给定这个函数,我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
给定这个函数,我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
当前回答
使用getRandomColor()代替“#0000FF”:
function getRandomColor() { var letters = '0123456789ABCDEF'; var color = '#'; for (var i = 0; i < 6; i++) { color += letters[Math.floor(Math.random() * 16)]; } return color; } function setRandomColor() { $("#colorpad").css("background-color", getRandomColor()); } <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="colorpad" style="width:300px;height:300px;background-color:#000"> </div> <button onclick="setRandomColor()">Random Color</button>
其他回答
谁能打败它?
'#' + Math.random().toString(16).substr(-6);
它保证一直工作:http://jsbin.com/OjELIfo/2/edit
根据eterps的注释,如果随机颜色的十六进制表示非常短(0.730224609375 => 0.baf),上面的代码仍然可以生成更短的字符串。
这段代码应该在所有情况下工作:
function makeRandomColor(){
var c = '';
while (c.length < 7) {
c += (Math.random()).toString(16).substr(-6).substr(-1)
}
return '#' + c;
}
在这种情况下,我喜欢parseInt:
parseInt(Math.random()*0xFFFFFFFF).toString(16)
另一个随机颜色生成器:
var randomColor;
randomColor = Math.random() * 0x1000000; // 0 < randomColor < 0x1000000 (randomColor is a float)
randomColor = Math.floor(randomColor); // 0 < randomColor <= 0xFFFFFF (randomColor is an integer)
randomColor = randomColor.toString(16); // hex representation randomColor
randomColor = ("000000" + randomColor).slice(-6); // leading zeros added
randomColor = "#" + randomColor; // # added
下面是对这个问题的另一种看法。
我的目标是创造充满活力和独特的颜色。为了确保颜色的不同,我避免使用随机生成器,并从彩虹中选择“均匀间隔”的颜色。
这非常适合在谷歌map中创建具有最佳“唯一性”(即没有两个标记具有相似的颜色)的弹出式标记。
/**
* @param numOfSteps: Total number steps to get color, means total colors
* @param step: The step number, means the order of the color
*/
function rainbow(numOfSteps, step) {
// This function generates vibrant, "evenly spaced" colours (i.e. no clustering). This is ideal for creating easily distinguishable vibrant markers in Google Maps and other apps.
// Adam Cole, 2011-Sept-14
// HSV to RBG adapted from: http://mjijackson.com/2008/02/rgb-to-hsl-and-rgb-to-hsv-color-model-conversion-algorithms-in-javascript
var r, g, b;
var h = step / numOfSteps;
var i = ~~(h * 6);
var f = h * 6 - i;
var q = 1 - f;
switch(i % 6){
case 0: r = 1; g = f; b = 0; break;
case 1: r = q; g = 1; b = 0; break;
case 2: r = 0; g = 1; b = f; break;
case 3: r = 0; g = q; b = 1; break;
case 4: r = f; g = 0; b = 1; break;
case 5: r = 1; g = 0; b = q; break;
}
var c = "#" + ("00" + (~ ~(r * 255)).toString(16)).slice(-2) + ("00" + (~ ~(g * 255)).toString(16)).slice(-2) + ("00" + (~ ~(b * 255)).toString(16)).slice(-2);
return (c);
}
如果您希望看到这看起来像在行动,请参阅简单JavaScript彩虹颜色生成器谷歌地图标记。
我认为第一个回答是最简洁/有用的,但我只是写了一个初学者可能更容易理解的回答。
function randomHexColor(){
var hexColor=[]; //new Array()
hexColor[0] = "#"; //first value of array needs to be hash tag for hex color val, could also prepend this later
for (i = 1; i < 7; i++)
{
var x = Math.floor((Math.random()*16)); //Tricky: Hex has 16 numbers, but 0 is one of them
if (x >=10 && x <= 15) //hex:0123456789ABCDEF, this takes care of last 6
{
switch(x)
{
case 10: x="a"
break;
case 11: x="b"
break;
case 12: x="c"
break;
case 13: x="d"
break;
case 14: x="e"
break;
case 15: x="f"
break;
}
}
hexColor[i] = x;
}
var cString = hexColor.join(""); //this argument for join method ensures there will be no separation with a comma
return cString;
}