这里有一个示例代码,但是它开始讨论毫秒/纳秒的问题。

同样的问题出现在MSDN上,从c#的Unix时代开始。

这是我目前得到的:

public Double CreatedEpoch
{
  get
  {
    DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
    TimeSpan span = (this.Created.ToLocalTime() - epoch);
    return span.TotalSeconds;
  }
  set
  {
    DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
    this.Created = epoch.AddSeconds(value);
  }
}

当前回答

以下是你需要的:

public static DateTime UnixTimeStampToDateTime( double unixTimeStamp )
{
    // Unix timestamp is seconds past epoch
    DateTime dateTime = new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc);
    dateTime = dateTime.AddSeconds( unixTimeStamp ).ToLocalTime();
    return dateTime;
}

或者,对于Java(这是不同的,因为时间戳是以毫秒为单位的,而不是秒):

public static DateTime JavaTimeStampToDateTime( double javaTimeStamp )
{
    // Java timestamp is milliseconds past epoch
    DateTime dateTime = new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc);
    dateTime = dateTime.AddMilliseconds( javaTimeStamp ).ToLocalTime();
    return dateTime;
}

其他回答

看到IdentityModel。EpochTimeExtensions

public static class EpochTimeExtensions
{
    /// <summary>
    /// Converts the given date value to epoch time.
    /// </summary>
    public static long ToEpochTime(this DateTime dateTime)
    {
        var date = dateTime.ToUniversalTime();
        var ticks = date.Ticks - new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc).Ticks;
        var ts = ticks / TimeSpan.TicksPerSecond;
        return ts;
    }

    /// <summary>
    /// Converts the given date value to epoch time.
    /// </summary>
    public static long ToEpochTime(this DateTimeOffset dateTime)
    {
        var date = dateTime.ToUniversalTime();
        var ticks = date.Ticks - new DateTimeOffset(1970, 1, 1, 0, 0, 0, TimeSpan.Zero).Ticks;
        var ts = ticks / TimeSpan.TicksPerSecond;
        return ts;
    }

    /// <summary>
    /// Converts the given epoch time to a <see cref="DateTime"/> with <see cref="DateTimeKind.Utc"/> kind.
    /// </summary>
    public static DateTime ToDateTimeFromEpoch(this long intDate)
    {
        var timeInTicks = intDate * TimeSpan.TicksPerSecond;
        return new DateTime(1970, 1, 1, 0, 0, 0, 0, DateTimeKind.Utc).AddTicks(timeInTicks);
    }

    /// <summary>
    /// Converts the given epoch time to a UTC <see cref="DateTimeOffset"/>.
    /// </summary>
    public static DateTimeOffset ToDateTimeOffsetFromEpoch(this long intDate)
    {
        var timeInTicks = intDate * TimeSpan.TicksPerSecond;
        return new DateTimeOffset(1970, 1, 1, 0, 0, 0, TimeSpan.Zero).AddTicks(timeInTicks);
    }
}

在。net 4.6中,你可以这样做:

var dateTime = DateTimeOffset.FromUnixTimeSeconds(unixDateTime).DateTime;

DateTime到UNIX时间戳:

public static double DateTimeToUnixTimestamp(DateTime dateTime)
{
    return (TimeZoneInfo.ConvertTimeToUtc(dateTime) - 
           new DateTime(1970, 1, 1, 0, 0, 0, 0, System.DateTimeKind.Utc)).TotalSeconds;
}

如果您需要高于毫秒的精度,请小心!

. net (v4.6)方法(例如fromunixtimemillisecseconds)不提供这种精度。

AddSeconds和AddMilliseconds还截断了double中的微秒。

这些版本有很高的精度:

Unix -> DateTime

public static DateTime UnixTimestampToDateTime(double unixTime)
{
    DateTime unixStart = new DateTime(1970, 1, 1, 0, 0, 0, 0, System.DateTimeKind.Utc);
    long unixTimeStampInTicks = (long) (unixTime * TimeSpan.TicksPerSecond);
    return new DateTime(unixStart.Ticks + unixTimeStampInTicks, System.DateTimeKind.Utc);
}

日期-> Unix

public static double DateTimeToUnixTimestamp(DateTime dateTime)
{
    DateTime unixStart = new DateTime(1970, 1, 1, 0, 0, 0, 0, System.DateTimeKind.Utc);
    long unixTimeStampInTicks = (dateTime.ToUniversalTime() - unixStart).Ticks;
    return (double) unixTimeStampInTicks / TimeSpan.TicksPerSecond;
}

我找到了正确的答案,只是通过比较转换到1/1/1970 w/o当地时间调整;

DateTime date = new DateTime(2011, 4, 1, 12, 0, 0, 0);
DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0);
TimeSpan span = (date - epoch);
double unixTime =span.TotalSeconds;