我试图在php中生成一个随机密码。

但是我得到的都是'a'返回类型是数组类型,我希望它是字符串。对如何修改代码有什么想法吗?

谢谢。

function randomPassword() {
    $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, count($alphabet)-1);
        $pass[$i] = $alphabet[$n];
    }
    return $pass;
}

当前回答

Base_convert (uniqid('pass', true), 10,36);

我。e0m6ngefmj4

EDIT

正如我在评论中提到的,长度意味着暴力攻击比定时攻击更有效,所以不必担心“随机生成器有多安全”。安全性,特别是对于这个用例,需要补充可用性,所以上面的解决方案对于所需的问题已经足够好了。

然而,以防你在搜索安全的随机字符串生成器时偶然发现了这个答案(我假设有些人已经基于响应),对于生成令牌之类的东西,以下是此类代码的生成器的样子:

function base64urlEncode($data) {
    return rtrim(strtr(base64_encode($data), '+/', '-_'), '=');
}

function secureId($length = 32) {

    if (function_exists('openssl_random_pseudo_bytes')) {
        $bytes = openssl_random_pseudo_bytes($length);
        return rtrim(strtr(base64_encode($bytes), '+/', '0a'), '=');
    }
    else { // fallback to system bytes

        error_log("Missing support for openssl_random_pseudo_bytes");

        $pr_bits = '';

        $fp = @fopen('/dev/urandom', 'rb');
        if ($fp !== false) {
            $pr_bits .= @fread($fp, $length);
            @fclose($fp);
        }

        if (strlen($pr_bits) < $length) {
            error_log('unable to read /dev/urandom');
            throw new \Exception('unable to read /dev/urandom');
        }

        return base64urlEncode($pr_bits);
    }
}

其他回答

以下是我对选项列表的贡献。

该功能可以确保密码策略被满足。

  function password_generate($length=8, $min_lowercases=1, $min_uppercases=1, $min_numbers=1, $min_specials=0) {

    $lowercases = 'abcdefghijklmnopqrstuvwxyz';
    $uppercases = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $numbers = '0123456789';
    $specials = '!#%&/(){}[]+-';

    $absolutes = '';
    if ($min_lowercases && !is_bool($min_lowercases)) $absolutes .= substr(str_shuffle(str_repeat($lowercases, $min_lowercases)), 0, $min_lowercases);
    if ($min_uppercases && !is_bool($min_uppercases)) $absolutes .= substr(str_shuffle(str_repeat($uppercases, $min_uppercases)), 0, $min_uppercases);
    if ($min_numbers && !is_bool($min_numbers)) $absolutes .= substr(str_shuffle(str_repeat($numbers, $min_numbers)), 0, $min_numbers);
    if ($min_specials && !is_bool($min_specials)) $absolutes .= substr(str_shuffle(str_repeat($specials, $min_specials)), 0, $min_specials);

    $remaining = $length - strlen($absolutes);

    $characters = '';
    if ($min_lowercases !== false) $characters .= substr(str_shuffle(str_repeat($lowercases, $remaining)), 0, $remaining);
    if ($min_uppercases !== false) $characters .= substr(str_shuffle(str_repeat($uppercases, $remaining)), 0, $remaining);
    if ($min_numbers !== false) $characters .= substr(str_shuffle(str_repeat($numbers, $remaining)), 0, $remaining);
    if ($min_specials !== false) $characters .= substr(str_shuffle(str_repeat($specials, $remaining)), 0, $remaining);

    $password = str_shuffle($absolutes . substr($characters, 0, $remaining));

    return $password;
  }

参数$min_*可以有以下值:

1-999 =需要 True =可选 False =禁用

它可以像下面这样使用:

echo password_generate(8); // Outputs a random 8 characters long password

10个字符的密码,每组至少有2个字符:

echo password_generate(10, 2, 2, 2, 2);

只输出6个随机数

echo password_generate(6, false, false, true, false);

快速。简单,干净和一致的格式,如果这是你想要的

$pw = chr(mt_rand(97,122)).mt_rand(0,9).chr(mt_rand(97,122)).mt_rand(10,99).chr(mt_rand(97,122)).mt_rand(100,999);

这是基于本页的另一个答案,https://stackoverflow.com/a/21498316/525649

这个答案只生成十六进制字符,0-9,a-f。对于一些看起来不像hex的东西,试试这个:

str_shuffle(
  rtrim(
    base64_encode(bin2hex(openssl_random_pseudo_bytes(5))),
    '='
  ). 
  strtoupper(bin2hex(openssl_random_pseudo_bytes(7))).
  bin2hex(openssl_random_pseudo_bytes(13))
)

Base64_encode返回更广泛的字母数字字符 Rtrim有时会在结尾删除=

例子:

32 efvfgdg891be5e7293e54z1d23110m3zu3fmjb30z9a740ej0jz4 b280R72b48eOm77a25YCj093DE5d9549Gc73Jg8TdD9Z0Nj4b98760 051年b33654c0eg201cfw0e6na4b9614ze8d2fn49e12y0zy557aucb8 y67Q86ffd83G0z00M0Z152f7O2ADcY313gD7a774fc5FF069zdb5b7

对于为用户创建界面来说,这不是很可配置的,但对于某些目的来说,这是可以的。增加字符数,以弥补特殊字符的不足。

Generates a strong password of length 8 containing at least one lower case letter, one uppercase letter, one digit, and one special character. You can change the length in the code too. function checkForCharacterCondition($string) { return (bool) preg_match('/(?=.*([A-Z]))(?=.*([a-z]))(?=.*([0-9]))(?=.*([~`\!@#\$%\^&\*\(\)_\{\}\[\]]))/', $string); } $j = 1; function generate_pass() { global $j; $allowedCharacters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ~`!@#$%^&*()_{}[]'; $pass = ''; $length = 8; $max = mb_strlen($allowedCharacters, '8bit') - 1; for ($i = 0; $i < $length; ++$i) { $pass .= $allowedCharacters[random_int(0, $max)]; } if (checkForCharacterCondition($pass)){ return '<br><strong>Selected password: </strong>'.$pass; }else{ echo 'Iteration '.$j.': <strong>'.$pass.'</strong> Rejected<br>'; $j++; return generate_pass(); } } echo generate_pass();

下面是另一个密码生成器代码片段。 控制长度,数字和特殊字符计数和列表。

其他解决方案的一个问题是,它们没有包含重复字符的选项。而下面的脚本也可以做到这一点。

$length = random_int(30, 40);

$pass = [];

$lowers = range('a', 'z');
$uppers = range('A', 'Z');
$digits = range('0', '9');
$specials = ['.', '-', '_', '^', '#', '(', ')'];

$specialCount = random_int(1, 5);
$digitCount = random_int(1, 9);

for ($i = 0; $i < $length - $specialCount - $digitCount; $i++) { 
    $pass[] = random_int(1, PHP_INT_MAX) % 2 == 0 ? $uppers[array_rand($uppers)] : $lowers[array_rand($lowers)];
}
for ($i = 0; $i < $specialCount; $i++) { 
    $pass[] = $specials[array_rand($specials)];
}
for ($i = 0; $i < $digitCount; $i++) { 
    $pass[] = $digits[array_rand($digits)];
}

shuffle($pass)

$pass = implode('', $pass);