我试图在php中生成一个随机密码。

但是我得到的都是'a'返回类型是数组类型,我希望它是字符串。对如何修改代码有什么想法吗?

谢谢。

function randomPassword() {
    $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, count($alphabet)-1);
        $pass[$i] = $alphabet[$n];
    }
    return $pass;
}

当前回答

这是我的密码助手

class PasswordHelper
{
    /**
    * generate a secured random password
    */
    public static function generatePassword(
        int $lowerCaseCount=8, 
        int $upperCaseCount=8, 
        int $numberCount=8, 
        int $specialCount=4
    ): string
    {
        $lowerCase  = 'abcdefghijklmnopqrstuvwxyz';
        $upperCase  = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
        $number     = '0123456789';
        $special    = '!@#$%^&*';

        $password = self::getRandom($lowerCase, $lowerCaseCount);
        $password .= self::getRandom($upperCase, $upperCaseCount);
        $password .= self::getRandom($number, $numberCount);
        $password .= self::getRandom($special, $specialCount);

        return str_shuffle($password);
    }

    /**
     * get a random string from a set of characters
     */
    public static function getRandom($set, $length): string
    {
        $rand = '';
        $setLength = strlen($set);

        for ($i = 0; $i < $length; $i++)
        {
            $rand .= $set[random_int(0, $setLength - 1)];
        }

        return $rand;
    }
}

用法:

PasswordHelper::generatePassword()或PasswordHelper::generatePassword(2,4,5,3)

其他回答

聪明一点:

function strand($length){
  if($length > 0)
    return chr(rand(33, 126)) . strand($length - 1);
}

点击这里在线查看。

有一个简短的解决方案(php 8.1):

$dict = array_merge(
    ...array_map(
        fn(array $d): array => range(ord($d[0]), ord($d[1])),
        [["0", "9"], ["a", "z"], ["A", "Z"]]
    )
); 

$f = fn (int $len): string =>
    join(
        "",
        array_map(
            fn (): string => chr($dict[random_int(0, count($dict) - 1)]),
            range(0, $len)
        )
    ); 

echo $f(12) . PHP_EOL;

一行bash脚本:

PHP -r '$dict = array_merge(…到fn(数组$ d):数组= >范围(奥德($ d[0]),奥德($ d[1])),(“0”,“9”,“一个”、“z”,[“一”、“z”]]));$ f = fn (int len美元):字符串= >加入(“”,到(fn():字符串= >科($ dict [random_int (0, count ($ dict) - 1))),范围(0,len美元)));Echo $f(12)。PHP_EOL;”

这是来自https://stackoverflow.com/a/41077923/5599052的想法

你需要strlen($alphabet),而不是常量字母的计数(相当于'alphabet')。

然而,rand并不是一个适合于此目的的随机函数。它的输出可以很容易地预测,因为它隐含地以当前时间作为种子。此外,兰特是不加密安全的;因此,从输出中确定其内部状态相对容易。

相反,从/dev/urandom读取以获得加密随机数据。

function password_generate($n, $l, $s) 
{
  $numbers = '1234567890';
  $letters = '1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZabcefghijklmnopqrstuvwxyz';
  $special = '--!=!@@#++%';
  return substr(str_shuffle($numbers), 0, $n).substr(str_shuffle($letters), 0, $l).substr(str_shuffle($special), 0, $s);
}

echo password_generate(2,9,1);

Create a file with this code in it. Call it like in the comments. <?php /** * @usage : * include_once($path . '/Password.php'); * $Password = new Password; * $pwd = $Password->createPassword(10); * return $pwd; * */ class Password { public function createPassword($length = 15) { $response = []; $response['pwd'] = $this->generate($length); $response['hashPwd'] = $this->hashPwd( $response['pwd'] ); return $response; } private function generate($length = 15) { $chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%^&*(){}/?,><"; return substr(str_shuffle($chars),0,$length); } private function hashPwd($pwd) { return hash('sha256', $pwd); } } ?>