在IB的库中,介绍告诉我们,当按下返回键时,UITextView的键盘将消失。但实际上返回键只能作为'\n'
我可以添加一个按钮,并使用[txtView resignFirstResponder]隐藏键盘。
但是有没有办法为键盘中的返回键添加动作,这样我就不需要添加UIButton了?
在IB的库中,介绍告诉我们,当按下返回键时,UITextView的键盘将消失。但实际上返回键只能作为'\n'
我可以添加一个按钮,并使用[txtView resignFirstResponder]隐藏键盘。
但是有没有办法为键盘中的返回键添加动作,这样我就不需要添加UIButton了?
当前回答
+ (void)addDoneButtonToControl:(id)txtFieldOrTextView
{
if([txtFieldOrTextView isKindOfClass:[UITextField class]])
{
txtFieldOrTextView = (UITextField *)txtFieldOrTextView;
}
else if([txtFieldOrTextView isKindOfClass:[UITextView class]])
{
txtFieldOrTextView = (UITextView *)txtFieldOrTextView;
}
UIToolbar* numberToolbar = [[UIToolbar alloc]initWithFrame:CGRectMake(0,
0,
[Global returnDeviceWidth],
50)];
numberToolbar.barStyle = UIBarStyleDefault;
UIBarButtonItem *btnDone = [[UIBarButtonItem alloc] initWithImage:[UIImage imageNamed:@"btn_return"]
style:UIBarButtonItemStyleBordered
target:txtFieldOrTextView
action:@selector(resignFirstResponder)];
numberToolbar.items = [NSArray arrayWithObjects:btnDone,nil];
[numberToolbar sizeToFit];
if([txtFieldOrTextView isKindOfClass:[UITextField class]])
{
((UITextField *)txtFieldOrTextView).inputAccessoryView = numberToolbar;
}
else if([txtFieldOrTextView isKindOfClass:[UITextView class]])
{
((UITextView *)txtFieldOrTextView).inputAccessoryView = numberToolbar;
}
}
其他回答
我知道这已经回答了,但我真的不喜欢使用字符串字面量的换行,所以这是我所做的。
- (BOOL)textView:(UITextView *)txtView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
if( [text rangeOfCharacterFromSet:[NSCharacterSet newlineCharacterSet]].location == NSNotFound ) {
return YES;
}
[txtView resignFirstResponder];
return NO;
}
Swift 4.0更新:
func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool {
if (text as NSString).rangeOfCharacter(from: CharacterSet.newlines).location == NSNotFound {
return true
}
txtView.resignFirstResponder()
return false
}
-(BOOL)textFieldShouldReturn:(UITextField *)textField; // called from textfield (keyboard)
-(BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text; // good tester function - thanks
我想我应该把这个片段放在这里:
确保声明了对UITextViewDelegate协议的支持。
- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
if([text isEqualToString:@"\n"]) {
[textView resignFirstResponder];
return NO;
}
return YES;
}
Swift 4.0更新:
func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool {
if text == "\n" {
textView.resignFirstResponder()
return false
}
return true
}
我发现josebama的回答是这个帖子中最完整、最干净的答案。
下面是Swift 4的语法:
func textView(_ textView: UITextView, shouldChangeTextIn _: NSRange, replacementText text: String) -> Bool {
let resultRange = text.rangeOfCharacter(from: CharacterSet.newlines, options: .backwards)
if text.count == 1 && resultRange != nil {
textView.resignFirstResponder()
// Do any additional stuff here
return false
}
return true
}
我使用这段代码来更改响应器。
- (BOOL)textView:(UITextView*) textView shouldChangeTextInRange: (NSRange) range replacementText: (NSString*) text
{
if ([text isEqualToString:@"\n"]) {
//[textView resignFirstResponder];
//return YES;
NSInteger nextTag = textView.tag + 1;
// Try to find next responder
UIResponder* nextResponder = [self.view viewWithTag:nextTag];
if (nextResponder) {
// Found next responder, so set it.
[nextResponder becomeFirstResponder];
} else {
// Not found, so remove keyboard.
[textView resignFirstResponder];
}
return NO;
return NO;
}
return YES;
}