单例模式确保只创建一个类的实例。我如何在达特建立这个?
当前回答
如何在飞镖扑动中创建类的单例实例
class ContactBook {
ContactBook._sharedInstance();
static final ContactBook _shared = ContactBook._sharedInstance();
factory ContactBook() => _shared;
}
其他回答
实例化后不能更改对象的单例
class User {
final int age;
final String name;
User({
this.name,
this.age
});
static User _instance;
static User getInstance({name, age}) {
if(_instance == null) {
_instance = User(name: name, age: age);
return _instance;
}
return _instance;
}
}
print(User.getInstance(name: "baidu", age: 24).age); //24
print(User.getInstance(name: "baidu 2").name); // is not changed //baidu
print(User.getInstance()); // {name: "baidu": age 24}
这也是一种创建Singleton类的方法
class Singleton{
Singleton._();
static final Singleton db = Singleton._();
}
** Sigleton范式在Dart声音零安全**
这段代码片段展示了如何在dart中实现单例 这通常用于每次必须使用同一个类的相同对象的情况。在数据库事务。
class MySingleton {
static MySingleton? _instance;
MySingleton._internal();
factory MySingleton() {
if (_instance == null) {
_instance = MySingleton._internal();
}
return _instance!;
}
}
修改了@Seth Ladd关于谁更喜欢Swift风格的单例,比如。shared的答案:
class Auth {
// singleton
static final Auth _singleton = Auth._internal();
factory Auth() => _singleton;
Auth._internal();
static Auth get shared => _singleton;
// variables
String username;
String password;
}
示例:
Auth.shared.username = 'abc';
因为我不太喜欢使用new关键字或其他构造函数,比如对单例对象的调用,我更喜欢使用一个名为inst的静态getter:
// the singleton class
class Dao {
// singleton boilerplate
Dao._internal() {}
static final Dao _singleton = new Dao._internal();
static get inst => _singleton;
// business logic
void greet() => print("Hello from singleton");
}
使用示例:
Dao.inst.greet(); // call a method
// Dao x = new Dao(); // compiler error: Method not found: 'Dao'
// verify that there only exists one and only one instance
assert(identical(Dao.inst, Dao.inst));