在Java中,当有人问:

什么是多态性?

重载或重写是可以接受的答案吗?

我认为事情远不止如此。

如果你有一个抽象基类,它定义了一个没有实现的方法,并且你在子类中定义了这个方法,这仍然是覆盖的吗?

我认为超负荷肯定不是正确的答案。


当前回答

多态性是类实例的一种能力,它的行为就像它是其继承树中另一个类的实例一样,通常是它的祖先类之一。例如,在Java中,所有的类都继承自Object。因此,您可以创建Object类型的变量,并将任何类的实例分配给它。

An override is a type of function which occurs in a class which inherits from another class. An override function "replaces" a function inherited from the base class, but does so in such a way that it is called even when an instance of its class is pretending to be a different type through polymorphism. Referring to the previous example, you could define your own class and override the toString() function. Because this function is inherited from Object, it will still be available if you copy an instance of this class into an Object-type variable. Normally, if you call toString() on your class while it is pretending to be an Object, the version of toString which will actually fire is the one defined on Object itself. However, because the function is an override, the definition of toString() from your class is used even when the class instance's true type is hidden behind polymorphism.

重载是定义具有相同名称但具有不同参数的多个方法的操作。它与覆盖或多态性无关。

其他回答

多态性就其意义而言更有可能……java中的override

这都是关于同一个对象在不同情况下的不同行为(在编程方式中…你可以调用不同的参数)

我认为下面的例子会帮助你理解……虽然它不是纯java代码…

     public void See(Friend)
     {
        System.out.println("Talk");
     }

但是如果我们改变参数…行为将会改变…

     public void See(Enemy)
     {
        System.out.println("Run");
     }

人(这里的“对象”)是一样的……

你说得对,超载不是解决问题的办法。

两者都不是最重要的。覆盖是获得多态性的方法。多态性是对象根据其类型改变行为的能力。当显示多态的对象的调用者不知道该对象是什么具体类型时,最能说明这一点。

具体地说重载或重写并没有给出全貌。多态性就是对象根据其类型专门化其行为的能力。

我不同意这里的一些答案,因为重载是一种多态形式(参数多态),在这种情况下,具有相同名称的方法可以具有不同的行为,给出不同的参数类型。一个很好的例子是操作符重载。您可以定义“+”来接受不同类型的参数——例如字符串或int型——并且基于这些类型,“+”将具有不同的行为。

多态性还包括继承和重写方法,尽管它们在基类型中可以是抽象的或虚拟的。在基于继承的多态性方面,Java只支持单个类继承,将其多态行为限制为单个基类型链。Java支持多个接口的实现,这是另一种形式的多态行为。

多态性是类实例的一种能力,它的行为就像它是其继承树中另一个类的实例一样,通常是它的祖先类之一。例如,在Java中,所有的类都继承自Object。因此,您可以创建Object类型的变量,并将任何类的实例分配给它。

An override is a type of function which occurs in a class which inherits from another class. An override function "replaces" a function inherited from the base class, but does so in such a way that it is called even when an instance of its class is pretending to be a different type through polymorphism. Referring to the previous example, you could define your own class and override the toString() function. Because this function is inherited from Object, it will still be available if you copy an instance of this class into an Object-type variable. Normally, if you call toString() on your class while it is pretending to be an Object, the version of toString which will actually fire is the one defined on Object itself. However, because the function is an override, the definition of toString() from your class is used even when the class instance's true type is hidden behind polymorphism.

重载是定义具有相同名称但具有不同参数的多个方法的操作。它与覆盖或多态性无关。

import java.io.IOException;

class Super {

    protected Super getClassName(Super s) throws IOException {
        System.out.println(this.getClass().getSimpleName() + " - I'm parent");
        return null;
    }

}

class SubOne extends Super {

    @Override
    protected Super getClassName(Super s)  {
        System.out.println(this.getClass().getSimpleName() + " - I'm Perfect Overriding");
        return null;
    }

}

class SubTwo extends Super {

    @Override
    protected Super getClassName(Super s) throws NullPointerException {
        System.out.println(this.getClass().getSimpleName() + " - I'm Overriding and Throwing Runtime Exception");
        return null;
    }

}

class SubThree extends Super {

    @Override
    protected SubThree getClassName(Super s) {
        System.out.println(this.getClass().getSimpleName()+ " - I'm Overriding and Returning SubClass Type");
        return null;
    }

}

class SubFour extends Super {

    @Override
    protected Super getClassName(Super s) throws IOException {
        System.out.println(this.getClass().getSimpleName()+ " - I'm Overriding and Throwing Narrower Exception ");
        return null;
    }

}

class SubFive extends Super {

    @Override
    public Super getClassName(Super s) {
        System.out.println(this.getClass().getSimpleName()+ " - I'm Overriding and have broader Access ");
        return null;
    }

}

class SubSix extends Super {

    public Super getClassName(Super s, String ol) {
        System.out.println(this.getClass().getSimpleName()+ " - I'm Perfect Overloading ");
        return null;
    }

}

class SubSeven extends Super {

    public Super getClassName(SubSeven s) {
        System.out.println(this.getClass().getSimpleName()+ " - I'm Perfect Overloading because Method signature (Argument) changed.");
        return null;
    }

}

public class Test{

    public static void main(String[] args) throws Exception {

        System.out.println("Overriding\n");

        Super s1 = new SubOne(); s1.getClassName(null);

        Super s2 = new SubTwo(); s2.getClassName(null);

        Super s3 = new SubThree(); s3.getClassName(null);

        Super s4 = new SubFour(); s4.getClassName(null);

        Super s5 = new SubFive(); s5.getClassName(null);

        System.out.println("Overloading\n");

        SubSix s6 = new SubSix(); s6.getClassName(null, null);

        s6 = new SubSix(); s6.getClassName(null);

        SubSeven s7 = new SubSeven(); s7.getClassName(s7);

        s7 = new SubSeven(); s7.getClassName(new Super());

    }
}