从字节大小返回人类可读大小的函数:
>>> human_readable(2048)
'2 kilobytes'
>>>
如何做到这一点?
从字节大小返回人类可读大小的函数:
>>> human_readable(2048)
'2 kilobytes'
>>>
如何做到这一点?
当前回答
以下工作在Python 3.6+中,在我看来,是这里最容易理解的答案,并允许您自定义使用的小数位数。
def human_readable_size(size, decimal_places=2):
for unit in ['B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB']:
if size < 1024.0 or unit == 'PiB':
break
size /= 1024.0
return f"{size:.{decimal_places}f} {unit}"
其他回答
总有一个这样的人。今天轮到我了。这是一行代码——如果算上函数签名的话是两行。
def human_size(bytes, units=[' bytes','KB','MB','GB','TB', 'PB', 'EB']):
""" Returns a human readable string representation of bytes """
return str(bytes) + units[0] if bytes < 1024 else human_size(bytes>>10, units[1:])
>>> human_size(123)
123 bytes
>>> human_size(123456789)
117GB
如果你需要大于1艾字节的大小,那就有点麻烦了:
def human_size(bytes, units=[' bytes','KB','MB','GB','TB', 'PB', 'EB']):
return str(bytes) + units[0] if bytes < 1024 else human_size(bytes>>10, units[1:]) if units[1:] else f'{bytes>>10}ZB'
以下工作在Python 3.6+中,在我看来,是这里最容易理解的答案,并允许您自定义使用的小数位数。
def human_readable_size(size, decimal_places=2):
for unit in ['B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB']:
if size < 1024.0 or unit == 'PiB':
break
size /= 1024.0
return f"{size:.{decimal_places}f} {unit}"
为了以人类可读的形式获取文件大小,我创建了这个函数:
import os
def get_size(path):
size = os.path.getsize(path)
if size < 1024:
return f"{size} bytes"
elif size < pow(1024,2):
return f"{round(size/1024, 2)} KB"
elif size < pow(1024,3):
return f"{round(size/(pow(1024,2)), 2)} MB"
elif size < pow(1024,4):
return f"{round(size/(pow(1024,3)), 2)} GB"
>>> get_size("a.txt")
1.4KB
你应该用humanize。
>>> humanize.naturalsize(1000000)
'1.0 MB'
>>> humanize.naturalsize(1000000, binary=True)
'976.6 KiB'
>>> humanize.naturalsize(1000000, gnu=True)
'976.6K'
参考: https://pypi.org/project/humanize/
参考Sridhar Ratnakumar的回答,更新为:
def formatSize(sizeInBytes, decimalNum=1, isUnitWithI=False, sizeUnitSeperator=""):
"""format size to human readable string"""
# https://en.wikipedia.org/wiki/Binary_prefix#Specific_units_of_IEC_60027-2_A.2_and_ISO.2FIEC_80000
# K=kilo, M=mega, G=giga, T=tera, P=peta, E=exa, Z=zetta, Y=yotta
sizeUnitList = ['','K','M','G','T','P','E','Z']
largestUnit = 'Y'
if isUnitWithI:
sizeUnitListWithI = []
for curIdx, eachUnit in enumerate(sizeUnitList):
unitWithI = eachUnit
if curIdx >= 1:
unitWithI += 'i'
sizeUnitListWithI.append(unitWithI)
# sizeUnitListWithI = ['','Ki','Mi','Gi','Ti','Pi','Ei','Zi']
sizeUnitList = sizeUnitListWithI
largestUnit += 'i'
suffix = "B"
decimalFormat = "." + str(decimalNum) + "f" # ".1f"
finalFormat = "%" + decimalFormat + sizeUnitSeperator + "%s%s" # "%.1f%s%s"
sizeNum = sizeInBytes
for sizeUnit in sizeUnitList:
if abs(sizeNum) < 1024.0:
return finalFormat % (sizeNum, sizeUnit, suffix)
sizeNum /= 1024.0
return finalFormat % (sizeNum, largestUnit, suffix)
示例输出如下:
def testKb():
kbSize = 3746
kbStr = formatSize(kbSize)
print("%s -> %s" % (kbSize, kbStr))
def testI():
iSize = 87533
iStr = formatSize(iSize, isUnitWithI=True)
print("%s -> %s" % (iSize, iStr))
def testSeparator():
seperatorSize = 98654
seperatorStr = formatSize(seperatorSize, sizeUnitSeperator=" ")
print("%s -> %s" % (seperatorSize, seperatorStr))
def testBytes():
bytesSize = 352
bytesStr = formatSize(bytesSize)
print("%s -> %s" % (bytesSize, bytesStr))
def testMb():
mbSize = 76383285
mbStr = formatSize(mbSize, decimalNum=2)
print("%s -> %s" % (mbSize, mbStr))
def testTb():
tbSize = 763832854988542
tbStr = formatSize(tbSize, decimalNum=2)
print("%s -> %s" % (tbSize, tbStr))
def testPb():
pbSize = 763832854988542665
pbStr = formatSize(pbSize, decimalNum=4)
print("%s -> %s" % (pbSize, pbStr))
def demoFormatSize():
testKb()
testI()
testSeparator()
testBytes()
testMb()
testTb()
testPb()
# 3746 -> 3.7KB
# 87533 -> 85.5KiB
# 98654 -> 96.3 KB
# 352 -> 352.0B
# 76383285 -> 72.84MB
# 763832854988542 -> 694.70TB
# 763832854988542665 -> 678.4199PB