给定这个函数,我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
给定这个函数,我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
当前回答
这是我的两个版本的随机十六进制代码生成器。
/* Slowest but shortest. */
"#000000".replace(/0/g,function(){return (~~(Math.random()*16)).toString(16);});
/* Good performance with small size. */
"#"+(function(a,b){while(a--){b+=""+(~~(Math.random()*16)).toString(16);} return b;})(6,"");
/* Remy Sharp provided one that's the fastest but a little bit too long */
(function(h){return '#000000'.substr(0,7-h.length)+h})((~~(Math.random()*(1<<24))).toString(16))
其他回答
这个函数在两个方面超越了其他答案:
它试图生成尽可能不同的颜色 20种颜色中哪一种与欧几里得距离最远 其他的都在HSV锥内。
它允许你限制色调, 饱和度,或值范围,但它仍然试图选择颜色作为 在这个范围内尽可能的不同。
它不是超级高效,但对于合理的值(谁甚至可以轻松地区分100种颜色?)够快了。
请参阅 JSFiddle
/**
* Generates a random palette of HSV colors. Attempts to pick colors
* that are as distinct as possible within the desired HSV range.
*
* @param {number} [options.numColors=10] - the number of colors to generate
* @param {number[]} [options.hRange=[0,1]] - the maximum range for generated hue
* @param {number[]} [options.sRange=[0,1]] - the maximum range for generated saturation
* @param {number[]} [options.vRange=[0,1]] - the maximum range for generated value
* @param {number[][]}[options.exclude=[[0,0,0],[0,0,1]]] - colors to exclude
*
* @returns {number[][]} an array of HSV colors (each HSV color
* is a [hue, saturation, value] array)
*/
function randomHSVPalette(options) {
function random(min, max) {
return min + Math.random() * (max - min);
}
function HSVtoXYZ(hsv) {
var h = hsv[0];
var s = hsv[1];
var v = hsv[2];
var angle = h * Math.PI * 2;
return [Math.sin(angle) * s * v,
Math.cos(angle) * s * v,
v];
}
function distSq(a, b) {
var dx = a[0] - b[0];
var dy = a[1] - b[1];
var dz = a[2] - b[2];
return dx * dx + dy * dy + dz * dz;
}
if (!options) {
options = {};
}
var numColors = options.numColors || 10;
var hRange = options.hRange || [0, 1];
var sRange = options.sRange || [0, 1];
var vRange = options.vRange || [0, 1];
var exclude = options.exclude || [[0, 0, 0], [0, 0, 1]];
var points = exclude.map(HSVtoXYZ);
var result = [];
while (result.length < numColors) {
var bestHSV;
var bestXYZ;
var bestDist = 0;
for (var i = 0; i < 20; i++) {
var hsv = [random(hRange[0], hRange[1]), random(sRange[0], sRange[1]), random(vRange[0], vRange[1])];
var xyz = HSVtoXYZ(hsv);
var minDist = 10;
points.forEach(function(point) {
minDist = Math.min(minDist, distSq(xyz, point));
});
if (minDist > bestDist) {
bestHSV = hsv;
bestXYZ = xyz;
bestDist = minDist;
}
}
points.push(bestXYZ);
result.push(bestHSV);
}
return result;
}
function HSVtoRGB(hsv) {
var h = hsv[0];
var s = hsv[1];
var v = hsv[2];
var i = ~~(h * 6);
var f = h * 6 - i;
var p = v * (1 - s);
var q = v * (1 - f * s);
var t = v * (1 - (1 - f) * s);
v = ~~(255 * v);
p = ~~(255 * p);
q = ~~(255 * q);
t = ~~(255 * t);
switch (i % 6) {
case 0: return [v, t, p];
case 1: return [q, v, p];
case 2: return [p, v, t];
case 3: return [p, q, v];
case 4: return [t, p, v];
case 5: return [v, p, q];
}
}
function RGBtoCSS(rgb) {
var r = rgb[0];
var g = rgb[1];
var b = rgb[2];
var rgb = (r << 16) + (g << 8) + b;
return '#' + ('000000' + rgb.toString(16)).slice(-6);
}
下面是@Anatoliy提供的解决方案。
我只需要生成浅色(作为背景),所以我使用了三个字母(#AAA)格式:
function get_random_color() {
var letters = 'ABCDE'.split('');
var color = '#';
for (var i=0; i<3; i++ ) {
color += letters[Math.floor(Math.random() * letters.length)];
}
return color;
}
许多答案调用Math.random()的次数比必需的要多。或者他们希望这个数字的十六进制表示,有六个字符。
首先将随机浮点数乘以范围[0,0xffffff + 1)。现在我们的数字有了0xRRRRRR的形式和一些变化,这是一个有24位有效位的数字。一次读取4位,并使用该随机数[0,15]并在查找时将其转换为匹配的十六进制字符。
function randomColor() {
var lookup = "0123456789abcdef";
var seed = Math.random() * 0x1000000;
return (
"#" +
lookup[(seed & 0xf00000) >> 20] +
lookup[(seed & 0x0f0000) >> 16] +
lookup[(seed & 0x00f000) >> 12] +
lookup[(seed & 0x000f00) >> 8] +
lookup[(seed & 0x0000f0) >> 4] +
lookup[seed & 0x00000f]
);
};
谁能打败它?
'#' + Math.random().toString(16).substr(-6);
它保证一直工作:http://jsbin.com/OjELIfo/2/edit
根据eterps的注释,如果随机颜色的十六进制表示非常短(0.730224609375 => 0.baf),上面的代码仍然可以生成更短的字符串。
这段代码应该在所有情况下工作:
function makeRandomColor(){
var c = '';
while (c.length < 7) {
c += (Math.random()).toString(16).substr(-6).substr(-1)
}
return '#' + c;
}
使用getRandomColor()代替“#0000FF”:
function getRandomColor() { var letters = '0123456789ABCDEF'; var color = '#'; for (var i = 0; i < 6; i++) { color += letters[Math.floor(Math.random() * 16)]; } return color; } function setRandomColor() { $("#colorpad").css("background-color", getRandomColor()); } <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="colorpad" style="width:300px;height:300px;background-color:#000"> </div> <button onclick="setRandomColor()">Random Color</button>