这样就行了

对于大文件:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            for line in infile:
                outfile.write(line)

对于小文件:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            outfile.write(infile.read())

我还想到了另一个有趣的问题:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for line in itertools.chain.from_iterable(itertools.imap(open, filnames)):
        outfile.write(line)

遗憾的是，最后一个方法留下了一些打开的文件描述符，无论如何GC都应该处理这些描述符。我只是觉得很有趣

这样就行了

对于大文件:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            for line in infile:
                outfile.write(line)

对于小文件:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for fname in filenames:
        with open(fname) as infile:
            outfile.write(infile.read())

我还想到了另一个有趣的问题:

filenames = ['file1.txt', 'file2.txt', ...]
with open('path/to/output/file', 'w') as outfile:
    for line in itertools.chain.from_iterable(itertools.imap(open, filnames)):
        outfile.write(line)

遗憾的是，最后一个方法留下了一些打开的文件描述符，无论如何GC都应该处理这些描述符。我只是觉得很有趣

我不知道什么叫优雅，但这招管用:

    import glob
    import os
    for f in glob.glob("file*.txt"):
         os.system("cat "+f+" >> OutFile.txt")

UNIX命令有什么问题?(假设你不是在Windows上工作):

Ls | xargs cat | tee output.txt完成这项工作(如果你想要，你可以从python用subprocess调用它)

使用shutil.copyfileobj。

它会自动读取输入文件的块为您，这是更有效的读取输入文件，即使一些输入文件太大，无法装入内存也能工作:

import shutil

with open('output_file.txt','wb') as wfd:
    for f in ['seg1.txt','seg2.txt','seg3.txt']:
        with open(f,'rb') as fd:
            shutil.copyfileobj(fd, wfd)

如果目录中有很多文件，那么glob2可能是生成文件名列表的更好选择，而不是手工编写它们。

import glob2

filenames = glob2.glob('*.txt')  # list of all .txt files in the directory

with open('outfile.txt', 'w') as f:
    for file in filenames:
        with open(file) as infile:
            f.write(infile.read()+'\n')