是的，尽管根据表的不同，I/O可能会很高，但我找到了一个解决方案。

SELECT *
INTO #temp
FROM table

ALTER TABLE #temp DROP COlUMN column_name

SELECT *
FROM #temp

如果你想排除一个字段的值，例如安全问题/敏感信息，你可以检索该列为空。

e.g.

SELECT *, NULL AS salary FROM users

您可以使用DESCRIBE my_table并使用其结果动态地生成SELECT语句。

只做

SELECT * FROM table WHERE whatever

然后用您最喜欢的编程语言php删除该列

while (($data = mysql_fetch_array($result, MYSQL_ASSOC)) !== FALSE) {
   unset($data["id"]);
   foreach ($data as $k => $v) { 
      echo"$v,";
   }      
}

也许我有一个解决Jan Koritak指出的矛盾的方法

SELECT CONCAT('SELECT ',
( SELECT GROUP_CONCAT(t.col)
FROM
(
    SELECT CASE
    WHEN COLUMN_NAME = 'eid' THEN NULL
    ELSE COLUMN_NAME
    END AS col 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'
) t
WHERE t.col IS NOT NULL) ,
' FROM employee' );

表:

SELECT table_name,column_name 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

table_name  column_name
employee    eid
employee    name_eid
employee    sal

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

查询结果:

'SELECT name_eid,sal FROM employee'

如果它总是相同的一列，那么你可以创建一个不包含它的视图。

否则，不，我不这么认为。