我找不到使用单一 16-octet TypedArray 和 DataView 的任何答案,所以我认为在 RFC 中创建版本 4 UUID 的下列解决方案将自行存在:

const uuid4 = () => {
    const ho = (n, p) => n.toString(16).padStart(p, 0); /// Return the hexadecimal text representation of number `n`, padded with zeroes to be of length `p`
    const data = crypto.getRandomValues(new Uint8Array(16)); /// Fill the buffer with random data
    data[6] = (data[6] & 0xf) | 0x40; /// Patch the 6th byte to reflect a version 4 UUID
    data[8] = (data[8] & 0x3f) | 0x80; /// Patch the 8th byte to reflect a variant 1 UUID (version 4 UUIDs are)
    const view = new DataView(data.buffer); /// Create a view backed by a 16-byte buffer
    return `${ho(view.getUint32(0), 8)}-${ho(view.getUint16(4), 4)}-${ho(view.getUint16(6), 4)}-${ho(view.getUint16(8), 4)}-${ho(view.getUint32(10), 8)}${ho(view.getUint16(14), 4)}`; /// Compile the canonical textual form from the array data
};

我更喜欢,因为:

它只依赖于标准 ECMAScript 平台的功能,在可能的情况下 - 这只是一个程序它只使用一个单一的泡沫,尽量减少数据的复制,这在理论上应该带来性能优势。

在写这篇文章时, getRandomValues 不是在 Node.js 中的加密对象中实施的东西,但是它具有相同的随机Bytes 功能,可以用来代替它。

ES6 样品

const guid=()=> {
  const s4=()=> Math.floor((1 + Math.random()) * 0x10000).toString(16).substring(1);     
  return `${s4() + s4()}-${s4()}-${s4()}-${s4()}-${s4() + s4() + s4()}`;
}

我想了解布罗法的答案,所以我扩展了它并添加了评论:

var uuid = function () {
    return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(
        /[xy]/g,
        function (match) {
            /*
            * Create a random nibble. The two clever bits of this code:
            *
            * - Bitwise operations will truncate floating point numbers
            * - For a bitwise OR of any x, x | 0 = x
            *
            * So:
            *
            * Math.random * 16
            *
            * creates a random floating point number
            * between 0 (inclusive) and 16 (exclusive) and
            *
            * | 0
            *
            * truncates the floating point number into an integer.
            */
            var randomNibble = Math.random() * 16 | 0;

            /*
            * Resolves the variant field. If the variant field (delineated
            * as y in the initial string) is matched, the nibble must
            * match the mask (where x is a do-not-care bit):
            *
            * 10xx
            *
            * This is achieved by performing the following operations in
            * sequence (where x is an intermediate result):
            *
            * - x & 0x3, which is equivalent to x % 3
            * - x | 0x8, which is equivalent to x + 8
            *
            * This results in a nibble between 8 inclusive and 11 exclusive,
            * (or 1000 and 1011 in binary), all of which satisfy the variant
            * field mask above.
            */
            var nibble = (match == 'y') ?
                (randomNibble & 0x3 | 0x8) :
                randomNibble;

            /*
            * Ensure the nibble integer is encoded as base 16 (hexadecimal).
            */
            return nibble.toString(16);
        }
    );
};

最好的方式:

function(
  a, b               // Placeholders
){
  for(               // Loop :)
      b = a = '';    // b - result , a - numeric variable
      a++ < 36;      //
      b += a*51&52   // If "a" is not 9 or 14 or 19 or 24
                  ?  //  return a random number or 4
           (
               a^15              // If "a" is not 15,
                  ?              // generate a random number from 0 to 15
               8^Math.random() *
               (a^20 ? 16 : 4)   // unless "a" is 20, in which case a random number from 8 to 11,
                  :
               4                 //  otherwise 4
           ).toString(16)
                  :
         '-'                     //  In other cases, (if "a" is 9,14,19,24) insert "-"
      );
  return b
 }

最小化:

function(a,b){for(b=a='';a++<36;b+=a*51&52?(a^15?8^Math.random()*(a^20?16:4):4).toString(16):'-');return b}

对于想要 RFC 4122 版本 4 符合速度考虑的解决方案的人(少数电话到 Math.random()):

var rand = Math.random; 函数 UUID() { var nbr, randStr = "; do { randStr += (nbr = rand()).toString(16).substr(3, 6); } 同时(randStr.length < 30); 返回( randStr.substr(0, 8) + "-" + randStr.substr(8, 4) + "-4" + randStr.substr(12, 3) + "-" + ((nbr*4♰0) +8).toString(16) + // [89ab] randStr.substr(15, 3) + "-" + rand

上面的功能应该在速度和随机性之间保持适当的平衡。

这可能对某人有用......

var d = new Date().valueOf();
var n = d.toString();
var result = '';
var length = 32;
var p = 0;
var chars = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';

for (var i = length; i > 0; --i){
    result += ((i & 1) && n.charAt(p) ? '<b>' + n.charAt(p) + '</b>' : chars[Math.floor(Math.random() * chars.length)]);
    if(i & 1) p++;
};

HTTPS://jsfiddle.net/j0evrdf1/1/