2024-11-15 10:00:05

什么是栈展开?

什么是栈展开?搜索了一遍,但没有找到有启发性的答案!


当前回答

在一般意义上,堆栈“unwind”几乎等同于函数调用的结束和随后的堆栈弹出。

然而,特别是在c++的情况下,堆栈展开必须与c++如何调用自任何代码块开始分配的对象的析构函数有关。在块中创建的对象将按照其分配的相反顺序被释放。

其他回答

我不知道你是否读过这篇文章,但维基百科关于调用堆栈的文章有一个很好的解释。

解除:

Returning from the called function will pop the top frame off of the stack, perhaps leaving a return value. The more general act of popping one or more frames off the stack to resume execution elsewhere in the program is called stack unwinding and must be performed when non-local control structures are used, such as those used for exception handling. In this case, the stack frame of a function contains one or more entries specifying exception handlers. When an exception is thrown, the stack is unwound until a handler is found that is prepared to handle (catch) the type of the thrown exception. Some languages have other control structures that require general unwinding. Pascal allows a global goto statement to transfer control out of a nested function and into a previously invoked outer function. This operation requires the stack to be unwound, removing as many stack frames as necessary to restore the proper context to transfer control to the target statement within the enclosing outer function. Similarly, C has the setjmp and longjmp functions that act as non-local gotos. Common Lisp allows control of what happens when the stack is unwound by using the unwind-protect special operator. When applying a continuation, the stack is (logically) unwound and then rewound with the stack of the continuation. This is not the only way to implement continuations; for example, using multiple, explicit stacks, application of a continuation can simply activate its stack and wind a value to be passed. The Scheme programming language allows arbitrary thunks to be executed in specified points on "unwinding" or "rewinding" of the control stack when a continuation is invoked.

检查[编辑]

堆栈展开主要是c++的概念,处理当堆栈分配的对象的作用域退出时(正常退出或通过异常退出)如何销毁。

假设你有这样一段代码:

void hw() {
    string hello("Hello, ");
    string world("world!\n");
    cout << hello << world;
} // at this point, "world" is destroyed, followed by "hello"

所有这些都与c++有关:

定义: 当您静态地创建对象(在堆栈上而不是在堆内存中分配对象)并执行函数调用时,它们是“堆叠起来的”。

当一个作用域(由{和}分隔的任何内容)退出(通过使用return XXX;,到达作用域的末尾或抛出异常)时,该作用域内的所有内容都被销毁(对所有内容调用析构函数)。这个销毁局部对象并调用析构函数的过程称为堆栈展开。

您有以下与堆栈展开相关的问题:

avoiding memory leaks (anything dynamically allocated that is not managed by a local object and cleaned up in the destructor will be leaked) - see RAII referred to by Nikolai, and the documentation for boost::scoped_ptr or this example of using boost::mutex::scoped_lock. program consistency: the C++ specifications state that you should never throw an exception before any existing exception has been handled. This means that the stack unwinding process should never throw an exception (either use only code guaranteed not to throw in destructors, or surround everything in destructors with try { and } catch(...) {}).

如果任何析构函数在堆栈展开过程中抛出异常,那么就会出现未定义的行为,这可能导致程序意外终止(最常见的行为)或整个宇宙结束(理论上是可能的,但在实践中尚未观察到)。

堆栈展开通常与异常处理有关。这里有一个例子:

void func( int x )
{
    char* pleak = new char[1024]; // might be lost => memory leak
    std::string s( "hello world" ); // will be properly destructed

    if ( x ) throw std::runtime_error( "boom" );

    delete [] pleak; // will only get here if x == 0. if x!=0, throw exception
}

int main()
{
    try
    {
        func( 10 );
    }
    catch ( const std::exception& e )
    {
        return 1;
    }

    return 0;
}

在这里,如果抛出异常,分配给pleak的内存将丢失,而分配给s的内存将在任何情况下通过std::string析构函数正确释放。当退出作用域时,在堆栈上分配的对象将被“解开”(这里的作用域是函数func的作用域)。这是通过编译器插入对自动(堆栈)变量析构函数的调用来完成的。

现在,这是一个非常强大的概念,导致称为RAII的技术,即资源获取即初始化,它帮助我们在c++中管理内存、数据库连接、打开的文件描述符等资源。

现在这允许我们提供异常安全保证。

在我看来,本文中给出的下图漂亮地解释了堆栈unwind对下一条指令路径的影响(一旦抛出未捕获的异常,将执行):

在图片中:

上面一个是正常的调用执行(没有抛出异常)。 当抛出异常时,位于底部。

在第二种情况下,当发生异常时,将在函数调用堆栈中线性搜索异常处理程序。搜索结束于带有异常处理程序的函数,即带有try-catch块的main(),但不是在从函数调用堆栈中删除它之前的所有条目之前。