在IB的库中,介绍告诉我们,当按下返回键时,UITextView的键盘将消失。但实际上返回键只能作为'\n'
我可以添加一个按钮,并使用[txtView resignFirstResponder]隐藏键盘。
但是有没有办法为键盘中的返回键添加动作,这样我就不需要添加UIButton了?
在IB的库中,介绍告诉我们,当按下返回键时,UITextView的键盘将消失。但实际上返回键只能作为'\n'
我可以添加一个按钮,并使用[txtView resignFirstResponder]隐藏键盘。
但是有没有办法为键盘中的返回键添加动作,这样我就不需要添加UIButton了?
当前回答
就像matt对samvermette的评论一样,我也不喜欢检测“\n”的想法。返回键在UITextView中是有原因的,当然是去下一行。
在我看来,最好的解决方案是模仿iPhone的消息应用程序-这是在键盘上添加工具栏(和按钮)。
我从以下博客文章中得到了代码:
http://www.iosdevnotes.com/2011/02/iphone-keyboard-toolbar/
步骤:
-添加工具栏到你的XIB文件-设置高度为460
-添加工具栏按钮项(如果尚未添加)。如果需要右对齐,还可以将灵活的工具栏按钮项添加到XIB,并移动工具栏按钮项
-创建将按钮项目链接到resignFirstResponder的动作,如下所示:
- (IBAction)hideKeyboard:(id)sender {
[yourUITextView resignFirstResponder];
}
套:
- (void)viewWillAppear:(BOOL)animated {
[super viewWillAppear:animated];
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(keyboardWillShow:) name:UIKeyboardWillShowNotification object:nil];
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(keyboardWillHide:) name:UIKeyboardWillHideNotification object:nil];
}
- (void)viewWillDisappear:(BOOL)animated {
[super viewWillDisappear:animated];
[[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillShowNotification object:nil];
[[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillHideNotification object:nil];
}
- (void)keyboardWillShow:(NSNotification *)notification {
[UIView beginAnimations:nil context:NULL];
[UIView setAnimationDuration:0.3];
CGRect frame = self.keyboardToolbar.frame;
frame.origin.y = self.view.frame.size.height - 260.0;
self.keyboardToolbar.frame = frame;
[UIView commitAnimations];
}
- (void)keyboardWillHide:(NSNotification *)notification {
[UIView beginAnimations:nil context:NULL];
[UIView setAnimationDuration:0.3];
CGRect frame = self.keyboardToolbar.frame;
frame.origin.y = self.view.frame.size.height;
self.keyboardToolbar.frame = frame;
[UIView commitAnimations];
}
其他回答
我使用这段代码来更改响应器。
- (BOOL)textView:(UITextView*) textView shouldChangeTextInRange: (NSRange) range replacementText: (NSString*) text
{
if ([text isEqualToString:@"\n"]) {
//[textView resignFirstResponder];
//return YES;
NSInteger nextTag = textView.tag + 1;
// Try to find next responder
UIResponder* nextResponder = [self.view viewWithTag:nextTag];
if (nextResponder) {
// Found next responder, so set it.
[nextResponder becomeFirstResponder];
} else {
// Not found, so remove keyboard.
[textView resignFirstResponder];
}
return NO;
return NO;
}
return YES;
}
-(BOOL)textFieldShouldReturn:(UITextField *)textField; // called from textfield (keyboard)
-(BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text; // good tester function - thanks
我想我应该把这个片段放在这里:
确保声明了对UITextViewDelegate协议的支持。
- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
if([text isEqualToString:@"\n"]) {
[textView resignFirstResponder];
return NO;
}
return YES;
}
Swift 4.0更新:
func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool {
if text == "\n" {
textView.resignFirstResponder()
return false
}
return true
}
在viewDidLoad中添加一个观察者
[[NSNotificationCenter defaultCenter] addObserver: self selector: @selector(textViewKeyPressed:) name: UITextViewTextDidChangeNotification object: nil];
然后使用选择器检查"\n"
-(void) textViewKeyPressed: (NSNotification*) notification {
if ([[[notification object] text] hasSuffix:@"\n"])
{
[[notification object] resignFirstResponder];
}
}
它确实使用“\n”,而不是专门检查返回键,但我认为这是可以的。
更新
参见下面ribto的答案,它使用[NSCharacterSet newlineCharacterSet]来代替\n
我知道这已经回答了,但我真的不喜欢使用字符串字面量的换行,所以这是我所做的。
- (BOOL)textView:(UITextView *)txtView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
if( [text rangeOfCharacterFromSet:[NSCharacterSet newlineCharacterSet]].location == NSNotFound ) {
return YES;
}
[txtView resignFirstResponder];
return NO;
}
Swift 4.0更新:
func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool {
if (text as NSString).rangeOfCharacter(from: CharacterSet.newlines).location == NSNotFound {
return true
}
txtView.resignFirstResponder()
return false
}