我试图在php中生成一个随机密码。
但是我得到的都是'a'返回类型是数组类型，我希望它是字符串。对如何修改代码有什么想法吗?
谢谢。
function randomPassword() {
$alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
for ($i = 0; $i < 8; $i++) {
$n = rand(0, count($alphabet)-1);
$pass[$i] = $alphabet[$n];
}
return $pass;
}
当前回答
如果你在PHP7上，你可以使用random_int()函数:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[random_int(0, $max)];
return $str;
}
旧答案如下:
function generate_password($length = 20){
$chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.
'0123456789`-=~!@#$%^&*()_+,./<>?;:[]{}\|';
$str = '';
$max = strlen($chars) - 1;
for ($i=0; $i < $length; $i++)
$str .= $chars[mt_rand(0, $max)];
return $str;
}
其他回答
生成随机密码字符串
function generate_randompassword($passlength = 8){
$alphabet = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789@#%^*>\$@?/[]=+';
$pass = array(); //remember to declare $pass as an array
$alphaLength = strlen($alphabet) - 1; //put the length -1 in cache
for ($i = 0; $i < $passlength; $i++) {
$n = rand(0, $alphaLength);
$pass[] = $alphabet[$n];
}
return implode($pass); //turn the array into a string
}
以下是我对选项列表的贡献。
该功能可以确保密码策略被满足。
function password_generate($length=8, $min_lowercases=1, $min_uppercases=1, $min_numbers=1, $min_specials=0) {
$lowercases = 'abcdefghijklmnopqrstuvwxyz';
$uppercases = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
$numbers = '0123456789';
$specials = '!#%&/(){}[]+-';
$absolutes = '';
if ($min_lowercases && !is_bool($min_lowercases)) $absolutes .= substr(str_shuffle(str_repeat($lowercases, $min_lowercases)), 0, $min_lowercases);
if ($min_uppercases && !is_bool($min_uppercases)) $absolutes .= substr(str_shuffle(str_repeat($uppercases, $min_uppercases)), 0, $min_uppercases);
if ($min_numbers && !is_bool($min_numbers)) $absolutes .= substr(str_shuffle(str_repeat($numbers, $min_numbers)), 0, $min_numbers);
if ($min_specials && !is_bool($min_specials)) $absolutes .= substr(str_shuffle(str_repeat($specials, $min_specials)), 0, $min_specials);
$remaining = $length - strlen($absolutes);
$characters = '';
if ($min_lowercases !== false) $characters .= substr(str_shuffle(str_repeat($lowercases, $remaining)), 0, $remaining);
if ($min_uppercases !== false) $characters .= substr(str_shuffle(str_repeat($uppercases, $remaining)), 0, $remaining);
if ($min_numbers !== false) $characters .= substr(str_shuffle(str_repeat($numbers, $remaining)), 0, $remaining);
if ($min_specials !== false) $characters .= substr(str_shuffle(str_repeat($specials, $remaining)), 0, $remaining);
$password = str_shuffle($absolutes . substr($characters, 0, $remaining));
return $password;
}
参数$min_*可以有以下值:
1-999 =需要 True =可选 False =禁用
它可以像下面这样使用:
echo password_generate(8); // Outputs a random 8 characters long password
10个字符的密码，每组至少有2个字符:
echo password_generate(10, 2, 2, 2, 2);
只输出6个随机数
echo password_generate(6, false, false, true, false);
一句话:
substr(str_shuffle('abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789') , 0 , 10 )
有一个简短的解决方案(php 8.1):
$dict = array_merge(
...array_map(
fn(array $d): array => range(ord($d[0]), ord($d[1])),
[["0", "9"], ["a", "z"], ["A", "Z"]]
)
);
$f = fn (int $len): string =>
join(
"",
array_map(
fn (): string => chr($dict[random_int(0, count($dict) - 1)]),
range(0, $len)
)
);
echo $f(12) . PHP_EOL;
一行bash脚本:
PHP -r '$dict = array_merge(…到fn(数组$ d):数组= >范围(奥德($ d[0]),奥德($ d[1])),(“0”,“9”,“一个”、“z”,[“一”、“z”]]));$ f = fn (int len美元):字符串= >加入(“”,到(fn():字符串= >科($ dict [random_int (0, count ($ dict) - 1))),范围(0,len美元)));Echo $f(12)。PHP_EOL;”
这是来自https://stackoverflow.com/a/41077923/5599052的想法
你最好的选择是ircmaxell的RandomLib库。
使用的例子:
$factory = new RandomLib\Factory;
$generator = $factory->getGenerator(new SecurityLib\Strength(SecurityLib\Strength::MEDIUM));
$passwordLength = 8; // Or more
$randomPassword = $generator->generateString($passwordLength);
它产生的字符串比普通的随机函数(如shuffle()和rand()(这是你通常想要的敏感信息，如密码，盐和密钥)更强的随机性。
