我试图在php中生成一个随机密码。
但是我得到的都是'a'返回类型是数组类型，我希望它是字符串。对如何修改代码有什么想法吗?
谢谢。
function randomPassword() {
$alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
for ($i = 0; $i < 8; $i++) {
$n = rand(0, count($alphabet)-1);
$pass[$i] = $alphabet[$n];
}
return $pass;
}
当前回答
聪明一点:
function strand($length){
if($length > 0)
return chr(rand(33, 126)) . strand($length - 1);
}
点击这里在线查看。
其他回答
Generates a strong password of length 8 containing at least one lower case letter, one uppercase letter, one digit, and one special character. You can change the length in the code too. function checkForCharacterCondition($string) { return (bool) preg_match('/(?=.*([A-Z]))(?=.*([a-z]))(?=.*([0-9]))(?=.*([~`\!@#\$%\^&\*\(\)_\{\}\[\]]))/', $string); } $j = 1; function generate_pass() { global $j; $allowedCharacters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ~`!@#$%^&*()_{}[]'; $pass = ''; $length = 8; $max = mb_strlen($allowedCharacters, '8bit') - 1; for ($i = 0; $i < $length; ++$i) { $pass .= $allowedCharacters[random_int(0, $max)]; } if (checkForCharacterCondition($pass)){ return '<br><strong>Selected password: </strong>'.$pass; }else{ echo 'Iteration '.$j.': <strong>'.$pass.'</strong> Rejected<br>'; $j++; return generate_pass(); } } echo generate_pass();
下面是我对随机密码生成助手的看法。
它确保密码包含数字，大写字母和小写字母，以及至少3个特殊字符。
密码长度为11 ~ 30。
function plainPassword(): string
{
$numbers = array_rand(range(0, 9), rand(3, 9));
$uppercase = array_rand(array_flip(range('A', 'Z')), rand(2, 8));
$lowercase = array_rand(array_flip(range('a', 'z')), rand(3, 8));
$special = array_rand(array_flip(['@', '#', '$', '!', '%', '*', '?', '&']), rand(3, 5));
$password = array_merge(
$numbers,
$uppercase,
$lowercase,
$special
);
shuffle($password);
return implode($password);
}
如果你在PHP7上，你可以使用random_int()函数:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[random_int(0, $max)];
return $str;
}
旧答案如下:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[mt_rand(0, $max)];
return $str;
}
试着用大写字母，小写字母，数字和特殊字符
function generatePassword($_len) {
$_alphaSmall = 'abcdefghijklmnopqrstuvwxyz'; // small letters
$_alphaCaps = strtoupper($_alphaSmall); // CAPITAL LETTERS
$_numerics = '1234567890'; // numerics
$_specialChars = '`~!@#$%^&*()-_=+]}[{;:,<.>/?\'"\|'; // Special Characters
$_container = $_alphaSmall.$_alphaCaps.$_numerics.$_specialChars; // Contains all characters
$password = ''; // will contain the desired pass
for($i = 0; $i < $_len; $i++) { // Loop till the length mentioned
$_rand = rand(0, strlen($_container) - 1); // Get Randomized Length
$password .= substr($_container, $_rand, 1); // returns part of the string [ high tensile strength ;) ]
}
return $password; // Returns the generated Pass
}
假设我们需要10位Pass
echo generatePassword(10);
示例输出:
IZCQ_IV \ 7
@wlqsfhT (d
是1!8 + 1 \ 4 @ud
快速。简单，干净和一致的格式，如果这是你想要的
$pw = chr(mt_rand(97,122)).mt_rand(0,9).chr(mt_rand(97,122)).mt_rand(10,99).chr(mt_rand(97,122)).mt_rand(100,999);
