var uuid = function() {
    var buf = new Uint32Array(4);
    window.crypto.getRandomValues(buf);
    var idx = -1;
    return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function(c) {
        idx++;
        var r = (buf[idx>>3] >> ((idx%8)*4))&15;
        var v = c == 'x' ? r : (r&0x3|0x8);
        return v.toString(16);
    });
};

这个版本是基于Briguy37的答案和一些Bitwise运营商从泡沫中提取Nibble大小的窗户。

它应该遵守RFC类型4(随机)方案,因为我上次遇到麻烦与Java的UUID不符合的UUID。

我找不到使用单一 16-octet TypedArray 和 DataView 的任何答案,所以我认为在 RFC 中创建版本 4 UUID 的下列解决方案将自行存在:

const uuid4 = () => {
    const ho = (n, p) => n.toString(16).padStart(p, 0); /// Return the hexadecimal text representation of number `n`, padded with zeroes to be of length `p`
    const data = crypto.getRandomValues(new Uint8Array(16)); /// Fill the buffer with random data
    data[6] = (data[6] & 0xf) | 0x40; /// Patch the 6th byte to reflect a version 4 UUID
    data[8] = (data[8] & 0x3f) | 0x80; /// Patch the 8th byte to reflect a variant 1 UUID (version 4 UUIDs are)
    const view = new DataView(data.buffer); /// Create a view backed by a 16-byte buffer
    return `${ho(view.getUint32(0), 8)}-${ho(view.getUint16(4), 4)}-${ho(view.getUint16(6), 4)}-${ho(view.getUint16(8), 4)}-${ho(view.getUint32(10), 8)}${ho(view.getUint16(14), 4)}`; /// Compile the canonical textual form from the array data
};

我更喜欢,因为:

它只依赖于标准 ECMAScript 平台的功能,在可能的情况下 - 这只是一个程序它只使用一个单一的泡沫,尽量减少数据的复制,这在理论上应该带来性能优势。

在写这篇文章时, getRandomValues 不是在 Node.js 中的加密对象中实施的东西,但是它具有相同的随机Bytes 功能,可以用来代替它。

  // RFC 4122
  //
  // A UUID is 128 bits long
  //
  // String representation is five fields of 4, 2, 2, 2, and 6 bytes.
  // Fields represented as lowercase, zero-filled, hexadecimal strings, and
  // are separated by dash characters
  //
  // A version 4 UUID is generated by setting all but six bits to randomly
  // chosen values
  var uuid = [
    Math.random().toString(16).slice(2, 10),
    Math.random().toString(16).slice(2, 6),

    // Set the four most significant bits (bits 12 through 15) of the
    // time_hi_and_version field to the 4-bit version number from Section
    // 4.1.3
    (Math.random() * .0625 /* 0x.1 */ + .25 /* 0x.4 */).toString(16).slice(2, 6),

    // Set the two most significant bits (bits 6 and 7) of the
    // clock_seq_hi_and_reserved to zero and one, respectively
    (Math.random() * .25 /* 0x.4 */ + .5 /* 0x.8 */).toString(16).slice(2, 6),

    Math.random().toString(16).slice(2, 14)].join('-');

这创建了一个版本 4 UUID (创建于假冒随机数字):

function uuid()
{
   var chars = '0123456789abcdef'.split('');

   var uuid = [], rnd = Math.random, r;
   uuid[8] = uuid[13] = uuid[18] = uuid[23] = '-';
   uuid[14] = '4'; // version 4

   for (var i = 0; i < 36; i++)
   {
      if (!uuid[i])
      {
         r = 0 | rnd()*16;

         uuid[i] = chars[(i == 19) ? (r & 0x3) | 0x8 : r & 0xf];
      }
   }

   return uuid.join('');
}

下面是产生的 UUID 的样本:

682db637-0f31-4847-9cdf-25ba9613a75c
97d19478-3ab2-4aa1-b8cc-a1c3540f54aa
2eed04c9-2692-456d-a0fd-51012f947136

下面是2011年10月9日的解决方案,由用户在https://gist.github.com/982883上发表评论:

UUIDv4 = function b(a){return a?(a^Math.random()*16>>a/4).toString(16):([1e7]+-1e3+-4e3+-8e3+-1e11).replace(/[018]/g,b)}

这实现了与当前最高评级的答案相同的目标,但在50比以更少的比特中,利用强迫性、回报性和曝光性评级。

UUIDv4 =

function b(
  a // placeholder
){
  return a // if the placeholder was passed, return
    ? ( // a random number from 0 to 15
      a ^ // unless b is 8,
      Math.random() // in which case
      * 16 // a random number from
      >> a/4 // 8 to 11
      ).toString(16) // in hexadecimal
    : ( // or otherwise a concatenated string:
      [1e7] + // 10000000 +
      -1e3 + // -1000 +
      -4e3 + // -4000 +
      -8e3 + // -80000000 +
      -1e11 // -100000000000,
      ).replace( // replacing
        /[018]/g, // zeroes, ones, and eights with
        b // random hex digits
      )
}

var guid = createMyGuid();

function createMyGuid()  
{  
   return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function(c) {  
      var r = Math.random()*16|0, v = c === 'x' ? r : (r&0x3|0x8);  
      return v.toString(16);  
   });  
}