从字节大小返回人类可读大小的函数:
>>> human_readable(2048)
'2 kilobytes'
>>>
如何做到这一点?
从字节大小返回人类可读大小的函数:
>>> human_readable(2048)
'2 kilobytes'
>>>
如何做到这一点?
当前回答
def human_readable_data_quantity(quantity, multiple=1024):
if quantity == 0:
quantity = +0
SUFFIXES = ["B"] + [i + {1000: "B", 1024: "iB"}[multiple] for i in "KMGTPEZY"]
for suffix in SUFFIXES:
if quantity < multiple or suffix == SUFFIXES[-1]:
if suffix == SUFFIXES[0]:
return "%d%s" % (quantity, suffix)
else:
return "%.1f%s" % (quantity, suffix)
else:
quantity /= multiple
其他回答
该功能在Boltons中可用,这对于大多数项目来说都是一个非常方便的库。
>>> bytes2human(128991)
'126K'
>>> bytes2human(100001221)
'95M'
>>> bytes2human(0, 2)
'0.00B'
以下工作在Python 3.6+中,在我看来,是这里最容易理解的答案,并允许您自定义使用的小数位数。
def human_readable_size(size, decimal_places=2):
for unit in ['B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB']:
if size < 1024.0 or unit == 'PiB':
break
size /= 1024.0
return f"{size:.{decimal_places}f} {unit}"
一个拥有你所寻找的所有功能的库似乎是人性化的。Humanize.naturalsize()似乎可以做您所寻找的所有事情。
示例代码(python 3.10)
import humanize
disk_sizes_list = [1, 100, 999, 1000,1024, 2000,2048, 3000, 9999, 10000, 2048000000, 9990000000, 9000000000000000000000]
for size in disk_sizes_list:
natural_size = humanize.naturalsize(size)
binary_size = humanize.naturalsize(size, binary=True)
print(f" {natural_size} \t| {binary_size}\t|{size}")
输出
1 Byte | 1 Byte |1
100 Bytes | 100 Bytes |100
999 Bytes | 999 Bytes |999
1.0 kB | 1000 Bytes |1000
1.0 kB | 1.0 KiB |1024
2.0 kB | 2.0 KiB |2000
2.0 kB | 2.0 KiB |2048
3.0 kB | 2.9 KiB |3000
10.0 kB | 9.8 KiB |9999
10.0 kB | 9.8 KiB |10000
2.0 GB | 1.9 GiB |2048000000
10.0 GB | 9.3 GiB |9990000000
9.0 ZB | 7.6 ZiB |9000000000000000000000
下面是一个使用while的选项:
def number_format(n):
n2, n3 = n, 0
while n2 >= 1e3:
n2 /= 1e3
n3 += 1
return '%.3f' % n2 + ('', ' k', ' M', ' G')[n3]
s = number_format(9012345678)
print(s == '9.012 G')
https://docs.python.org/reference/compound_stmts.html#while
重复作为匆匆.filesize()替代方案提供的代码段,下面的代码段根据所使用的前缀给出不同的精度数字。它不像某些片段那样简洁,但我喜欢这样的结果。
def human_size(size_bytes):
"""
format a size in bytes into a 'human' file size, e.g. bytes, KB, MB, GB, TB, PB
Note that bytes/KB will be reported in whole numbers but MB and above will have greater precision
e.g. 1 byte, 43 bytes, 443 KB, 4.3 MB, 4.43 GB, etc
"""
if size_bytes == 1:
# because I really hate unnecessary plurals
return "1 byte"
suffixes_table = [('bytes',0),('KB',0),('MB',1),('GB',2),('TB',2), ('PB',2)]
num = float(size_bytes)
for suffix, precision in suffixes_table:
if num < 1024.0:
break
num /= 1024.0
if precision == 0:
formatted_size = "%d" % num
else:
formatted_size = str(round(num, ndigits=precision))
return "%s %s" % (formatted_size, suffix)