我已经开发了一个随机字符串生成器,但它的行为并不像我所希望的那样。我的目标是能够运行两次,并生成两个不同的四字符随机字符串。但是,它只生成一个四个字符的随机字符串两次。

下面是代码和输出示例:

private string RandomString(int size)
{
    StringBuilder builder = new StringBuilder();
    Random random = new Random();
    char ch;
    for (int i = 0; i < size; i++)
    {
        ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));                 
        builder.Append(ch);
    }

    return builder.ToString();
}

// get 1st random string 
string Rand1 = RandomString(4);

// get 2nd random string 
string Rand2 = RandomString(4);

// create full rand string
string docNum = Rand1 + "-" + Rand2;

...输出如下:UNTE-UNTE ...但它应该看起来像这个UNTE-FWNU

如何确保两个明显随机的字符串?


当前回答

你好,你可以使用WordGenerator或LoremIpsumGenerator从MMLib。RapidPrototyping nuget package。

using MMLib.RapidPrototyping.Generators;
public void WordGeneratorExample()
{
   WordGenerator generator = new WordGenerator();
   var randomWord = generator.Next();

   Console.WriteLine(randomWord);
} 

Nuget网站 Codeplex项目网站

其他回答

另一个样本(在vs2013中测试):

    Random R = new Random();
    public static string GetRandomString(int Length)
    {
        char[] ArrRandomChar = new char[Length];
        for (int i = 0; i < Length; i++)
            ArrRandomChar[i] = (char)('a' + R.Next(0, 26));
        return new string(ArrRandomChar);
    }

    string D = GetRandomString(12);

我自己实现的。

字符串生成器的另一个版本。简单,没有花哨的数学和神奇的数字。而是用一些神奇的字符串来指定允许的字符。

更新: 我将generator设置为静态的,因此当多次调用时,它将不会返回相同的字符串。然而,此代码不是线程安全的,并且绝对不是加密安全的。

对于密码生成,应该使用System.Security.Cryptography.RNGCryptoServiceProvider。

private Random _random = new Random(Environment.TickCount);

public string RandomString(int length)
{
    string chars = "0123456789abcdefghijklmnopqrstuvwxyz";
    StringBuilder builder = new StringBuilder(length);

    for (int i = 0; i < length; ++i)
        builder.Append(chars[_random.Next(chars.Length)]);

    return builder.ToString();
}
public static class StringHelpers
{
    public static readonly Random rnd = new Random();

    public static readonly string EnglishAlphabet = "abcdefghijklmnopqrstuvwxyz";
    public static readonly string RussianAlphabet = "абвгдеёжзийклмнопрстуфхцчшщъыьэюя";

    public static unsafe string GenerateRandomUTF8String(int length, string alphabet)
    {
        if (length <= 0)
            return String.Empty;
        if (string.IsNullOrWhiteSpace(alphabet))
            throw new ArgumentNullException("alphabet");

        byte[] randomBytes = rnd.NextBytes(length);

        string s = new string(alphabet[0], length);

        fixed (char* p = s)
        {
            for (int i = 0; i < s.Length; i++)
            {
                *(p + i) = alphabet[randomBytes[i] % alphabet.Length];
            }
        }
        return s;
    }

    public static unsafe string GenerateRandomUTF8String(int length, params UnicodeCategory[] unicodeCategories)
    {
        if (length <= 0)
            return String.Empty;
        if (unicodeCategories == null)
            throw new ArgumentNullException("unicodeCategories");
        if (unicodeCategories.Length == 0)
            return rnd.NextString(length);

        byte[] randomBytes = rnd.NextBytes(length);

        string s = randomBytes.ConvertToString();
        fixed (char* p = s)
        {
            for (int i = 0; i < s.Length; i++)
            {
                while (!unicodeCategories.Contains(char.GetUnicodeCategory(*(p + i))))
                    *(p + i) += (char)*(p + i);
            }
        }
        return s;
    }
}

你还需要这个:

public static class RandomExtensions
{
    public static string NextString(this Random rnd, int length)
    {
        if (length <= 0)
            return String.Empty;

        return rnd.NextBytes(length).ConvertToString();
    }

    public static byte[] NextBytes(this Random rnd, int length)
    {
        if (length <= 0)
            return new byte[0];

        byte[] randomBytes = new byte[length];
        rnd.NextBytes(randomBytes);
        return randomBytes;
    }
}

这:

public static class ByteArrayExtensions
{
    public static string ConvertToString(this byte[] bytes)
    {
        if (bytes.Length <= 0)
            return string.Empty;

        char[] chars = new char[bytes.Length / sizeof(char)];
        Buffer.BlockCopy(bytes, 0, chars, 0, bytes.Length);
        return new string(chars);
    }
}

我发现这更有帮助,因为它是一个扩展,它允许您选择代码的源代码。

static string
    numbers = "0123456789",
    letters = "abcdefghijklmnopqrstvwxyz",
    lettersUp = letters.ToUpper(),
    codeAll = numbers + letters + lettersUp;

static Random m_rand = new Random();

public static string GenerateCode(this int size)
{
    return size.GenerateCode(CodeGeneratorType.All);
}

public static string GenerateCode(this int size, CodeGeneratorType type)
{
    string source;

    if (type == CodeGeneratorType.All)
    {
        source = codeAll;
    }
    else
    {
        StringBuilder sourceBuilder = new StringBuilder();
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.Numbers)
            sourceBuilder.Append(numbers);
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.Letters)
            sourceBuilder.Append(letters);
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.LettersUpperCase)
            sourceBuilder.Append(lettersUp);

        source = sourceBuilder.ToString();
    }

    return size.GenerateCode(source);
}

public static string GenerateCode(this int size, string source)
{
    StringBuilder code = new StringBuilder();
    int maxIndex = source.Length-1;
    for (int i = 0; i < size; i++)
    {

        code.Append(source[Convert.ToInt32(Math.Round(m_rand.NextDouble() * maxIndex))]);
    }

    return code.ToString();
}

public enum CodeGeneratorType { Numbers = 1, Letters = 2, LettersUpperCase = 4, All = 16 };

希望这能有所帮助。

还有另一个版本:我在测试中使用这种方法生成随机的伪股票代码:

Random rand = new Random();
Func<char> randChar = () => (char)rand.Next(65, 91); // upper case ascii codes
Func<int,string> randStr = null;
    randStr = (x) => (x>0) ? randStr(--x)+randChar() : ""; // recursive

用法:

string str4 = randStr(4);// generates a random 4 char string
string strx = randStr(rand.next(1,5)); // random string between 1-4 chars in length

你可以重新定义randChar函数,使用一个“允许的”字符数组,而不是ascii码:

char[] allowedchars = {'A','B','C','1','2','3'};
Func<char> randChar = () => allowedchars[rand.Next(0, allowedchars.Length-1)];