如何从使用经纬度坐标的位置获得时区?

给定一个位置的经度和纬度，如何知道该位置的有效时区?

在大多数情况下，我们正在寻找IANA/Olson时区id，尽管有些服务可能只返回UTC偏移量或其他一些时区标识符。详细信息请阅读时区标签信息。

当前回答

2019-12-02 05:23:19

其他回答

你可以使用geolocator.js轻松获得时区和更多…

它使用需要密钥的谷歌api。首先你配置geolocator

geolocator.config({
    language: "en",
    google: {
        version: "3",
        key: "YOUR-GOOGLE-API-KEY"
    }
});

获取TimeZone，如果你有坐标:

geolocator.getTimeZone(options, function (err, timezone) {
    console.log(err || timezone);
});

示例输出:

{
    id: "Europe/Paris",
    name: "Central European Standard Time",
    abbr: "CEST",
    dstOffset: 0,
    rawOffset: 3600,
    timestamp: 1455733120
}

定位，然后获得时区和更多

如果没有坐标，可以先定位用户位置。

下面的例子将首先尝试HTML5 Geolocation API来获取坐标。如果失败或被拒绝，它将通过Geo-IP查找获得坐标。最后，它将获得时区和更多…

var options = {
    enableHighAccuracy: true,
    timeout: 6000,
    maximumAge: 0,
    desiredAccuracy: 30,
    fallbackToIP: true, // if HTML5 fails or rejected
    addressLookup: true, // this will get full address information
    timezone: true,
    map: "my-map" // this will even create a map for you
};
geolocator.locate(options, function (err, location) {
    console.log(err || location);
});

示例输出:

{
    coords: {
        latitude: 37.4224764,
        longitude: -122.0842499,
        accuracy: 30,
        altitude: null,
        altitudeAccuracy: null,
        heading: null,
        speed: null
    },
    address: {
        commonName: "",
        street: "Amphitheatre Pkwy",
        route: "Amphitheatre Pkwy",
        streetNumber: "1600",
        neighborhood: "",
        town: "",
        city: "Mountain View",
        region: "Santa Clara County",
        state: "California",
        stateCode: "CA",
        postalCode: "94043",
        country: "United States",
        countryCode: "US"
    },
    formattedAddress: "1600 Amphitheatre Parkway, Mountain View, CA 94043, USA",
    type: "ROOFTOP",
    placeId: "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
    timezone: {
        id: "America/Los_Angeles",
        name: "Pacific Standard Time",
        abbr: "PST",
        dstOffset: 0,
        rawOffset: -28800
    },
    flag: "//cdnjs.cloudflare.com/ajax/libs/flag-icon-css/2.3.1/flags/4x3/us.svg",
    map: {
        element: HTMLElement,
        instance: Object, // google.maps.Map
        marker: Object, // google.maps.Marker
        infoWindow: Object, // google.maps.InfoWindow
        options: Object // map options
    },
    timestamp: 1456795956380
}

2016-07-01 23:51:10

我们在Teleport刚刚开始开放我们的API，其中一个用例也是为坐标公开TZ信息。

例如，可以通过以下方式请求我们所有可用的TZ信息的坐标:

curl -s https://api.teleport.org/api/locations/59.4372,24.7453/?embed=location:nearest-cities/location:nearest-city/city:timezone/tz:offsets-now | jq '._embedded."location:nearest-cities"[0]._embedded."location:nearest-city"._embedded."city:timezone"'

这将返回以下内容

{
  "_embedded": {
    "tz:offsets-now": {
      "_links": {
        "self": {
          "href": "https://api.teleport.org/api/timezones/iana:Europe%2FTallinn/offsets/?date=2015-09-07T11%3A20%3A09Z"
        }
      },
      "base_offset_min": 120,
      "dst_offset_min": 60,
      "end_time": "2015-10-25T01:00:00Z",
      "short_name": "EEST",
      "total_offset_min": 180,
      "transition_time": "2015-03-29T01:00:00Z"
    }
  },
  "_links": {
    "self": {
      "href": "https://api.teleport.org/api/timezones/iana:Europe%2FTallinn/"
    },
    "tz:offsets": {
      "href": "https://api.teleport.org/api/timezones/iana:Europe%2FTallinn/offsets/{?date}",
      "templated": true
    },
    "tz:offsets-now": {
      "href": "https://api.teleport.org/api/timezones/iana:Europe%2FTallinn/offsets/?date=2015-09-07T11%3A20%3A09Z"
    }
  },
  "iana_name": "Europe/Tallinn"
}

