只是另一个更可读的变量,只有两个突变。

function uuid4()
{
  function hex (s, b)
  {
    return s +
      (b >>> 4   ).toString (16) +  // high nibble
      (b & 0b1111).toString (16);   // low nibble
  }

  let r = crypto.getRandomValues (new Uint8Array (16));

  r[6] = r[6] >>> 4 | 0b01000000; // Set type 4: 0100
  r[8] = r[8] >>> 3 | 0b10000000; // Set variant: 100

  return r.slice ( 0,  4).reduce (hex, '' ) +
         r.slice ( 4,  6).reduce (hex, '-') +
         r.slice ( 6,  8).reduce (hex, '-') +
         r.slice ( 8, 10).reduce (hex, '-') +
         r.slice (10, 16).reduce (hex, '-');
}

如果您只需要任何特定格式的随机 128 位序列,您可以使用:

function uuid() {
    return crypto.getRandomValues(new Uint32Array(4)).join('-');
}

这将返回像2350143528-4164020887-938913176-2513998651这样的东西。

使用 Blobs 的单行解决方案。

window.URL.createObjectURL(new Blob([])).substring(31);

最终值(31)取决于URL的长度。

编辑:

像Rinogo所建议的那样,一个更小而普遍的解决方案:

URL.createObjectURL(new Blob([])).substr(-36);

這只是一個概念,大多數人肯定可以以多種方式改進,但並不像我認為那樣緩慢。

总的来说,这个代码包含在毫秒内编码的黑客时间表(有某些黑客它给了12个数字,所以代码甚至在2527-06-24,但不是在5138-11-16之后工作),这意味着它是可编码的。

我知道这可能会缩短,性能提高,但我对结果感到高兴(除了MAC地址)。

目前Nanoseconds = () => { return nodeMode? process.hrtime.bigint() : BigInt(Date.now() * 1000000); } nodeFindMacAddress = () => { // 提取 MAC 地址 const 界面 = require('os').network 界面(); let result = null; for (index in interfaces) { let entry = interfaces[index]; entry.forEach(item => { if (item.mac!== '00:00:00:00:00:00') { result = '-'

使用:

let uniqueId = Date.now().toString(36) + Math.random().toString(36).substring(2);

document.getElementById(“独一无二”。innerHTML = Math.random().toString(36).substring(2) + (新日期()).getTime().toString(36); <div id="unique"> </div>

您可以通过添加更多数字来增加这个数字,但要创建100%独特的ID,您将需要使用全球计数器。

let u = Date.now().toString(16) + Math.random().toString(16) + '0'.repeat(16);
let guid = [u.substr(0,8), u.substr(8,4), '4000-8' + u.substr(13,3), u.substr(16,12)].join('-');

let u = Date.now().toString(16)+Math.random().toString(16)+'0'.repeat(16); let guid = [u.substr(0,8), u.substr(8,4), '4000-8' + u.substr(13,3), u.substr(16,12)].join('-'); document.getElementById("unique").innerHTML = guid; <div id="unique"> </div>

我想了解布罗法的答案,所以我扩展了它并添加了评论:

var uuid = function () {
    return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(
        /[xy]/g,
        function (match) {
            /*
            * Create a random nibble. The two clever bits of this code:
            *
            * - Bitwise operations will truncate floating point numbers
            * - For a bitwise OR of any x, x | 0 = x
            *
            * So:
            *
            * Math.random * 16
            *
            * creates a random floating point number
            * between 0 (inclusive) and 16 (exclusive) and
            *
            * | 0
            *
            * truncates the floating point number into an integer.
            */
            var randomNibble = Math.random() * 16 | 0;

            /*
            * Resolves the variant field. If the variant field (delineated
            * as y in the initial string) is matched, the nibble must
            * match the mask (where x is a do-not-care bit):
            *
            * 10xx
            *
            * This is achieved by performing the following operations in
            * sequence (where x is an intermediate result):
            *
            * - x & 0x3, which is equivalent to x % 3
            * - x | 0x8, which is equivalent to x + 8
            *
            * This results in a nibble between 8 inclusive and 11 exclusive,
            * (or 1000 and 1011 in binary), all of which satisfy the variant
            * field mask above.
            */
            var nibble = (match == 'y') ?
                (randomNibble & 0x3 | 0x8) :
                randomNibble;

            /*
            * Ensure the nibble integer is encoded as base 16 (hexadecimal).
            */
            return nibble.toString(16);
        }
    );
};