如何从使用经纬度坐标的位置获得时区?

给定一个位置的经度和纬度，如何知道该位置的有效时区?

在大多数情况下，我们正在寻找IANA/Olson时区id，尽管有些服务可能只返回UTC偏移量或其他一些时区标识符。详细信息请阅读时区标签信息。

当前回答

披露:我是下面描述的docker-image的作者

我将https://github.com/evansiroky/node-geo-tz包装在一个非常简单的docker-container中

https://hub.docker.com/repository/docker/tobias74/timezone-lookup

您可以启动docker容器

docker run -p 80:3000 tobias74/timezone-lookup:latest

这将公开端口3000上的本地主机上的查找服务。然后可以执行时区查找

curl "localhost:3000/timezone?latitude=12&longitude=34"

2020-06-18 12:41:47

其他回答

2019-12-02 05:23:19

如果你不想使用web服务，你可以像这样从浏览器中检索信息:

var d = new Date();
var usertime = d.toLocaleString();

//some browsers / OSs provide the timezone name in their local string
var tzsregex = /\b(ACDT|ACST|ACT|ADT|AEDT|AEST|AFT|AKDT|AKST|AMST|AMT|ART|AST|AWDT|AWST|AZOST|AZT|BDT|BIOT|BIT|BOT|BRT|BST|BTT|CAT|CCT|CDT|CEDT|CEST|CET|CHADT|CHAST|CIST|CKT|CLST|CLT|COST|COT|CST|CT|CVT|CXT|CHST|DFT|EAST|EAT|ECT|EDT|EEDT|EEST|EET|EST|FJT|FKST|FKT|GALT|GET|GFT|GILT|GIT|GMT|GST|GYT|HADT|HAEC|HAST|HKT|HMT|HST|ICT|IDT|IRKT|IRST|IST|JST|KRAT|KST|LHST|LINT|MART|MAGT|MDT|MET|MEST|MIT|MSD|MSK|MST|MUT|MYT|NDT|NFT|NPT|NST|NT|NZDT|NZST|OMST|PDT|PETT|PHOT|PKT|PST|RET|SAMT|SAST|SBT|SCT|SGT|SLT|SST|TAHT|THA|UYST|UYT|VET|VLAT|WAT|WEDT|WEST|WET|WST|YAKT|YEKT)\b/gi;

//in other browsers the timezone needs to be estimated based on the offset
var timezonenames = {"UTC+0":"GMT","UTC+1":"CET","UTC+2":"EET","UTC+3":"EEDT","UTC+3.5":"IRST","UTC+4":"MSD","UTC+4.5":"AFT","UTC+5":"PKT","UTC+5.5":"IST","UTC+6":"BST","UTC+6.5":"MST","UTC+7":"THA","UTC+8":"AWST","UTC+9":"AWDT","UTC+9.5":"ACST","UTC+10":"AEST","UTC+10.5":"ACDT","UTC+11":"AEDT","UTC+11.5":"NFT","UTC+12":"NZST","UTC-1":"AZOST","UTC-2":"GST","UTC-3":"BRT","UTC-3.5":"NST","UTC-4":"CLT","UTC-4.5":"VET","UTC-5":"EST","UTC-6":"CST","UTC-7":"MST","UTC-8":"PST","UTC-9":"AKST","UTC-9.5":"MIT","UTC-10":"HST","UTC-11":"SST","UTC-12":"BIT"};

var timezone = usertime.match(tzsregex);
if (timezone) {
    timezone = timezone[timezone.length-1];
} else {
    var offset = -1*d.getTimezoneOffset()/60;
    offset = "UTC" + (offset >= 0 ? "+" + offset : offset);
    timezone = timezonenames[offset];
}

//there are 3 variables can use to see the timezone
// usertime - full date
// offset - UTC offset time
// timezone - country

console.log('Full Date: ' + usertime);
console.log('UTC Offset: ' + offset);
console.log('Country Code Timezone: ' + timezone);

在我目前的情况下，它是打印:

日期:“27”/“01”/“2014”:“16”:“53”:“37” UTC偏移量:UTC-3 国家代码时区:BRT

希望对大家有所帮助。

2014-01-27 19:56:28

https://en.wikipedia.org/wiki/Great-circle_distance

下面是一个使用JSON数据的很好的实现: https://github.com/agap/llttz

public TimeZone nearestTimeZone(Location node) {
    double bestDistance = Double.MAX_VALUE;
    Location bestGuess = timeZones.get(0);

    for (Location current : timeZones.subList(1, timeZones.size())) {
        double newDistance = distanceInKilometers(node, current);

        if (newDistance < bestDistance) {
            bestDistance = newDistance;
            bestGuess = current;
        }
    }

    return java.util.TimeZone.getTimeZone(bestGuess.getZone());
}

  protected double distanceInKilometers(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double meridianLength = 111.1;
        return meridianLength * centralAngle(latFrom, lonFrom, latTo, lonTo);
    }

    protected double centralAngle(final Location from, final Location to) {
        return centralAngle(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }

    protected double centralAngle(final double latFrom, final double lonFrom, final double latTo, final double lonTo) {
        final double latFromRad = toRadians(latFrom),
                lonFromRad = toRadians(lonFrom),
                latToRad   = toRadians(latTo),
                lonToRad   = toRadians(lonTo);

        final double centralAngle = toDegrees(acos(sin(latFromRad) * sin(latToRad) + cos(latFromRad) * cos(latToRad) * cos(lonToRad - lonFromRad)));

        return centralAngle <= 180.0 ? centralAngle : (360.0 - centralAngle);
    }

    protected double distanceInKilometers(final Location from, final Location to) {
        return distanceInKilometers(from.getLatitude(), from.getLongitude(), to.getLatitude(), to.getLongitude());
    }
}