在本例中，我使用./jq进行JSON解析。

2015-09-07 11:24:14

https://en.wikipedia.org/wiki/Great-circle_distance

下面是一个使用JSON数据的很好的实现: https://github.com/agap/llttz

public TimeZone nearestTimeZone(Location node) {
    double bestDistance = Double.MAX_VALUE;
    Location bestGuess = timeZones.get(0);

    for (Location current : timeZones.subList(1, timeZones.size())) {
        double newDistance = distanceInKilometers(node, current);

        if (newDistance < bestDistance) {
            bestDistance = newDistance;
            bestGuess = current;
        }
    }

    return java.util.TimeZone.getTimeZone(bestGuess.getZone());
}

  protected double distanceInKilometers(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double meridianLength = 111.1;
        return meridianLength * centralAngle(latFrom, lonFrom, latTo, lonTo);
    }

    protected double centralAngle(final Location from, final Location to) {
        return centralAngle(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }

    protected double centralAngle(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double latFromRad = toRadians(latFrom),
                lonFromRad = toRadians(lonFrom),
                latToRad   = toRadians(latTo),
                lonToRad   = toRadians(lonTo);

        final double centralAngle = toDegrees(acos(sin(latFromRad) * sin(latToRad) + cos(latFromRad) * cos(latToRad) * cos(lonToRad - lonFromRad)));

        return centralAngle <= 180.0 ? centralAngle : (360.0 - centralAngle);
    }

    protected double distanceInKilometers(final Location from, final Location to) {
        return distanceInKilometers(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }
}

2015-08-19 10:44:07

我写了一个包https://github.com/ringsaturn/tzf支持获取时区在Go&Python和非常快:

package main

import (
    "fmt"

    "github.com/ringsaturn/tzf"
)

func main() {
    finder, err := tzf.NewDefaultFinder()
    if err != nil {
        panic(err)
    }
    fmt.Println(finder.GetTimezoneName(116.6386, 40.0786))
}

Python https://github.com/ringsaturn/tzfpy sample:

from tzfpy import get_tz

print(get_tz(121.4737, 31.2305))

Rust https://github.com/ringsaturn/tzf-rs样品:

use tzf_rs::DefaultFinder;

fn main() {
    let finder = DefaultFinder::new();

    print!("{:?}\n", DefaultFinder.get_tz_name(116.3883, 39.9289));
}

2022-11-12 14:50:19

对于我们这些使用Javascript并希望通过谷歌api从邮政编码获取时区的人来说，这里有一个方法。

通过地理定位获取lat/lng 通过这个参数获取时区进入时区API。此处使用Luxon进行时区转换。

注意:我的理解是，邮政编码在不同的国家并不是唯一的，所以这可能最适合在美国使用。

const googleMapsClient; // instantiate your client here
const zipcode = '90210'
const myDateThatNeedsTZAdjustment; // define your date that needs adjusting
// fetch lat/lng from google api by zipcode
const geocodeResponse = await googleMapsClient.geocode({ address: zipcode }).asPromise();
if (geocodeResponse.json.status === 'OK') {
  lat = geocodeResponse.json.results[0].geometry.location.lat;
  lng = geocodeResponse.json.results[0].geometry.location.lng;
} else {
  console.log('Geocode was not successful for the following reason: ' + status);
}

// prepare lat/lng and timestamp of profile created_at to fetch time zone
const location = `${lat},${lng}`;
const timestamp = new Date().valueOf() / 1000;
const timezoneResponse = await googleMapsClient
  .timezone({ location: location, timestamp: timestamp })
  .asPromise();

const timeZoneId = timezoneResponse.json.timeZoneId;
// adjust by setting timezone
const timezoneAdjustedDate = DateTime.fromJSDate(
  myDateThatNeedsTZAdjustment
).setZone(timeZoneId);

2020-05-14 15:33:38

如何从使用经纬度坐标的位置获得时区?

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