I think the question is getting at the fact that C# needs another keyword, for precisely this sort of situation. You want a method whose return value depends only on the type on which it is called. You can't call it "static" if said type is unknown. But once the type becomes known, it will become static. "Unresolved static" is the idea -- it's not static yet, but once we know the receiving type, it will be. This is a perfectly good concept, which is why programmers keep asking for it. But it didn't quite fit into the way the designers thought about the language.

因为它不可用，所以我采用如下所示的方式使用非静态方法。虽然不太理想，但至少对我来说，我找不到比这更有意义的方法了。

public interface IZeroWrapper<TNumber> {
  TNumber Zero {get;}
}

public class DoubleWrapper: IZeroWrapper<double> {
  public double Zero { get { return 0; } }
}

c#和CLR应该像Java一样支持接口中的静态方法。静态修饰符是契约定义的一部分，确实有意义，具体来说，行为和返回值不会基于实例而变化，尽管在不同调用之间仍然可能不同。

也就是说，当您想在接口中使用静态方法而又不能使用时，我建议您使用注释。您将得到您正在寻找的功能。

从c# 9开始，接口中的静态方法是允许的(参见https://www.dotnetcurry.com/csharp/simpler-code-with-csharp-9)。

因为接口的目的是允许多态性，能够传递任意数量的已定义类的实例，这些类都已定义，以实现已定义的接口……确保在多态调用中，代码能够找到您正在调用的方法。允许静态方法实现接口是没有意义的，

你怎么称呼它??

public interface MyInterface { void MyMethod(); }
public class MyClass: MyInterface
{
    public static void MyMethod() { //Do Something; }
}

 // inside of some other class ...  
 // How would you call the method on the interface ???
    MyClass.MyMethod();  // this calls the method normally 
                         // not through the interface...

    // This next fails you can't cast a classname to a different type... 
    // Only instances can be Cast to a different type...
    MyInterface myItf = MyClass as MyInterface;  

假设你在问为什么你不能这样做:

public interface IFoo {
    void Bar();
}

public class Foo: IFoo {
    public static void Bar() {}
}

This doesn't make sense to me, semantically. Methods specified on an interface should be there to specify the contract for interacting with an object. Static methods do not allow you to interact with an object - if you find yourself in the position where your implementation could be made static, you may need to ask yourself if that method really belongs in the interface. To implement your example, I would give Animal a const property, which would still allow it to be accessed from a static context, and return that value in the implementation.

public class Animal: IListItem {
    /* Can be tough to come up with a different, yet meaningful name!
     * A different casing convention, like Java has, would help here.
     */
    public const string AnimalScreenName = "Animal";
    public string ScreenName(){ return AnimalScreenName; }
}

对于更复杂的情况，您总是可以声明另一个静态方法并委托给它。在尝试给出一个例子的过程中，我想不出您在静态和实例上下文中都要做一些非平凡的事情的任何理由，因此我将给您一个FooBar blob，并将其作为它可能不是一个好主意的指示。

这里的大多数答案似乎都没有抓住重点。多态性不仅可以在实例之间使用，还可以在类型之间使用。当我们使用泛型时，这是经常需要的。

假设我们在泛型方法中有类型参数，我们需要对它做一些操作。我们不想实例化，因为我们不知道构造函数。

例如:

Repository GetRepository<T>()
{
  //need to call T.IsQueryable, but can't!!!
  //need to call T.RowCount
  //need to call T.DoSomeStaticMath(int param)
}

...
var r = GetRepository<Customer>()

不幸的是，我只能想出一些“丑陋”的选择:

Use reflection Ugly and beats the idea of interfaces and polymorphism. Create completely separate factory class This might greatly increase the complexity of the code. For example, if we are trying to model domain objects, each object would need another repository class. Instantiate and then call the desired interface method This can be hard to implement even if we control the source for the classes, used as generic parameters. The reason is that, for example we might need the instances to be only in well-known, "connected to DB" state.

例子:

public class Customer 
{
  //create new customer
  public Customer(Transaction t) { ... }

  //open existing customer
  public Customer(Transaction t, int id) { ... }

  void SomeOtherMethod() 
  { 
    //do work...
  }
}

为了使用实例化来解决静态接口问题，我们需要做以下事情:

public class Customer: IDoSomeStaticMath
{
  //create new customer
  public Customer(Transaction t) { ... }

  //open existing customer
  public Customer(Transaction t, int id) { ... }

  //dummy instance
  public Customer() { IsDummy = true; }

  int DoSomeStaticMath(int a) { }

  void SomeOtherMethod() 
  { 
    if(!IsDummy) 
    {
      //do work...
    }
  }
}

这显然是丑陋的，也是不必要的，会使所有其他方法的代码复杂化。显然，这也不是一个优雅的解决方案!