2015-08-19 10:44:07

好的，这是没有正确NTP时间的短版本:

String get_xml_server_reponse(String server_url){

URL xml_server = null;

String xmltext = "";

InputStream input;


try {
    xml_server = new URL(server_url);


    try {
        input = xml_server.openConnection().getInputStream();


        final BufferedReader reader = new BufferedReader(new InputStreamReader(input));
        final StringBuilder sBuf = new StringBuilder();

        String line = null;
        try {
            while ((line = reader.readLine()) != null) 
            {
                sBuf.append(line);
            }
           } 
        catch (IOException e) 
          {
                Log.e(e.getMessage(), "XML parser, stream2string 1");
          } 
        finally {
            try {
                input.close();
                }
            catch (IOException e) 
            {
                Log.e(e.getMessage(), "XML parser, stream2string 2");
            }
        }

        xmltext =  sBuf.toString();

    } catch (IOException e1) {

            e1.printStackTrace();
        }


    } catch (MalformedURLException e1) {

      e1.printStackTrace();
    }

 return  xmltext;

} 


long get_time_zone_time_l(GeoPoint gp){


        String raw_offset = "";
        String dst_offset = "";

        double Longitude = gp.getLongitudeE6()/1E6;
        double Latitude = gp.getLatitudeE6()/1E6;

        long tsLong = System.currentTimeMillis()/1000;


        if (tsLong != 0)
        {

        // https://maps.googleapis.com/maps/api/timezone/xml?location=39.6034810,-119.6822510&timestamp=1331161200&sensor=false

        String request = "https://maps.googleapis.com/maps/api/timezone/xml?location="+Latitude+","+ Longitude+ "&timestamp="+tsLong +"&sensor=false";

        String xmltext = get_xml_server_reponse(request);

        if(xmltext.compareTo("")!= 0)
        {

         int startpos = xmltext.indexOf("<TimeZoneResponse");
         xmltext = xmltext.substring(startpos);



        XmlPullParser parser;
        try {
            parser = XmlPullParserFactory.newInstance().newPullParser();


             parser.setInput(new StringReader (xmltext));

             int eventType = parser.getEventType();  

             String tagName = "";


             while(eventType != XmlPullParser.END_DOCUMENT) {
                 switch(eventType) {

                     case XmlPullParser.START_TAG:

                           tagName = parser.getName();

                         break;


                     case XmlPullParser.TEXT :


                        if  (tagName.equalsIgnoreCase("raw_offset"))
                          if(raw_offset.compareTo("")== 0)                               
                            raw_offset = parser.getText();  

                        if  (tagName.equalsIgnoreCase("dst_offset"))
                          if(dst_offset.compareTo("")== 0)
                            dst_offset = parser.getText();  


                        break;   

                 }

                 try {
                        eventType = parser.next();
                    } catch (IOException e) {

                        e.printStackTrace();
                    }

                }

                } catch (XmlPullParserException e) {

                    e.printStackTrace();
                    erg += e.toString();
                }

        }      

        int ro = 0;
        if(raw_offset.compareTo("")!= 0)
        { 
            float rof = str_to_float(raw_offset);
            ro = (int)rof;
        }

        int dof = 0;
        if(dst_offset.compareTo("")!= 0)
        { 
            float doff = str_to_float(dst_offset);
            dof = (int)doff;
        }

        tsLong = (tsLong + ro + dof) * 1000;


        }


  return tsLong;

}

并将其用于:

GeoPoint gp = new GeoPoint(39.6034810,-119.6822510);
long Current_TimeZone_Time_l = get_time_zone_time_l(gp);

2013-11-05 17:23:39

对于我们这些使用Javascript并希望通过谷歌api从邮政编码获取时区的人来说，这里有一个方法。

通过地理定位获取lat/lng 通过这个参数获取时区进入时区API。此处使用Luxon进行时区转换。

注意:我的理解是，邮政编码在不同的国家并不是唯一的，所以这可能最适合在美国使用。

const googleMapsClient; // instantiate your client here
const zipcode = '90210'
const myDateThatNeedsTZAdjustment; // define your date that needs adjusting
// fetch lat/lng from google api by zipcode
const geocodeResponse = await googleMapsClient.geocode({ address: zipcode }).asPromise();
if (geocodeResponse.json.status === 'OK') {
  lat = geocodeResponse.json.results[0].geometry.location.lat;
  lng = geocodeResponse.json.results[0].geometry.location.lng;
} else {
  console.log('Geocode was not successful for the following reason: ' + status);
}

// prepare lat/lng and timestamp of profile created_at to fetch time zone
const location = `${lat},${lng}`;
const timestamp = new Date().valueOf() / 1000;
const timezoneResponse = await googleMapsClient
  .timezone({ location: location, timestamp: timestamp })
  .asPromise();

const timeZoneId = timezoneResponse.json.timeZoneId;
// adjust by setting timezone
const timezoneAdjustedDate = DateTime.fromJSDate(
  myDateThatNeedsTZAdjustment
).setZone(timeZoneId);

2020-05-14 15:33:38

如何从使用经纬度坐标的位置获得时区?

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