我试图在php中生成一个随机密码。
但是我得到的都是'a'返回类型是数组类型，我希望它是字符串。对如何修改代码有什么想法吗?
谢谢。
function randomPassword() {
$alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
for ($i = 0; $i < 8; $i++) {
$n = rand(0, count($alphabet)-1);
$pass[$i] = $alphabet[$n];
}
return $pass;
}
当前回答
function password_generate($n, $l, $s)
{
$numbers = '1234567890';
$letters = '1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZabcefghijklmnopqrstuvwxyz';
$special = '--!=!@@#++%';
return substr(str_shuffle($numbers), 0, $n).substr(str_shuffle($letters), 0, $l).substr(str_shuffle($special), 0, $s);
}
echo password_generate(2,9,1);
其他回答
快速。简单，干净和一致的格式，如果这是你想要的
$pw = chr(mt_rand(97,122)).mt_rand(0,9).chr(mt_rand(97,122)).mt_rand(10,99).chr(mt_rand(97,122)).mt_rand(100,999);
该函数将根据参数中的规则生成密码
function random_password( $length = 8, $characters = true, $numbers = true, $case_sensitive = true, $hash = true ) {
$password = '';
if($characters)
{
$charLength = $length;
if($numbers) $charLength-=2;
if($case_sensitive) $charLength-=2;
if($hash) $charLength-=2;
$chars = "abcdefghijklmnopqrstuvwxyz";
$password.= substr( str_shuffle( $chars ), 0, $charLength );
}
if($numbers)
{
$numbersLength = $length;
if($characters) $numbersLength-=2;
if($case_sensitive) $numbersLength-=2;
if($hash) $numbersLength-=2;
$chars = "0123456789";
$password.= substr( str_shuffle( $chars ), 0, $numbersLength );
}
if($case_sensitive)
{
$UpperCaseLength = $length;
if($characters) $UpperCaseLength-=2;
if($numbers) $UpperCaseLength-=2;
if($hash) $UpperCaseLength-=2;
$chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
$password.= substr( str_shuffle( $chars ), 0, $UpperCaseLength );
}
if($hash)
{
$hashLength = $length;
if($characters) $hashLength-=2;
if($numbers) $hashLength-=2;
if($case_sensitive) $hashLength-=2;
$chars = "!@#$%^&*()_-=+;:,.?";
$password.= substr( str_shuffle( $chars ), 0, $hashLength );
}
$password = str_shuffle( $password );
return $password;
}
我的答案与上面的一些类似，但我去掉了元音，数字1和0，字母I, j, I, l, O, O, Q, Q, X, X, Y, Y, W, W。原因是:第一个很容易混淆(就像l和1，取决于字体)，其余的(从Q开始)是因为它们在我的语言中不存在，所以对于超级终端用户来说可能有点奇怪。字符串仍然足够长。此外，我知道使用一些特殊的标志是理想的，但他们也与一些最终用户相处不好。
function generatePassword($length = 8) {
$chars = '23456789bcdfhkmnprstvzBCDFHJKLMNPRSTVZ';
$shuffled = str_shuffle($chars);
$result = mb_substr($shuffled, 0, $length);
return $result;
}
此外，通过这种方式，我们避免重复相同的字母和数字(不包括匹配情况)
如果你在PHP7上，你可以使用random_int()函数:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[random_int(0, $max)];
return $str;
}
旧答案如下:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[mt_rand(0, $max)];
return $str;
}
这是我的密码助手
class PasswordHelper
{
/**
* generate a secured random password
*/
public static function generatePassword(
int $lowerCaseCount=8,
int $upperCaseCount=8,
int $numberCount=8,
int $specialCount=4
): string
{
$lowerCase = 'abcdefghijklmnopqrstuvwxyz';
$upperCase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
$number = '0123456789';
$special = '!@#$%^&*';
$password = self::getRandom($lowerCase, $lowerCaseCount);
$password .= self::getRandom($upperCase, $upperCaseCount);
$password .= self::getRandom($number, $numberCount);
$password .= self::getRandom($special, $specialCount);
return str_shuffle($password);
}
/**
* get a random string from a set of characters
*/
public static function getRandom($set, $length): string
{
$rand = '';
$setLength = strlen($set);
for ($i = 0; $i < $length; $i++)
{
$rand .= $set[random_int(0, $setLength - 1)];
}
return $rand;
}
}
用法:
PasswordHelper::generatePassword()或PasswordHelper::generatePassword(2,4,5,3)
