- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range  replacementText:(NSString *)text
{
    if (range.length==0) {
        if ([text isEqualToString:@"\n"]) {
            [txtView resignFirstResponder];
            if(textView.returnKeyType== UIReturnKeyGo){

                [self PreviewLatter];
                return NO;
            }
            return NO;
        }
    }   return YES;
}

我发现josebama的回答是这个帖子中最完整、最干净的答案。

下面是Swift 4的语法:

func textView(_ textView: UITextView, shouldChangeTextIn _: NSRange, replacementText text: String) -> Bool {
    let resultRange = text.rangeOfCharacter(from: CharacterSet.newlines, options: .backwards)
    if text.count == 1 && resultRange != nil {
        textView.resignFirstResponder()
        // Do any additional stuff here
        return false
    }
    return true
}

不要忘记为textView设置委托-否则resignfirstresponder将无法工作。

用另一种方法解决了这个问题。

Create a button that will be placed in the background From the Attribute Inspector, change the button type to custom, and the makes the button transparent. Expand the button to cover the whole view, and make sure the button is behind all the other object. Easy way to do this is to drag the button to the top of list view in the View Control drag the button to the viewController.h file and create an action (Sent Event: Touch Up Inside) like : (IBAction)ExitKeyboard:(id)sender; In ViewController.m should look like : (IBAction)ExitKeyboard:(id)sender { [self.view endEditing:TRUE]; } Run app, and when you click away from the TextView, the keyboard disappears

函数hideQueboard。

- (void)HideQueyboard
{
    [[UIApplication sharedApplication] sendAction:@selector(resignFirstResponder)   to:nil from:nil forEvent:nil];
}

银行的国际代码

在你的类/视图中实现UITextViewDelegate，如下所示:

class MyClass: UITextViewDelegate  { ...

设置textView委托为self

myTextView.delegate = self

然后实现以下内容:

  func textViewDidChange(_ textView: UITextView) {
    if textView.text.characters.count >= 1 {

        if let lastChar = textView.text.characters.last {

            if(lastChar == "\n"){

              textView.text = textView.text.substring(to: textView.text.index(before: textView.text.endIndex))
              textView.resignFirstResponder()
            }
        }
    }
}

编辑 我更新了代码，因为它从来都不是一个好主意，改变用户在文本框的输入，以解决问题，而不是在黑客代码完成后重新设置状态。