这段代码接受#fff和#ffffff变量和不透明度。

function hex2rgb(hex, opacity) {
        var h=hex.replace('#', '');
        h =  h.match(new RegExp('(.{'+h.length/3+'})', 'g'));

        for(var i=0; i<h.length; i++)
            h[i] = parseInt(h[i].length==1? h[i]+h[i]:h[i], 16);

        if (typeof opacity != 'undefined')  h.push(opacity);

        return 'rgba('+h.join(',')+')';
}

我发现了这个，因为我认为它非常直截了当，有验证测试和支持alpha值(可选)，这将适合这种情况。

只要注释掉regex行，如果你知道你在做什么，它会快一点。

function hexToRGBA(hex, alpha){
    hex = (""+hex).trim().replace(/#/g,""); //trim and remove any leading # if there (supports number values as well)
    if (!/^(?:[0-9a-fA-F]{3}){1,2}$/.test(hex)) throw ("not a valid hex string"); //Regex Validator
    if (hex.length==3){hex=hex[0]+hex[0]+hex[1]+hex[1]+hex[2]+hex[2]} //support short form
    var b_int = parseInt(hex, 16);
    return "rgba("+[
        (b_int >> 16) & 255, //R
        (b_int >> 8) & 255, //G
        b_int & 255, //B
        alpha || 1  //add alpha if is set
    ].join(",")+")";
}

我需要一个函数，接受无效值太像

Rgb (- 255,255,255) Rgb (510, 255, 255)

这是@cwolves answer的衍生

function rgb(r, g, b) {
  this.c = this.c || function (n) {
    return Math.max(Math.min(n, 255), 0)
  };

  return ((1 << 24) + (this.c(r) << 16) + (this.c(g) << 8) + this.c(b)).toString(16).slice(1).toUpperCase();
}

我正在使用XAML数据，具有十六进制格式的#AARRGGBB (Alpha，红色，绿色，蓝色)。利用上面的答案，以下是我的解决方案:

function hexToRgba(hex) {
    var bigint, r, g, b, a;
    //Remove # character
    var re = /^#?/;
    var aRgb = hex.replace(re, '');
    bigint = parseInt(aRgb, 16);

    //If in #FFF format
    if (aRgb.length == 3) {
        r = (bigint >> 4) & 255;
        g = (bigint >> 2) & 255;
        b = bigint & 255;
        return "rgba(" + r + "," + g + "," + b + ",1)";
    }

    //If in #RRGGBB format
    if (aRgb.length >= 6) {
        r = (bigint >> 16) & 255;
        g = (bigint >> 8) & 255;
        b = bigint & 255;
        var rgb = r + "," + g + "," + b;

        //If in #AARRBBGG format
        if (aRgb.length == 8) {
            a = ((bigint >> 24) & 255) / 255;
            return "rgba(" + rgb + "," + a.toFixed(1) + ")";
        }
    }
    return "rgba(" + rgb + ",1)";
}

http://jsfiddle.net/kvLyscs3/

我意识到这个问题有很多答案，但如果你像我一样，你知道你的HEX总是6个字符，带或不带#前缀，那么如果你想做一些快速内联的东西，这可能是最简单的方法。它不关心是否以散列开始。

var hex = "#ffffff";
var rgb = [
    parseInt(hex.substr(-6,2),16),
    parseInt(hex.substr(-4,2),16),
    parseInt(hex.substr(-2),16)
];

看起来你在寻找这样的东西:

function hexstr(number) {
    var chars = new Array("0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "a", "b", "c", "d", "e", "f");
    var low = number & 0xf;
    var high = (number >> 4) & 0xf;
    return "" + chars[high] + chars[low];
}

function rgb2hex(r, g, b) {
    return "#" + hexstr(r) + hexstr(g) + hexstr(b);
}