List<String> myStringList = new List<String> (); foreach (myStringArray中的字符串) ｛ 如果(! myStringList.Contains (s)) ｛ myStringList.Add(年代); ｝ ｝

这是O(n²)，这对于一个短列表来说没有什么关系因为它将被塞进一个组合中，但对于一个大的集合来说可能很快就会成为一个问题。

所以我在做一个面试时，得到了同样的问题来分类和区分

static void Sort()
    {
        try
        {
            int[] number = new int[Convert.ToInt32(Console.ReadLine())];
            for (int i = 0; i < number.Length; i++)
            {
                number[i] = Convert.ToInt32(Console.ReadLine());
            }
            Array.Sort(number);
            int[] num = number.Distinct().ToArray();
            for (int i = 0; i < num.Length; i++)
            {
                Console.WriteLine(num[i]);
            }
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex);
        }
        Console.Read();
    }

测试了下面的&它工作。最酷的是，它还做了一个文化敏感搜索

class RemoveDuplicatesInString
{
    public static String RemoveDups(String origString)
    {
        String outString = null;
        int readIndex = 0;
        CompareInfo ci = CultureInfo.CurrentCulture.CompareInfo;


        if(String.IsNullOrEmpty(origString))
        {
            return outString;
        }

        foreach (var ch in origString)
        {
            if (readIndex == 0)
            {
                outString = String.Concat(ch);
                readIndex++;
                continue;
            }

            if (ci.IndexOf(origString, ch.ToString().ToLower(), 0, readIndex) == -1)
            {
                //Unique char as this char wasn't found earlier.
                outString = String.Concat(outString, ch);                   
            }

            readIndex++;

        }


        return outString;
    }


    static void Main(string[] args)
    {
        String inputString = "aAbcefc";
        String outputString;

        outputString = RemoveDups(inputString);

        Console.WriteLine(outputString);
    }

}

--AptSenSDET

这段代码从数组中100%删除重复值[因为我使用了一个[I]].....您可以将其转换为任何OO语言.....：）

for(int i=0;i<size;i++)
{
    for(int j=i+1;j<size;j++)
    {
        if(a[i] == a[j])
        {
            for(int k=j;k<size;k++)
            {
                 a[k]=a[k+1];
            }
            j--;
            size--;
        }
    }

}

protected void Page_Load(object sender, EventArgs e)
{
    string a = "a;b;c;d;e;v";
    string[] b = a.Split(';');
    string[] c = b.Distinct().ToArray();

    if (b.Length != c.Length)
    {
        for (int i = 0; i < b.Length; i++)
        {
            try
            {
                if (b[i].ToString() != c[i].ToString())
                {
                    Response.Write("Found duplicate " + b[i].ToString());
                    return;
                }
            }
            catch (Exception ex)
            {
                Response.Write("Found duplicate " + b[i].ToString());
                return;
            }
        }              
    }
    else
    {
        Response.Write("No duplicate ");
    }
}

你可以在使用数组列表时使用这段代码

ArrayList arrayList;
//Add some Members :)
arrayList.Add("ali");
arrayList.Add("hadi");
arrayList.Add("ali");

//Remove duplicates from array
  for (int i = 0; i < arrayList.Count; i++)
    {
       for (int j = i + 1; j < arrayList.Count ; j++)
           if (arrayList[i].ToString() == arrayList[j].ToString())
                 arrayList.Remove(arrayList[j]);