在c++中是否有跨平台的方法来获取当前的日期和时间?
当前回答
这适用于g++,我不确定这是否对你有帮助。 项目输出:
The current time is 11:43:41 am
The current date is 6-18-2015 June Wednesday
Day of month is 17 and the Month of year is 6,
also the day of year is 167 & our Weekday is 3.
The current year is 2015.
代码:
#include <ctime>
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
using namespace std;
const std::string currentTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%H:%M:%S %P", &tstruct);
return buf;
}
const std::string currentDate() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%B %A ", &tstruct);
return buf;
}
int main() {
cout << "\033[2J\033[1;1H";
std:cout << "The current time is " << currentTime() << std::endl;
time_t t = time(0); // get time now
struct tm * now = localtime( & t );
cout << "The current date is " << now->tm_mon + 1 << '-'
<< (now->tm_mday + 1) << '-'
<< (now->tm_year + 1900)
<< " " << currentDate() << endl;
cout << "Day of month is " << (now->tm_mday)
<< " and the Month of year is " << (now->tm_mon)+1 << "," << endl;
cout << "also the day of year is " << (now->tm_yday)
<< " & our Weekday is " << (now->tm_wday) << "." << endl;
cout << "The current year is " << (now->tm_year)+1900 << "."
<< endl;
return 0;
}
其他回答
auto time = std::time(nullptr);
std::cout << std::put_time(std::localtime(&time), "%F %T%z"); // ISO 8601 format.
使用std::time()或std::chrono::system_clock::now()(或其他时钟类型)获取当前时间。
std::put_time() (c++ 11)和strftime() (C)提供了很多格式化程序来输出这些时间。
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout
// ISO 8601: %Y-%m-%d %H:%M:%S, e.g. 2017-07-31 00:42:00+0200.
<< std::put_time(std::gmtime(&time), "%F %T%z") << '\n'
// %m/%d/%y, e.g. 07/31/17
<< std::put_time(std::gmtime(&time), "%D");
}
格式化程序的顺序很重要:
std::cout << std::put_time(std::gmtime(&time), "%c %A %Z") << std::endl;
// Mon Jul 31 00:00:42 2017 Monday GMT
std::cout << std::put_time(std::gmtime(&time), "%Z %c %A") << std::endl;
// GMT Mon Jul 31 00:00:42 2017 Monday
strftime()的格式化器类似:
char output[100];
if (std::strftime(output, sizeof(output), "%F", std::gmtime(&time))) {
std::cout << output << '\n'; // %Y-%m-%d, e.g. 2017-07-31
}
通常,大写格式器表示“完整版本”,小写格式器表示缩写(例如Y: 2017, Y: 17)。
区域设置改变输出:
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout << "undef: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_US.utf8"));
std::cout << "en_US: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_GB.utf8"));
std::cout << "en_GB: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("de_DE.utf8"));
std::cout << "de_DE: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ja_JP.utf8"));
std::cout << "ja_JP: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ru_RU.utf8"));
std::cout << "ru_RU: " << std::put_time(std::gmtime(&time), "%c");
}
可能的输出(Coliru,编译器浏览器):
undef: Tue Aug 1 08:29:30 2017
en_US: Tue 01 Aug 2017 08:29:30 AM GMT
en_GB: Tue 01 Aug 2017 08:29:30 GMT
de_DE: Di 01 Aug 2017 08:29:30 GMT
ja_JP: 2017年08月01日 08時29分30秒
ru_RU: Вт 01 авг 2017 08:29:30
我已经使用std::gmtime()转换为UTC。提供Std::localtime()来转换为本地时间。
注意,在其他答案中提到的asctime()/ctime()现在被标记为已弃用,strftime()应该是首选。
(给谷歌人)
还有Boost::date_time:
#include <boost/date_time/posix_time/posix_time.hpp>
boost::posix_time::ptime date_time = boost::posix_time::microsec_clock::universal_time();
#include <iostream>
#include <chrono>
#include <string>
#pragma warning(disable: 4996)
// Ver: C++ 17
// IDE: Visual Studio
int main() {
using namespace std;
using namespace chrono;
time_point tp = system_clock::now();
time_t tt = system_clock::to_time_t(tp);
cout << "Current time: " << ctime(&tt) << endl;
return 0;
}
localtime_s()版本:
#include <stdio.h>
#include <time.h>
int main ()
{
time_t current_time;
struct tm local_time;
time ( ¤t_time );
localtime_s(&local_time, ¤t_time);
int Year = local_time.tm_year + 1900;
int Month = local_time.tm_mon + 1;
int Day = local_time.tm_mday;
int Hour = local_time.tm_hour;
int Min = local_time.tm_min;
int Sec = local_time.tm_sec;
return 0;
}
下面是不弃用的现代c++解决方案,用于将时间戳作为std::string用于例如文件名:
std::string get_file_timestamp()
{
const auto now = std::chrono::system_clock::now();
const auto in_time_t = std::chrono::system_clock::to_time_t(now);
std::stringstream output_stream;
struct tm time_info;
const auto errno_value = localtime_s(&time_info, &in_time_t);
if(errno_value != 0)
{
throw std::runtime_error("localtime_s() failed: " + std::to_string(errno_value));
}
output_stream << std::put_time(&time_info, "%Y-%m-%d.%H_%M_%S");
return output_stream.str();
}
推荐文章
- 为什么这个结合赋值和相等检查的if语句返回true?
- cplusplus.com给出的错误、误解或坏建议是什么?
- 找出质数最快的算法是什么?
- 如何减去日期/时间在JavaScript?
- c++枚举类可以有方法吗?
- 将Date对象转换为日历对象
- 格式化IO函数(*printf / *scanf)中的转换说明符%i和%d之间的区别是什么?
- 将析构函数设为私有有什么用?
- main()中的Return语句vs exit()
- 为什么c#不提供c++风格的'friend'关键字?
- 将缺失的日期添加到熊猫数据框架中
- 如何防止ifelse()从日期对象转化为数字对象
- 在函数的签名中添加关键字
- 我如何在Visual Studio中预处理后看到C/ c++源文件?
- 为什么在标准容器中使用std::auto_ptr<>是错误的?