我想在不退出的情况下捕获和记录异常,例如,

try:
    do_stuff()
except Exception as err:
    print(Exception, err)
    # I want to print the entire traceback here,
    # not just the exception name and details

我想打印与抛出异常时打印的完全相同的输出,而不使用try/,只是拦截异常,并且我不希望它退出程序。


当前回答

Traceback.format_exc()或sys.exc_info()将产生更多信息,如果这是你想要的。

import traceback
import sys

try:
    do_stuff()
except Exception:
    print(traceback.format_exc())
    # or
    print(sys.exc_info()[2])

其他回答

traceback.format_exception (exception_object)

如果你只有异常对象,你可以从Python 3中的任何代码点获得字符串形式的回溯:

import traceback

''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))

完整的例子:

#!/usr/bin/env python3

import traceback

def f():
    g()

def g():
    raise Exception('asdf')

try:
    g()
except Exception as e:
    exc_obj = e

tb_str = ''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))
print(tb_str)

输出:

Traceback (most recent call last):
  File "./main.py", line 12, in <module>
    g()
  File "./main.py", line 9, in g
    raise Exception('asdf')
Exception: asdf

文档:https://docs.python.org/3.9/library/traceback.html traceback.format_exception

请参见:从异常对象中提取回溯信息

在Python 3.9中测试

关于这个答案的注释:print(traceback.format_exc())对我来说比traceback.print_exc()更好。对于后者,hello有时会奇怪地与回溯文本“混合”在一起,比如两者都想同时写入stdout或stderr,产生奇怪的输出(至少在从文本编辑器内部构建并在“构建结果”面板中查看输出时)。

回溯(最近一次调用): 文件“C:\Users\User\Desktop\test.py”,第7行,在 地狱do_stuff () 文件“C:\Users\User\Desktop\test.py”,第4行,do_stuff 1/0 ZeroDivisionError:整数除法或对0取模 o [0.1s完成]

所以我用:

import traceback, sys

def do_stuff():
    1/0

try:
    do_stuff()
except Exception:
    print(traceback.format_exc())
    print('hello')

要获得精确的堆栈跟踪(作为字符串),如果没有try/except进行跨步处理,则会引发该字符串,只需将其放置在捕获违规异常的except块中。

desired_trace = traceback.format_exc(sys.exc_info())

下面是如何使用它(假设定义了flaky_func,并且log调用您最喜欢的日志系统):

import traceback
import sys

try:
    flaky_func()
except KeyboardInterrupt:
    raise
except Exception:
    desired_trace = traceback.format_exc(sys.exc_info())
    log(desired_trace)

捕获并重新引发KeyboardInterrupts是个好主意,这样您仍然可以使用Ctrl-C终止程序。日志记录不在这个问题的范围之内,但是日志记录是一个很好的选择。sys和traceback模块的文档。

这是我把错误写在日志文件和控制台的解决方案:

import logging, sys
import traceback
logging.basicConfig(filename='error.log', level=logging.DEBUG)

def handle_exception(exc_type, exc_value, exc_traceback):
    if issubclass(exc_type, KeyboardInterrupt):
        sys.__excepthook__(exc_type, exc_value, exc_traceback)
        return
    exc_info=(exc_type, exc_value, exc_traceback)
    logging.critical("\nDate:" + str(datetime.datetime.now()), exc_info=(exc_type, exc_value, exc_traceback))
    print("An error occured, check error.log to see the error details")
    traceback.print_exception(*exc_info)


sys.excepthook = handle_exception

Python 3解决方案

stacktrace_helper.py:

from linecache import getline
import sys
import traceback


def get_stack_trace():
    exc_type, exc_value, exc_tb = sys.exc_info()
    trace = traceback.format_stack()
    trace = list(filter(lambda x: ("\\lib\\" not in x and "/lib/" not in x and "stacktrace_helper.py" not in x), trace))
    ex_type = exc_type.__name__
    ex_line = exc_tb.tb_lineno
    ex_file = exc_tb.tb_frame.f_code.co_filename
    ex_message = str(exc_value)
    line_code = ""
    try:
        line_code = getline(ex_file, ex_line).strip()
    except:
        pass

    trace.insert(
        0, f'File "{ex_file}", line {ex_line}, line_code: {line_code} , ex: {ex_type} {ex_message}',
    )
    return trace


def get_stack_trace_str(msg: str = ""):
    trace = list(get_stack_trace())
    trace_str = "\n".join(list(map(str, trace)))
    trace_str = msg + "\n" + trace_str
    return trace_str