在c++中是否有跨平台的方法来获取当前的日期和时间?
当前回答
ctime std::
为什么到目前为止只有评论提到了ctime ?
#include <ctime>
#include <iostream>
int main()
{
std::time_t result = std::time(nullptr);
std::cout << std::ctime(&result);
}
输出
周二 12月 27 5:21:29 PM 2011
其他回答
是的,你可以这样做的格式规则指定的当前填充区域:
#include <iostream>
#include <iterator>
#include <string>
class timefmt
{
public:
timefmt(std::string fmt)
: format(fmt) { }
friend std::ostream& operator <<(std::ostream &, timefmt const &);
private:
std::string format;
};
std::ostream& operator <<(std::ostream& os, timefmt const& mt)
{
std::ostream::sentry s(os);
if (s)
{
std::time_t t = std::time(0);
std::tm const* tm = std::localtime(&t);
std::ostreambuf_iterator<char> out(os);
std::use_facet<std::time_put<char>>(os.getloc())
.put(out, os, os.fill(),
tm, &mt.format[0], &mt.format[0] + mt.format.size());
}
os.width(0);
return os;
}
int main()
{
std::cout << timefmt("%c");
}
输出:周五9月6日20:33:31 2013
ffead-cpp为各种任务提供了多个实用程序类,其中一个类是Date类,它提供了从Date操作到日期算术的许多特性,还有一个Timer类用于计时操作。你也可以看看。
我发现这个链接对我的实现非常有用: c++日期和时间
下面是我在实现中使用的代码,以获得清晰的“YYYYMMDD HHMMSS”输出格式。参数in用于在UTC和本地时间之间切换。您可以轻松地修改我的代码以满足您的需要。
#include <iostream>
#include <ctime>
using namespace std;
/**
* This function gets the current date time
* @param useLocalTime true if want to use local time, default to false (UTC)
* @return current datetime in the format of "YYYYMMDD HHMMSS"
*/
string getCurrentDateTime(bool useLocalTime) {
stringstream currentDateTime;
// current date/time based on current system
time_t ttNow = time(0);
tm * ptmNow;
if (useLocalTime)
ptmNow = localtime(&ttNow);
else
ptmNow = gmtime(&ttNow);
currentDateTime << 1900 + ptmNow->tm_year;
//month
if (ptmNow->tm_mon < 9)
//Fill in the leading 0 if less than 10
currentDateTime << "0" << 1 + ptmNow->tm_mon;
else
currentDateTime << (1 + ptmNow->tm_mon);
//day
if (ptmNow->tm_mday < 10)
currentDateTime << "0" << ptmNow->tm_mday << " ";
else
currentDateTime << ptmNow->tm_mday << " ";
//hour
if (ptmNow->tm_hour < 10)
currentDateTime << "0" << ptmNow->tm_hour;
else
currentDateTime << ptmNow->tm_hour;
//min
if (ptmNow->tm_min < 10)
currentDateTime << "0" << ptmNow->tm_min;
else
currentDateTime << ptmNow->tm_min;
//sec
if (ptmNow->tm_sec < 10)
currentDateTime << "0" << ptmNow->tm_sec;
else
currentDateTime << ptmNow->tm_sec;
return currentDateTime.str();
}
输出(UTC, EST):
20161123 000454
20161122 190454
我需要一种方法在每次更新列表时插入当前日期-时间。 简单地说,这似乎很有效。
#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;
int main()
{ //initialize variables
time_t now;
//blah..blah
/*each time I want the updated stamp*/
now=time(0);cout<<ctime(&now)<<"blah_blah";
}
这为我在Linux (RHEL)和Windows (x64)上编译,目标是g++和OpenMP:
#include <ctime>
#include <iostream>
#include <string>
#include <locale>
////////////////////////////////////////////////////////////////////////////////
//
// Reports a time-stamped update to the console; format is:
// Name: Update: Year-Month-Day_of_Month Hour:Minute:Second
//
////////////////////////////////////////////////////////////////////////////////
//
// [string] strName : name of the update object
// [string] strUpdate: update descripton
//
////////////////////////////////////////////////////////////////////////////////
void ReportTimeStamp(string strName, string strUpdate)
{
try
{
#ifdef _WIN64
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm tmStart;
localtime_s(&tmStart, &tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart.tm_year) << "-" << tmStart.tm_mon << "-" << tmStart.tm_mday << " " << tmStart.tm_hour << ":" << tmStart.tm_min << ":" << tmStart.tm_sec << "\n\n";
#else
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm* tmStart;
tmStart = localtime(&tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart->tm_year) << "-" << tmStart->tm_mon << "-" << tmStart->tm_mday << " " << tmStart->tm_hour << ":" << tmStart->tm_min << ":" << tmStart->tm_sec << "\n\n";
#endif
}
catch (exception ex)
{
cout << "ERROR [ReportTimeStamp] Exception Code: " << ex.what() << "\n";
}
return;
}