceInKilometers(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }
}
2015-08-19 10:44:07

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